Classification of Elements and Periodicity in Properties
89711
Which of the given atoms has the greatest electron affinity?
1 $F$
2 $\mathrm{Cl}$
3 $P$
4 $\mathrm{Al}$
Explanation:
The electron affinity is a measure of the attraction between the incoming electron to the nucleus. Generally electron affinity decreases down a group, but electron affinity of $\mathrm{Cl}$ is greater than electron affinity of F due to small size of $F$ atom which can not easily accomodate the electron rather than the chlorine. Hence, $\mathrm{Cl}$ has highest electron affinity.
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89715
Why is $F_2$ the strongest oxidizing agent (among halogens) although electron affinity of $\mathrm{Cl}_2$ is higher than $\mathrm{F}_2$ ?
1 Low enthalpy of dissociation and high free energy of hydration
2 Low enthalpy of dissociation
3 High free energy of hydration
4 High electronegativity and low free energy of hydration
Explanation:
$F_2$ is the strongest oxidizing agent among the halogen due to greater heat of hydration of $\mathrm{F}^{-}$than $\mathrm{Cl}^{-}$ which compensates for the lower electron affinity of $\mathrm{F}$ than of $\mathrm{Cl} . \mathrm{F}_2$ has low enthalpy of dissociation as $\mathrm{F}-\mathrm{F}$ bond is weak and high enthalpy of hydration of small $\mathrm{F}^{-}$ion.
J and K CET-(2017)
Classification of Elements and Periodicity in Properties
89718
Electron gain enthalpy with negative sign of fluorine is less than that of chlorine due to
1 high ionisation enthalpy of fluorine
2 smaller size of chlorine atom
3 smaller size of fluorine atom
4 bigger size of $2 \mathrm{p}$ orbital of fluorine
Explanation:
Due to smaller size and high repulsive force within the outermost orbit of fluorine. Its electron gain enthalpy is less negative.
JCECE - 2015
Classification of Elements and Periodicity in Properties
89719
Copper is extracted from copper pyrites by heating in a Bessemer converter. The method is based on the principle that
1 copper has more affinity for oxygen than sulphur at high temperature
2 iron has less affinity for oxygen than sulphur at high temperature
3 copper has less affinity for oxygen than sulphur at high temperature
4 sulphur has less affinity for oxygen at high temperature
Explanation:
Copper is extracted from the copper pyrites by heating in a Bessemer Convertor. The method is based on the principle of copper has more affinity for oxygen than sulphur at high temperature.
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Classification of Elements and Periodicity in Properties
89711
Which of the given atoms has the greatest electron affinity?
1 $F$
2 $\mathrm{Cl}$
3 $P$
4 $\mathrm{Al}$
Explanation:
The electron affinity is a measure of the attraction between the incoming electron to the nucleus. Generally electron affinity decreases down a group, but electron affinity of $\mathrm{Cl}$ is greater than electron affinity of F due to small size of $F$ atom which can not easily accomodate the electron rather than the chlorine. Hence, $\mathrm{Cl}$ has highest electron affinity.
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89715
Why is $F_2$ the strongest oxidizing agent (among halogens) although electron affinity of $\mathrm{Cl}_2$ is higher than $\mathrm{F}_2$ ?
1 Low enthalpy of dissociation and high free energy of hydration
2 Low enthalpy of dissociation
3 High free energy of hydration
4 High electronegativity and low free energy of hydration
Explanation:
$F_2$ is the strongest oxidizing agent among the halogen due to greater heat of hydration of $\mathrm{F}^{-}$than $\mathrm{Cl}^{-}$ which compensates for the lower electron affinity of $\mathrm{F}$ than of $\mathrm{Cl} . \mathrm{F}_2$ has low enthalpy of dissociation as $\mathrm{F}-\mathrm{F}$ bond is weak and high enthalpy of hydration of small $\mathrm{F}^{-}$ion.
J and K CET-(2017)
Classification of Elements and Periodicity in Properties
89718
Electron gain enthalpy with negative sign of fluorine is less than that of chlorine due to
1 high ionisation enthalpy of fluorine
2 smaller size of chlorine atom
3 smaller size of fluorine atom
4 bigger size of $2 \mathrm{p}$ orbital of fluorine
Explanation:
Due to smaller size and high repulsive force within the outermost orbit of fluorine. Its electron gain enthalpy is less negative.
JCECE - 2015
Classification of Elements and Periodicity in Properties
89719
Copper is extracted from copper pyrites by heating in a Bessemer converter. The method is based on the principle that
1 copper has more affinity for oxygen than sulphur at high temperature
2 iron has less affinity for oxygen than sulphur at high temperature
3 copper has less affinity for oxygen than sulphur at high temperature
4 sulphur has less affinity for oxygen at high temperature
Explanation:
Copper is extracted from the copper pyrites by heating in a Bessemer Convertor. The method is based on the principle of copper has more affinity for oxygen than sulphur at high temperature.
