229265 The value of $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{CaCO}_{3}$ and $\mathrm{CaC}_{2} \mathrm{O}_{4}$ are $4.7 \times 10^{-9}$ and $1.3 \times 10^{-9}$ respectively at $25^{\circ} \mathrm{C}$. If the mixture of these two is washed with water, what is the concentration of $\mathrm{Ca}^{2+}$ ions in water?
229266
For the equilibrium, $\mathbf{A}(\mathrm{g}) \rightleftharpoons \mathbf{B}(\mathrm{g})+\mathbf{C}(\mathrm{g})$; $\mathbf{K}_{\mathrm{p}}=$ $0.82 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. At the same temperature, its $\mathrm{K}_{\mathrm{c}}$ in $\mathrm{mol} \mathrm{L}^{-1}$ is
$\left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right. \text { ) }$
229268
Given the reaction between 2 gases represented by $A_{2}$ and $B_{2}$ to give the compound $A B(g)$.
$\mathrm{A}_{2}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{g})$
At equilibrium the concentration of
$\mathrm{A}_{2}=3.0 \times 10^{-3} \mathrm{M}$ of $B_{2}=4.2 \times 10^{-3} \mathrm{M}$ of $\mathrm{AB}=2.8 \times 10^{-3} \mathrm{M}$
If the reaction takes place in sealed vessel at $527^{\circ} \mathrm{C}$, then the value of $K_{c}$ will be
229265 The value of $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{CaCO}_{3}$ and $\mathrm{CaC}_{2} \mathrm{O}_{4}$ are $4.7 \times 10^{-9}$ and $1.3 \times 10^{-9}$ respectively at $25^{\circ} \mathrm{C}$. If the mixture of these two is washed with water, what is the concentration of $\mathrm{Ca}^{2+}$ ions in water?
229266
For the equilibrium, $\mathbf{A}(\mathrm{g}) \rightleftharpoons \mathbf{B}(\mathrm{g})+\mathbf{C}(\mathrm{g})$; $\mathbf{K}_{\mathrm{p}}=$ $0.82 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. At the same temperature, its $\mathrm{K}_{\mathrm{c}}$ in $\mathrm{mol} \mathrm{L}^{-1}$ is
$\left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right. \text { ) }$
229268
Given the reaction between 2 gases represented by $A_{2}$ and $B_{2}$ to give the compound $A B(g)$.
$\mathrm{A}_{2}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{g})$
At equilibrium the concentration of
$\mathrm{A}_{2}=3.0 \times 10^{-3} \mathrm{M}$ of $B_{2}=4.2 \times 10^{-3} \mathrm{M}$ of $\mathrm{AB}=2.8 \times 10^{-3} \mathrm{M}$
If the reaction takes place in sealed vessel at $527^{\circ} \mathrm{C}$, then the value of $K_{c}$ will be
229265 The value of $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{CaCO}_{3}$ and $\mathrm{CaC}_{2} \mathrm{O}_{4}$ are $4.7 \times 10^{-9}$ and $1.3 \times 10^{-9}$ respectively at $25^{\circ} \mathrm{C}$. If the mixture of these two is washed with water, what is the concentration of $\mathrm{Ca}^{2+}$ ions in water?
229266
For the equilibrium, $\mathbf{A}(\mathrm{g}) \rightleftharpoons \mathbf{B}(\mathrm{g})+\mathbf{C}(\mathrm{g})$; $\mathbf{K}_{\mathrm{p}}=$ $0.82 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. At the same temperature, its $\mathrm{K}_{\mathrm{c}}$ in $\mathrm{mol} \mathrm{L}^{-1}$ is
$\left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right. \text { ) }$
229268
Given the reaction between 2 gases represented by $A_{2}$ and $B_{2}$ to give the compound $A B(g)$.
$\mathrm{A}_{2}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{g})$
At equilibrium the concentration of
$\mathrm{A}_{2}=3.0 \times 10^{-3} \mathrm{M}$ of $B_{2}=4.2 \times 10^{-3} \mathrm{M}$ of $\mathrm{AB}=2.8 \times 10^{-3} \mathrm{M}$
If the reaction takes place in sealed vessel at $527^{\circ} \mathrm{C}$, then the value of $K_{c}$ will be
229265 The value of $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{CaCO}_{3}$ and $\mathrm{CaC}_{2} \mathrm{O}_{4}$ are $4.7 \times 10^{-9}$ and $1.3 \times 10^{-9}$ respectively at $25^{\circ} \mathrm{C}$. If the mixture of these two is washed with water, what is the concentration of $\mathrm{Ca}^{2+}$ ions in water?
229266
For the equilibrium, $\mathbf{A}(\mathrm{g}) \rightleftharpoons \mathbf{B}(\mathrm{g})+\mathbf{C}(\mathrm{g})$; $\mathbf{K}_{\mathrm{p}}=$ $0.82 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. At the same temperature, its $\mathrm{K}_{\mathrm{c}}$ in $\mathrm{mol} \mathrm{L}^{-1}$ is
$\left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right. \text { ) }$
229268
Given the reaction between 2 gases represented by $A_{2}$ and $B_{2}$ to give the compound $A B(g)$.
$\mathrm{A}_{2}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{g})$
At equilibrium the concentration of
$\mathrm{A}_{2}=3.0 \times 10^{-3} \mathrm{M}$ of $B_{2}=4.2 \times 10^{-3} \mathrm{M}$ of $\mathrm{AB}=2.8 \times 10^{-3} \mathrm{M}$
If the reaction takes place in sealed vessel at $527^{\circ} \mathrm{C}$, then the value of $K_{c}$ will be
229265 The value of $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{CaCO}_{3}$ and $\mathrm{CaC}_{2} \mathrm{O}_{4}$ are $4.7 \times 10^{-9}$ and $1.3 \times 10^{-9}$ respectively at $25^{\circ} \mathrm{C}$. If the mixture of these two is washed with water, what is the concentration of $\mathrm{Ca}^{2+}$ ions in water?
229266
For the equilibrium, $\mathbf{A}(\mathrm{g}) \rightleftharpoons \mathbf{B}(\mathrm{g})+\mathbf{C}(\mathrm{g})$; $\mathbf{K}_{\mathrm{p}}=$ $0.82 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. At the same temperature, its $\mathrm{K}_{\mathrm{c}}$ in $\mathrm{mol} \mathrm{L}^{-1}$ is
$\left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right. \text { ) }$
229268
Given the reaction between 2 gases represented by $A_{2}$ and $B_{2}$ to give the compound $A B(g)$.
$\mathrm{A}_{2}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{g})$
At equilibrium the concentration of
$\mathrm{A}_{2}=3.0 \times 10^{-3} \mathrm{M}$ of $B_{2}=4.2 \times 10^{-3} \mathrm{M}$ of $\mathrm{AB}=2.8 \times 10^{-3} \mathrm{M}$
If the reaction takes place in sealed vessel at $527^{\circ} \mathrm{C}$, then the value of $K_{c}$ will be