For the isolectronic species ionic radii increases on adding the electron in shell are increase but the on removing the electron the ionic radii decreases. Hence, the decreasing order of ionic radii are- $$ \mathrm{P}^{3-}>\mathrm{S}^{2-}>\mathrm{Cl}^{-}>\mathrm{K}^{+}>\mathrm{Ca}^{2+} $$
(JEE Main 2021
Classification of Elements and Periodicity in Properties
89455
Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is
1 $117,143,64,74$
2 $143,117,74,64$
3 $143,47,64,74$
4 $64,74,117,143$
Explanation:
Nitrogen and Fluorine belong to second period. $\mathrm{Al}$ and $\mathrm{Si}$ are belong to $3^{\text {rd }}$ period. The size of element decreases from left to right in a period. Hence the decreasing order of atomic radius is - $$ \underset{143}{\mathrm{Al}}>\underset{117}{\mathrm{Si}}>\underset{74}{\mathrm{~N}}>\underset{64}{\mathrm{~F}} $$
TS EAMCET-2017
Classification of Elements and Periodicity in Properties
89446
The correct order of the atomic radii of $\mathrm{C}$, $\mathrm{Cs}$, $A l$ and $S$ is
1 $\mathrm{C}<\mathrm{S}<\mathrm{Al}<\mathrm{Cs}$
2 $\mathrm{C}<\mathrm{S}<\mathrm{Cs}<\mathrm{Al}$
3 $\mathrm{S}<\mathrm{C}<\mathrm{Cs}<\mathrm{Al}$
4 $\mathrm{S}<\mathrm{C}<\mathrm{Al}<\mathrm{Cs}$
Explanation:
On moving from left to right in a period atomic radii decreases and the moving from top to bottom in a group atomic radii increases. $\therefore$ The order of increasing atomic radii are$\underset{170}{\mathrm{C}}<\underset{180}{\mathrm{~S}}<\underset{184}{\mathrm{Al}}<\underset{300}{\mathrm{Cs}}$ Atomic radii $(\mathrm{pm})$
(JEE Main 2019
Classification of Elements and Periodicity in Properties
89447
For which of the following ionic species radius would be maximum?
1 $\mathrm{C}^{4-}$
2 $\mathrm{N}^{3-}$
3 $\mathrm{O}^{2-}$
4 $\mathrm{Mg}^{2+}$
Explanation:
Among the isoelectronic species ionic radius increase with increase in negative charge or decrease in positive charge. Therefore, the order of ionic radius maximum in $\mathrm{C}^{4-}$ and increasing order of ionic radius are- $\mathrm{Mg}^{2+}<\mathrm{O}^{2-}<\mathrm{N}^{3-}<\mathrm{C}^{4-}$
For the isolectronic species ionic radii increases on adding the electron in shell are increase but the on removing the electron the ionic radii decreases. Hence, the decreasing order of ionic radii are- $$ \mathrm{P}^{3-}>\mathrm{S}^{2-}>\mathrm{Cl}^{-}>\mathrm{K}^{+}>\mathrm{Ca}^{2+} $$
(JEE Main 2021
Classification of Elements and Periodicity in Properties
89455
Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is
1 $117,143,64,74$
2 $143,117,74,64$
3 $143,47,64,74$
4 $64,74,117,143$
Explanation:
Nitrogen and Fluorine belong to second period. $\mathrm{Al}$ and $\mathrm{Si}$ are belong to $3^{\text {rd }}$ period. The size of element decreases from left to right in a period. Hence the decreasing order of atomic radius is - $$ \underset{143}{\mathrm{Al}}>\underset{117}{\mathrm{Si}}>\underset{74}{\mathrm{~N}}>\underset{64}{\mathrm{~F}} $$
TS EAMCET-2017
Classification of Elements and Periodicity in Properties
89446
The correct order of the atomic radii of $\mathrm{C}$, $\mathrm{Cs}$, $A l$ and $S$ is
1 $\mathrm{C}<\mathrm{S}<\mathrm{Al}<\mathrm{Cs}$
2 $\mathrm{C}<\mathrm{S}<\mathrm{Cs}<\mathrm{Al}$
3 $\mathrm{S}<\mathrm{C}<\mathrm{Cs}<\mathrm{Al}$
4 $\mathrm{S}<\mathrm{C}<\mathrm{Al}<\mathrm{Cs}$
Explanation:
On moving from left to right in a period atomic radii decreases and the moving from top to bottom in a group atomic radii increases. $\therefore$ The order of increasing atomic radii are$\underset{170}{\mathrm{C}}<\underset{180}{\mathrm{~S}}<\underset{184}{\mathrm{Al}}<\underset{300}{\mathrm{Cs}}$ Atomic radii $(\mathrm{pm})$
(JEE Main 2019
Classification of Elements and Periodicity in Properties
89447
For which of the following ionic species radius would be maximum?