Classification of Elements and Periodicity in Properties
89711
Which of the given atoms has the greatest electron affinity?
1 $F$
2 $\mathrm{Cl}$
3 $P$
4 $\mathrm{Al}$
Explanation:
The electron affinity is a measure of the attraction between the incoming electron to the nucleus. Generally electron affinity decreases down a group, but electron affinity of $\mathrm{Cl}$ is greater than electron affinity of F due to small size of $F$ atom which can not easily accomodate the electron rather than the chlorine. Hence, $\mathrm{Cl}$ has highest electron affinity.
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89715
Why is $F_2$ the strongest oxidizing agent (among halogens) although electron affinity of $\mathrm{Cl}_2$ is higher than $\mathrm{F}_2$ ?
1 Low enthalpy of dissociation and high free energy of hydration
2 Low enthalpy of dissociation
3 High free energy of hydration
4 High electronegativity and low free energy of hydration
Explanation:
$F_2$ is the strongest oxidizing agent among the halogen due to greater heat of hydration of $\mathrm{F}^{-}$than $\mathrm{Cl}^{-}$ which compensates for the lower electron affinity of $\mathrm{F}$ than of $\mathrm{Cl} . \mathrm{F}_2$ has low enthalpy of dissociation as $\mathrm{F}-\mathrm{F}$ bond is weak and high enthalpy of hydration of small $\mathrm{F}^{-}$ion.
J and K CET-(2017)
Classification of Elements and Periodicity in Properties
89718
Electron gain enthalpy with negative sign of fluorine is less than that of chlorine due to
1 high ionisation enthalpy of fluorine
2 smaller size of chlorine atom
3 smaller size of fluorine atom
4 bigger size of $2 \mathrm{p}$ orbital of fluorine
Explanation:
Due to smaller size and high repulsive force within the outermost orbit of fluorine. Its electron gain enthalpy is less negative.
JCECE - 2015
Classification of Elements and Periodicity in Properties
89719
Copper is extracted from copper pyrites by heating in a Bessemer converter. The method is based on the principle that
1 copper has more affinity for oxygen than sulphur at high temperature
2 iron has less affinity for oxygen than sulphur at high temperature
3 copper has less affinity for oxygen than sulphur at high temperature
4 sulphur has less affinity for oxygen at high temperature
Explanation:
Copper is extracted from the copper pyrites by heating in a Bessemer Convertor. The method is based on the principle of copper has more affinity for oxygen than sulphur at high temperature.
Classification of Elements and Periodicity in Properties
89711
Which of the given atoms has the greatest electron affinity?
1 $F$
2 $\mathrm{Cl}$
3 $P$
4 $\mathrm{Al}$
Explanation:
The electron affinity is a measure of the attraction between the incoming electron to the nucleus. Generally electron affinity decreases down a group, but electron affinity of $\mathrm{Cl}$ is greater than electron affinity of F due to small size of $F$ atom which can not easily accomodate the electron rather than the chlorine. Hence, $\mathrm{Cl}$ has highest electron affinity.
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89715
Why is $F_2$ the strongest oxidizing agent (among halogens) although electron affinity of $\mathrm{Cl}_2$ is higher than $\mathrm{F}_2$ ?
1 Low enthalpy of dissociation and high free energy of hydration
2 Low enthalpy of dissociation
3 High free energy of hydration
4 High electronegativity and low free energy of hydration
Explanation:
$F_2$ is the strongest oxidizing agent among the halogen due to greater heat of hydration of $\mathrm{F}^{-}$than $\mathrm{Cl}^{-}$ which compensates for the lower electron affinity of $\mathrm{F}$ than of $\mathrm{Cl} . \mathrm{F}_2$ has low enthalpy of dissociation as $\mathrm{F}-\mathrm{F}$ bond is weak and high enthalpy of hydration of small $\mathrm{F}^{-}$ion.
J and K CET-(2017)
Classification of Elements and Periodicity in Properties
89718
Electron gain enthalpy with negative sign of fluorine is less than that of chlorine due to
1 high ionisation enthalpy of fluorine
2 smaller size of chlorine atom
3 smaller size of fluorine atom
4 bigger size of $2 \mathrm{p}$ orbital of fluorine
Explanation:
Due to smaller size and high repulsive force within the outermost orbit of fluorine. Its electron gain enthalpy is less negative.
JCECE - 2015
Classification of Elements and Periodicity in Properties
89719
Copper is extracted from copper pyrites by heating in a Bessemer converter. The method is based on the principle that
1 copper has more affinity for oxygen than sulphur at high temperature
2 iron has less affinity for oxygen than sulphur at high temperature
3 copper has less affinity for oxygen than sulphur at high temperature
4 sulphur has less affinity for oxygen at high temperature
Explanation:
Copper is extracted from the copper pyrites by heating in a Bessemer Convertor. The method is based on the principle of copper has more affinity for oxygen than sulphur at high temperature.
