229202
How will increase of pressure affect the equation? $\mathrm{C}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{~g})$
1 Shift in the forward direction
2 Shift in the reverse direction
3 Increase in the yield of hydrogen
4 No effect.
Explanation:
Reverse reaction, Le-Chatelier's principal when there is change in number of moles the equilibrium will shift in the direction having smaller number of moles, when the pressure is increased and vice-verssa
J and K CET-(2003)
Chemical Equilibrium
229206
For any reversible reaction, if we increase concentration of the reactions, then effect in equilibrium constant
1 depends on amount of concentration
2 unchange
3 decrease
4 increase
Explanation:
Equilibrium constant independent of change in concentration of reactants or products. It depend only on temperature.
NEET-2000
Chemical Equilibrium
229207
In an exothermic reaction. $10^{\circ} \mathrm{C}$ rise in temperature will
1 Decrease the value of equilibrium constant
2 Double the value of $\mathrm{K}_{\mathrm{c}}$
3 Do not produce any change in $\mathrm{K}_{\mathrm{c}}$
4 Produce some change in $K_{c}$
Explanation:
In exothermic reaction, increase in temperature favours the backward reaction i.e. decreases the value of equilibrium constant.
J and K CET-(2000)
Chemical Equilibrium
229209
In the chemical reaction, $\mathbf{2 S O}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}$, increasing the total pressure leads to
1 Increase in the amount of $\mathrm{SO}_{3}$
2 Increase in the partial pressure of $\mathrm{O}_{2}$
3 Increase in the partial pressure of $\mathrm{SO}_{2}$
4 Change in the equilibrium constant
Explanation:
When pressure is increased, at constant temperature the equilibrium will shift in such a way as to reduce this stress on its position. It shift towards product sides. So, the amount of $\mathrm{SO}_{3}$ increased
229202
How will increase of pressure affect the equation? $\mathrm{C}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{~g})$
1 Shift in the forward direction
2 Shift in the reverse direction
3 Increase in the yield of hydrogen
4 No effect.
Explanation:
Reverse reaction, Le-Chatelier's principal when there is change in number of moles the equilibrium will shift in the direction having smaller number of moles, when the pressure is increased and vice-verssa
J and K CET-(2003)
Chemical Equilibrium
229206
For any reversible reaction, if we increase concentration of the reactions, then effect in equilibrium constant
1 depends on amount of concentration
2 unchange
3 decrease
4 increase
Explanation:
Equilibrium constant independent of change in concentration of reactants or products. It depend only on temperature.
NEET-2000
Chemical Equilibrium
229207
In an exothermic reaction. $10^{\circ} \mathrm{C}$ rise in temperature will
1 Decrease the value of equilibrium constant
2 Double the value of $\mathrm{K}_{\mathrm{c}}$
3 Do not produce any change in $\mathrm{K}_{\mathrm{c}}$
4 Produce some change in $K_{c}$
Explanation:
In exothermic reaction, increase in temperature favours the backward reaction i.e. decreases the value of equilibrium constant.
J and K CET-(2000)
Chemical Equilibrium
229209
In the chemical reaction, $\mathbf{2 S O}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}$, increasing the total pressure leads to
1 Increase in the amount of $\mathrm{SO}_{3}$
2 Increase in the partial pressure of $\mathrm{O}_{2}$
3 Increase in the partial pressure of $\mathrm{SO}_{2}$
4 Change in the equilibrium constant
Explanation:
When pressure is increased, at constant temperature the equilibrium will shift in such a way as to reduce this stress on its position. It shift towards product sides. So, the amount of $\mathrm{SO}_{3}$ increased
229202
How will increase of pressure affect the equation? $\mathrm{C}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{~g})$
1 Shift in the forward direction
2 Shift in the reverse direction
3 Increase in the yield of hydrogen
4 No effect.
Explanation:
Reverse reaction, Le-Chatelier's principal when there is change in number of moles the equilibrium will shift in the direction having smaller number of moles, when the pressure is increased and vice-verssa
J and K CET-(2003)
Chemical Equilibrium
229206
For any reversible reaction, if we increase concentration of the reactions, then effect in equilibrium constant
1 depends on amount of concentration
2 unchange
3 decrease
4 increase
Explanation:
Equilibrium constant independent of change in concentration of reactants or products. It depend only on temperature.
NEET-2000
Chemical Equilibrium
229207
In an exothermic reaction. $10^{\circ} \mathrm{C}$ rise in temperature will
1 Decrease the value of equilibrium constant
2 Double the value of $\mathrm{K}_{\mathrm{c}}$
3 Do not produce any change in $\mathrm{K}_{\mathrm{c}}$
4 Produce some change in $K_{c}$
Explanation:
In exothermic reaction, increase in temperature favours the backward reaction i.e. decreases the value of equilibrium constant.
J and K CET-(2000)
Chemical Equilibrium
229209
In the chemical reaction, $\mathbf{2 S O}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}$, increasing the total pressure leads to
1 Increase in the amount of $\mathrm{SO}_{3}$
2 Increase in the partial pressure of $\mathrm{O}_{2}$
3 Increase in the partial pressure of $\mathrm{SO}_{2}$
4 Change in the equilibrium constant
Explanation:
When pressure is increased, at constant temperature the equilibrium will shift in such a way as to reduce this stress on its position. It shift towards product sides. So, the amount of $\mathrm{SO}_{3}$ increased
229202
How will increase of pressure affect the equation? $\mathrm{C}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{~g})$
1 Shift in the forward direction
2 Shift in the reverse direction
3 Increase in the yield of hydrogen
4 No effect.
Explanation:
Reverse reaction, Le-Chatelier's principal when there is change in number of moles the equilibrium will shift in the direction having smaller number of moles, when the pressure is increased and vice-verssa
J and K CET-(2003)
Chemical Equilibrium
229206
For any reversible reaction, if we increase concentration of the reactions, then effect in equilibrium constant
1 depends on amount of concentration
2 unchange
3 decrease
4 increase
Explanation:
Equilibrium constant independent of change in concentration of reactants or products. It depend only on temperature.
NEET-2000
Chemical Equilibrium
229207
In an exothermic reaction. $10^{\circ} \mathrm{C}$ rise in temperature will
1 Decrease the value of equilibrium constant
2 Double the value of $\mathrm{K}_{\mathrm{c}}$
3 Do not produce any change in $\mathrm{K}_{\mathrm{c}}$
4 Produce some change in $K_{c}$
Explanation:
In exothermic reaction, increase in temperature favours the backward reaction i.e. decreases the value of equilibrium constant.
J and K CET-(2000)
Chemical Equilibrium
229209
In the chemical reaction, $\mathbf{2 S O}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}$, increasing the total pressure leads to
1 Increase in the amount of $\mathrm{SO}_{3}$
2 Increase in the partial pressure of $\mathrm{O}_{2}$
3 Increase in the partial pressure of $\mathrm{SO}_{2}$
4 Change in the equilibrium constant
Explanation:
When pressure is increased, at constant temperature the equilibrium will shift in such a way as to reduce this stress on its position. It shift towards product sides. So, the amount of $\mathrm{SO}_{3}$ increased
