89524
$\mathrm{HClO}_4$ is a stronger acid than $\mathrm{H}_2 \mathrm{SO}_4$ due to which of the following reasons?
(i) Oxidation state of $\mathrm{Cl}$ in $\mathrm{HClO}_4$ is +7 and that of $\mathrm{S}$ in $\mathrm{H}_2 \mathrm{SO}_4$ is +6
(ii) $\mathrm{Cl}$ is more electronegative then $\mathrm{S}$
(iii) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ is dibasic
(iv) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ part in $\mathrm{H}_2 \mathrm{SO}_4$
89524
$\mathrm{HClO}_4$ is a stronger acid than $\mathrm{H}_2 \mathrm{SO}_4$ due to which of the following reasons?
(i) Oxidation state of $\mathrm{Cl}$ in $\mathrm{HClO}_4$ is +7 and that of $\mathrm{S}$ in $\mathrm{H}_2 \mathrm{SO}_4$ is +6
(ii) $\mathrm{Cl}$ is more electronegative then $\mathrm{S}$
(iii) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ is dibasic
(iv) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ part in $\mathrm{H}_2 \mathrm{SO}_4$
89524
$\mathrm{HClO}_4$ is a stronger acid than $\mathrm{H}_2 \mathrm{SO}_4$ due to which of the following reasons?
(i) Oxidation state of $\mathrm{Cl}$ in $\mathrm{HClO}_4$ is +7 and that of $\mathrm{S}$ in $\mathrm{H}_2 \mathrm{SO}_4$ is +6
(ii) $\mathrm{Cl}$ is more electronegative then $\mathrm{S}$
(iii) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ is dibasic
(iv) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ part in $\mathrm{H}_2 \mathrm{SO}_4$
89524
$\mathrm{HClO}_4$ is a stronger acid than $\mathrm{H}_2 \mathrm{SO}_4$ due to which of the following reasons?
(i) Oxidation state of $\mathrm{Cl}$ in $\mathrm{HClO}_4$ is +7 and that of $\mathrm{S}$ in $\mathrm{H}_2 \mathrm{SO}_4$ is +6
(ii) $\mathrm{Cl}$ is more electronegative then $\mathrm{S}$
(iii) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ is dibasic
(iv) $\mathrm{ClO}_3$ part of $\mathrm{HClO}_4$ can break $\mathrm{O}$-H bond more easily to liberate a proton than $\mathrm{SO}_3$ part in $\mathrm{H}_2 \mathrm{SO}_4$