Classification of Elements and Periodicity in Properties
89730
Which of the following is a favourable factor for cation formation?
1 Low ionisation potential
2 High electron affinity
3 High electronegativity
4 Small atomic size
Explanation:
As the ionization potential decreases the removal of electron get place easily and the cation formed. Hence, low ionization potential is a favourable factor for cation formation.
AP-EAMCET (Engg.)-2005
Classification of Elements and Periodicity in Properties
89732
The electron affinity values (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) of three halogens $X, Y$ and $Z$ are respectively 349, -333 and -325 . Then $X, Y$ and $Z$ respectively are:
1 $\mathrm{F}_2, \mathrm{Cl}_2$ and $\mathrm{Br}_2$
2 $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$
3 $\mathrm{Cl}_2, \mathrm{Br}_2$ and $\mathrm{F}_2$
4 $\mathrm{Br}_2, \mathrm{Cl}_2$ and $\mathrm{F}_2$
Explanation:
As we know, group 17 elements shows the highest negative value of electron affinity. Chlorine has highest value of electron affinity than fluorine due to small size of fluorine and more electrostatic repulsion occur between nucleus and $\mathrm{F}$ outer shell. Thus, the electron affinity values (in $\mathrm{kJmol}^{-1}$ ) of three halogens $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$ are respectively $-349,-333$ and -325 .
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89733
Which one of the following reagents is used for detection of unsaturation in alkenes?
Both bromine water or alkaline $\mathrm{KMnO}_4$ (Baeyer's reagent) are decolourised after the reaction with unsaturated compound. Unsaturation in alkyne or alkene in any organic compound is defected by reagents the organic compound with alkaline $\mathrm{KMnO}_4$ or bromine water.
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89734
Which of the following is as per the definition of electron-affinity?
The electron affinity is the potential energy change of the atom when an electron is added to a neutral gaseous atom to form a negative ion. So, $\mathrm{X}(\mathrm{g}) \stackrel{\text { +e }}{\longrightarrow} \mathrm{X}^{-}(\mathrm{g})$ is more favorable.
Classification of Elements and Periodicity in Properties
89730
Which of the following is a favourable factor for cation formation?
1 Low ionisation potential
2 High electron affinity
3 High electronegativity
4 Small atomic size
Explanation:
As the ionization potential decreases the removal of electron get place easily and the cation formed. Hence, low ionization potential is a favourable factor for cation formation.
AP-EAMCET (Engg.)-2005
Classification of Elements and Periodicity in Properties
89732
The electron affinity values (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) of three halogens $X, Y$ and $Z$ are respectively 349, -333 and -325 . Then $X, Y$ and $Z$ respectively are:
1 $\mathrm{F}_2, \mathrm{Cl}_2$ and $\mathrm{Br}_2$
2 $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$
3 $\mathrm{Cl}_2, \mathrm{Br}_2$ and $\mathrm{F}_2$
4 $\mathrm{Br}_2, \mathrm{Cl}_2$ and $\mathrm{F}_2$
Explanation:
As we know, group 17 elements shows the highest negative value of electron affinity. Chlorine has highest value of electron affinity than fluorine due to small size of fluorine and more electrostatic repulsion occur between nucleus and $\mathrm{F}$ outer shell. Thus, the electron affinity values (in $\mathrm{kJmol}^{-1}$ ) of three halogens $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$ are respectively $-349,-333$ and -325 .
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89733
Which one of the following reagents is used for detection of unsaturation in alkenes?
Both bromine water or alkaline $\mathrm{KMnO}_4$ (Baeyer's reagent) are decolourised after the reaction with unsaturated compound. Unsaturation in alkyne or alkene in any organic compound is defected by reagents the organic compound with alkaline $\mathrm{KMnO}_4$ or bromine water.
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89734
Which of the following is as per the definition of electron-affinity?
The electron affinity is the potential energy change of the atom when an electron is added to a neutral gaseous atom to form a negative ion. So, $\mathrm{X}(\mathrm{g}) \stackrel{\text { +e }}{\longrightarrow} \mathrm{X}^{-}(\mathrm{g})$ is more favorable.
Classification of Elements and Periodicity in Properties
89730
Which of the following is a favourable factor for cation formation?
