272487 The combination of plots which does not represent isothermal expansion of an ideal gas is

272488 $\Delta \mathrm{U}$ is equal to

272489 5 moles of an ideal gas at $100 \mathrm{~K}$ are allowed to undergo reversible compression till its temperature becomes $200 \mathrm{~K}$. If $\mathrm{C}_{\mathrm{T}}=28 \mathrm{JK}^{-1}$ $\mathrm{mol}^{-1}$, calculate $\Delta \mathrm{U}$ and $\Delta \mathrm{PV}$ for this process. $\left(\mathbf{R}=8.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$

272492 At $300 \mathrm{~K}$ and $1 \mathrm{~atm}, 15 \mathrm{~mL}$ of a gaseous hydrocarbon requires $375 \mathrm{~mL}$ air containing $20 \% \mathrm{O}_2$ by volume for complete combustion. After combustion, the gases occupy $330 \mathrm{~mL}$. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is

272487 The combination of plots which does not represent isothermal expansion of an ideal gas is

272488 $\Delta \mathrm{U}$ is equal to

272489 5 moles of an ideal gas at $100 \mathrm{~K}$ are allowed to undergo reversible compression till its temperature becomes $200 \mathrm{~K}$. If $\mathrm{C}_{\mathrm{T}}=28 \mathrm{JK}^{-1}$ $\mathrm{mol}^{-1}$, calculate $\Delta \mathrm{U}$ and $\Delta \mathrm{PV}$ for this process. $\left(\mathbf{R}=8.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$

272492 At $300 \mathrm{~K}$ and $1 \mathrm{~atm}, 15 \mathrm{~mL}$ of a gaseous hydrocarbon requires $375 \mathrm{~mL}$ air containing $20 \% \mathrm{O}_2$ by volume for complete combustion. After combustion, the gases occupy $330 \mathrm{~mL}$. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is

272487 The combination of plots which does not represent isothermal expansion of an ideal gas is

272488 $\Delta \mathrm{U}$ is equal to

272489 5 moles of an ideal gas at $100 \mathrm{~K}$ are allowed to undergo reversible compression till its temperature becomes $200 \mathrm{~K}$. If $\mathrm{C}_{\mathrm{T}}=28 \mathrm{JK}^{-1}$ $\mathrm{mol}^{-1}$, calculate $\Delta \mathrm{U}$ and $\Delta \mathrm{PV}$ for this process. $\left(\mathbf{R}=8.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$

272492 At $300 \mathrm{~K}$ and $1 \mathrm{~atm}, 15 \mathrm{~mL}$ of a gaseous hydrocarbon requires $375 \mathrm{~mL}$ air containing $20 \% \mathrm{O}_2$ by volume for complete combustion. After combustion, the gases occupy $330 \mathrm{~mL}$. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is

272487 The combination of plots which does not represent isothermal expansion of an ideal gas is

272488 $\Delta \mathrm{U}$ is equal to

272489 5 moles of an ideal gas at $100 \mathrm{~K}$ are allowed to undergo reversible compression till its temperature becomes $200 \mathrm{~K}$. If $\mathrm{C}_{\mathrm{T}}=28 \mathrm{JK}^{-1}$ $\mathrm{mol}^{-1}$, calculate $\Delta \mathrm{U}$ and $\Delta \mathrm{PV}$ for this process. $\left(\mathbf{R}=8.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$

272492 At $300 \mathrm{~K}$ and $1 \mathrm{~atm}, 15 \mathrm{~mL}$ of a gaseous hydrocarbon requires $375 \mathrm{~mL}$ air containing $20 \% \mathrm{O}_2$ by volume for complete combustion. After combustion, the gases occupy $330 \mathrm{~mL}$. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is