229304 For reaction, $2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons \quad 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{c}}$ at $427^{\circ} \mathrm{C}$ is $3 \times 10^{-6} \mathrm{~L} \mathrm{~mol}^{-1}$. The value of $\mathrm{K}_{\mathrm{p}}$ is nearly:
229307
In the reaction, $\mathrm{H}_{2}+\mathrm{I}_{2}-2 \mathrm{HI}$
In a $1 \mathrm{~L}$ flask, 0.4 mole of each $\mathrm{H}_{2}$ and $\mathrm{I}_{2}$ are taken. At equilibrium 0.5 mole of $\mathrm{HI}$ are formed. What will be the value of equilibrium constant, $K_{\mathbf{c}}$ ?
229304 For reaction, $2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons \quad 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{c}}$ at $427^{\circ} \mathrm{C}$ is $3 \times 10^{-6} \mathrm{~L} \mathrm{~mol}^{-1}$. The value of $\mathrm{K}_{\mathrm{p}}$ is nearly:
229307
In the reaction, $\mathrm{H}_{2}+\mathrm{I}_{2}-2 \mathrm{HI}$
In a $1 \mathrm{~L}$ flask, 0.4 mole of each $\mathrm{H}_{2}$ and $\mathrm{I}_{2}$ are taken. At equilibrium 0.5 mole of $\mathrm{HI}$ are formed. What will be the value of equilibrium constant, $K_{\mathbf{c}}$ ?
229304 For reaction, $2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons \quad 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{c}}$ at $427^{\circ} \mathrm{C}$ is $3 \times 10^{-6} \mathrm{~L} \mathrm{~mol}^{-1}$. The value of $\mathrm{K}_{\mathrm{p}}$ is nearly:
229307
In the reaction, $\mathrm{H}_{2}+\mathrm{I}_{2}-2 \mathrm{HI}$
In a $1 \mathrm{~L}$ flask, 0.4 mole of each $\mathrm{H}_{2}$ and $\mathrm{I}_{2}$ are taken. At equilibrium 0.5 mole of $\mathrm{HI}$ are formed. What will be the value of equilibrium constant, $K_{\mathbf{c}}$ ?
229304 For reaction, $2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons \quad 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{c}}$ at $427^{\circ} \mathrm{C}$ is $3 \times 10^{-6} \mathrm{~L} \mathrm{~mol}^{-1}$. The value of $\mathrm{K}_{\mathrm{p}}$ is nearly:
229307
In the reaction, $\mathrm{H}_{2}+\mathrm{I}_{2}-2 \mathrm{HI}$
In a $1 \mathrm{~L}$ flask, 0.4 mole of each $\mathrm{H}_{2}$ and $\mathrm{I}_{2}$ are taken. At equilibrium 0.5 mole of $\mathrm{HI}$ are formed. What will be the value of equilibrium constant, $K_{\mathbf{c}}$ ?
229304 For reaction, $2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons \quad 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) ; \mathrm{K}_{\mathrm{c}}$ at $427^{\circ} \mathrm{C}$ is $3 \times 10^{-6} \mathrm{~L} \mathrm{~mol}^{-1}$. The value of $\mathrm{K}_{\mathrm{p}}$ is nearly:
229307
In the reaction, $\mathrm{H}_{2}+\mathrm{I}_{2}-2 \mathrm{HI}$
In a $1 \mathrm{~L}$ flask, 0.4 mole of each $\mathrm{H}_{2}$ and $\mathrm{I}_{2}$ are taken. At equilibrium 0.5 mole of $\mathrm{HI}$ are formed. What will be the value of equilibrium constant, $K_{\mathbf{c}}$ ?