1 Low ionisation potential
2 High electron affinity
3 High electronegativity
4 Small atomic size
Explanation:
As the ionization potential decreases the removal of electron get place easily and the cation formed. Hence, low ionization potential is a favourable factor for cation formation.
AP-EAMCET (Engg.)-2005
Classification of Elements and Periodicity in Properties
89732
The electron affinity values (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) of three halogens $X, Y$ and $Z$ are respectively 349, -333 and -325 . Then $X, Y$ and $Z$ respectively are:
1 $\mathrm{F}_2, \mathrm{Cl}_2$ and $\mathrm{Br}_2$
2 $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$
3 $\mathrm{Cl}_2, \mathrm{Br}_2$ and $\mathrm{F}_2$
4 $\mathrm{Br}_2, \mathrm{Cl}_2$ and $\mathrm{F}_2$
Explanation:
As we know, group 17 elements shows the highest negative value of electron affinity. Chlorine has highest value of electron affinity than fluorine due to small size of fluorine and more electrostatic repulsion occur between nucleus and $\mathrm{F}$ outer shell. Thus, the electron affinity values (in $\mathrm{kJmol}^{-1}$ ) of three halogens $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$ are respectively $-349,-333$ and -325 .
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89733
Which one of the following reagents is used for detection of unsaturation in alkenes?
Both bromine water or alkaline $\mathrm{KMnO}_4$ (Baeyer's reagent) are decolourised after the reaction with unsaturated compound. Unsaturation in alkyne or alkene in any organic compound is defected by reagents the organic compound with alkaline $\mathrm{KMnO}_4$ or bromine water.
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89734
Which of the following is as per the definition of electron-affinity?
The electron affinity is the potential energy change of the atom when an electron is added to a neutral gaseous atom to form a negative ion. So, $\mathrm{X}(\mathrm{g}) \stackrel{\text { +e }}{\longrightarrow} \mathrm{X}^{-}(\mathrm{g})$ is more favorable.
Classification of Elements and Periodicity in Properties
89730
Which of the following is a favourable factor for cation formation?
1 Low ionisation potential
2 High electron affinity
3 High electronegativity
4 Small atomic size
Explanation:
As the ionization potential decreases the removal of electron get place easily and the cation formed. Hence, low ionization potential is a favourable factor for cation formation.
AP-EAMCET (Engg.)-2005
Classification of Elements and Periodicity in Properties
89732
The electron affinity values (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) of three halogens $X, Y$ and $Z$ are respectively 349, -333 and -325 . Then $X, Y$ and $Z$ respectively are:
1 $\mathrm{F}_2, \mathrm{Cl}_2$ and $\mathrm{Br}_2$
2 $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$
3 $\mathrm{Cl}_2, \mathrm{Br}_2$ and $\mathrm{F}_2$
4 $\mathrm{Br}_2, \mathrm{Cl}_2$ and $\mathrm{F}_2$
Explanation:
As we know, group 17 elements shows the highest negative value of electron affinity. Chlorine has highest value of electron affinity than fluorine due to small size of fluorine and more electrostatic repulsion occur between nucleus and $\mathrm{F}$ outer shell. Thus, the electron affinity values (in $\mathrm{kJmol}^{-1}$ ) of three halogens $\mathrm{Cl}_2, \mathrm{~F}_2$ and $\mathrm{Br}_2$ are respectively $-349,-333$ and -325 .
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89733
Which one of the following reagents is used for detection of unsaturation in alkenes?
Both bromine water or alkaline $\mathrm{KMnO}_4$ (Baeyer's reagent) are decolourised after the reaction with unsaturated compound. Unsaturation in alkyne or alkene in any organic compound is defected by reagents the organic compound with alkaline $\mathrm{KMnO}_4$ or bromine water.
AP-EAMCET (Medical)
Classification of Elements and Periodicity in Properties
89734
Which of the following is as per the definition of electron-affinity?
The electron affinity is the potential energy change of the atom when an electron is added to a neutral gaseous atom to form a negative ion. So, $\mathrm{X}(\mathrm{g}) \stackrel{\text { +e }}{\longrightarrow} \mathrm{X}^{-}(\mathrm{g})$ is more favorable.
