229159
Which statement is incorrect for a catalyst?
1 It does not affect the equilibrium constant
2 It increases the proportion of products in less time
3 It decreases the activation energy of a reaction
4 It increases the free energy change for the reaction
Explanation:
It increases the free energy change for the reaction a catalyst does not affect the energies of reactants and products of the reaction and hence, the energies are same for both catalyzed and non-catalyzed reactions.
GUJCET-2018
Chemical Equilibrium
229167
Which of the following according to LeChatelier's principle is correct?
1 Increase in temperature favours the endothermic reaction
2 Increase in temperature favours the exothermic reaction
3 Increase in pressure shifts the equilibrium in that side in which number of gaseous moles increases
4 All of the above are true
Explanation:
According to Le-chatelier's principle increase in temperature favours the endothermic reaction while a decrease in temperature favour the exothermic reaction. Increase in pressure shifts the equilibrium in that side in which the number of moles of gaseous species decreases.
BITSAT 2015
Chemical Equilibrium
229164
For the chemical equilibrium, $2 \mathrm{NO}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+14.6 \mathrm{kcal}$ increase in temperature :
1 favours the formation of $\mathrm{N}_{2} \mathrm{O}_{4}$
2 favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$
3 does not affect equilibrium
4 stop the reaction
Explanation:
The given reaction is exothermic and according to Le-chatelier's principal, high temperature shifts the equilibrium in backward direction i.e. high temperature favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$.
Manipal-2016
Chemical Equilibrium
229166
The reaction $\mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons \mathbf{2 S O}_{3}+$ Heat The equilibrium reaction proceeds in forward direction by
1 addition of $\mathrm{O}_{2}$
2 removal of $\mathrm{O}_{2}$
3 addition of inert gas
4 cannot proceed
Explanation:
According to Le- Chatelier's principle, equilibrium shift towards forward direction by addition of reactant.
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Chemical Equilibrium
229159
Which statement is incorrect for a catalyst?
1 It does not affect the equilibrium constant
2 It increases the proportion of products in less time
3 It decreases the activation energy of a reaction
4 It increases the free energy change for the reaction
Explanation:
It increases the free energy change for the reaction a catalyst does not affect the energies of reactants and products of the reaction and hence, the energies are same for both catalyzed and non-catalyzed reactions.
GUJCET-2018
Chemical Equilibrium
229167
Which of the following according to LeChatelier's principle is correct?
1 Increase in temperature favours the endothermic reaction
2 Increase in temperature favours the exothermic reaction
3 Increase in pressure shifts the equilibrium in that side in which number of gaseous moles increases
4 All of the above are true
Explanation:
According to Le-chatelier's principle increase in temperature favours the endothermic reaction while a decrease in temperature favour the exothermic reaction. Increase in pressure shifts the equilibrium in that side in which the number of moles of gaseous species decreases.
BITSAT 2015
Chemical Equilibrium
229164
For the chemical equilibrium, $2 \mathrm{NO}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+14.6 \mathrm{kcal}$ increase in temperature :
1 favours the formation of $\mathrm{N}_{2} \mathrm{O}_{4}$
2 favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$
3 does not affect equilibrium
4 stop the reaction
Explanation:
The given reaction is exothermic and according to Le-chatelier's principal, high temperature shifts the equilibrium in backward direction i.e. high temperature favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$.
Manipal-2016
Chemical Equilibrium
229166
The reaction $\mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons \mathbf{2 S O}_{3}+$ Heat The equilibrium reaction proceeds in forward direction by
1 addition of $\mathrm{O}_{2}$
2 removal of $\mathrm{O}_{2}$
3 addition of inert gas
4 cannot proceed
Explanation:
According to Le- Chatelier's principle, equilibrium shift towards forward direction by addition of reactant.
229159
Which statement is incorrect for a catalyst?
1 It does not affect the equilibrium constant
2 It increases the proportion of products in less time
3 It decreases the activation energy of a reaction
4 It increases the free energy change for the reaction
Explanation:
It increases the free energy change for the reaction a catalyst does not affect the energies of reactants and products of the reaction and hence, the energies are same for both catalyzed and non-catalyzed reactions.
GUJCET-2018
Chemical Equilibrium
229167
Which of the following according to LeChatelier's principle is correct?
1 Increase in temperature favours the endothermic reaction
2 Increase in temperature favours the exothermic reaction
3 Increase in pressure shifts the equilibrium in that side in which number of gaseous moles increases
4 All of the above are true
Explanation:
According to Le-chatelier's principle increase in temperature favours the endothermic reaction while a decrease in temperature favour the exothermic reaction. Increase in pressure shifts the equilibrium in that side in which the number of moles of gaseous species decreases.
BITSAT 2015
Chemical Equilibrium
229164
For the chemical equilibrium, $2 \mathrm{NO}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+14.6 \mathrm{kcal}$ increase in temperature :
1 favours the formation of $\mathrm{N}_{2} \mathrm{O}_{4}$
2 favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$
3 does not affect equilibrium
4 stop the reaction
Explanation:
The given reaction is exothermic and according to Le-chatelier's principal, high temperature shifts the equilibrium in backward direction i.e. high temperature favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$.
Manipal-2016
Chemical Equilibrium
229166
The reaction $\mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons \mathbf{2 S O}_{3}+$ Heat The equilibrium reaction proceeds in forward direction by
1 addition of $\mathrm{O}_{2}$
2 removal of $\mathrm{O}_{2}$
3 addition of inert gas
4 cannot proceed
Explanation:
According to Le- Chatelier's principle, equilibrium shift towards forward direction by addition of reactant.
229159
Which statement is incorrect for a catalyst?
1 It does not affect the equilibrium constant
2 It increases the proportion of products in less time
3 It decreases the activation energy of a reaction
4 It increases the free energy change for the reaction
Explanation:
It increases the free energy change for the reaction a catalyst does not affect the energies of reactants and products of the reaction and hence, the energies are same for both catalyzed and non-catalyzed reactions.
GUJCET-2018
Chemical Equilibrium
229167
Which of the following according to LeChatelier's principle is correct?
1 Increase in temperature favours the endothermic reaction
2 Increase in temperature favours the exothermic reaction
3 Increase in pressure shifts the equilibrium in that side in which number of gaseous moles increases
4 All of the above are true
Explanation:
According to Le-chatelier's principle increase in temperature favours the endothermic reaction while a decrease in temperature favour the exothermic reaction. Increase in pressure shifts the equilibrium in that side in which the number of moles of gaseous species decreases.
BITSAT 2015
Chemical Equilibrium
229164
For the chemical equilibrium, $2 \mathrm{NO}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+14.6 \mathrm{kcal}$ increase in temperature :
1 favours the formation of $\mathrm{N}_{2} \mathrm{O}_{4}$
2 favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$
3 does not affect equilibrium
4 stop the reaction
Explanation:
The given reaction is exothermic and according to Le-chatelier's principal, high temperature shifts the equilibrium in backward direction i.e. high temperature favours the decomposition of $\mathrm{N}_{2} \mathrm{O}_{4}$.
Manipal-2016
Chemical Equilibrium
229166
The reaction $\mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons \mathbf{2 S O}_{3}+$ Heat The equilibrium reaction proceeds in forward direction by
1 addition of $\mathrm{O}_{2}$
2 removal of $\mathrm{O}_{2}$
3 addition of inert gas
4 cannot proceed
Explanation:
According to Le- Chatelier's principle, equilibrium shift towards forward direction by addition of reactant.