1 $\mathrm{C}^{4-}$
2 $\mathrm{N}^{3-}$
3 $\mathrm{O}^{2-}$
4 $\mathrm{Mg}^{2+}$
Explanation:
Among the isoelectronic species ionic radius increase with increase in negative charge or decrease in positive charge. Therefore, the order of ionic radius maximum in $\mathrm{C}^{4-}$ and increasing order of ionic radius are- $\mathrm{Mg}^{2+}<\mathrm{O}^{2-}<\mathrm{N}^{3-}<\mathrm{C}^{4-}$
For the isolectronic species ionic radii increases on adding the electron in shell are increase but the on removing the electron the ionic radii decreases. Hence, the decreasing order of ionic radii are- $$ \mathrm{P}^{3-}>\mathrm{S}^{2-}>\mathrm{Cl}^{-}>\mathrm{K}^{+}>\mathrm{Ca}^{2+} $$
(JEE Main 2021
Classification of Elements and Periodicity in Properties
89455
Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is
1 $117,143,64,74$
2 $143,117,74,64$
3 $143,47,64,74$
4 $64,74,117,143$
Explanation:
Nitrogen and Fluorine belong to second period. $\mathrm{Al}$ and $\mathrm{Si}$ are belong to $3^{\text {rd }}$ period. The size of element decreases from left to right in a period. Hence the decreasing order of atomic radius is - $$ \underset{143}{\mathrm{Al}}>\underset{117}{\mathrm{Si}}>\underset{74}{\mathrm{~N}}>\underset{64}{\mathrm{~F}} $$
TS EAMCET-2017
Classification of Elements and Periodicity in Properties
89446
The correct order of the atomic radii of $\mathrm{C}$, $\mathrm{Cs}$, $A l$ and $S$ is
1 $\mathrm{C}<\mathrm{S}<\mathrm{Al}<\mathrm{Cs}$
2 $\mathrm{C}<\mathrm{S}<\mathrm{Cs}<\mathrm{Al}$
3 $\mathrm{S}<\mathrm{C}<\mathrm{Cs}<\mathrm{Al}$
4 $\mathrm{S}<\mathrm{C}<\mathrm{Al}<\mathrm{Cs}$
Explanation:
On moving from left to right in a period atomic radii decreases and the moving from top to bottom in a group atomic radii increases. $\therefore$ The order of increasing atomic radii are$\underset{170}{\mathrm{C}}<\underset{180}{\mathrm{~S}}<\underset{184}{\mathrm{Al}}<\underset{300}{\mathrm{Cs}}$ Atomic radii $(\mathrm{pm})$
(JEE Main 2019
Classification of Elements and Periodicity in Properties
89447
For which of the following ionic species radius would be maximum?
1 $\mathrm{C}^{4-}$
2 $\mathrm{N}^{3-}$
3 $\mathrm{O}^{2-}$
4 $\mathrm{Mg}^{2+}$
Explanation:
Among the isoelectronic species ionic radius increase with increase in negative charge or decrease in positive charge. Therefore, the order of ionic radius maximum in $\mathrm{C}^{4-}$ and increasing order of ionic radius are- $\mathrm{Mg}^{2+}<\mathrm{O}^{2-}<\mathrm{N}^{3-}<\mathrm{C}^{4-}$
For the isolectronic species ionic radii increases on adding the electron in shell are increase but the on removing the electron the ionic radii decreases. Hence, the decreasing order of ionic radii are- $$ \mathrm{P}^{3-}>\mathrm{S}^{2-}>\mathrm{Cl}^{-}>\mathrm{K}^{+}>\mathrm{Ca}^{2+} $$
(JEE Main 2021
Classification of Elements and Periodicity in Properties
89455
Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is
1 $117,143,64,74$
2 $143,117,74,64$
3 $143,47,64,74$
4 $64,74,117,143$
Explanation:
Nitrogen and Fluorine belong to second period. $\mathrm{Al}$ and $\mathrm{Si}$ are belong to $3^{\text {rd }}$ period. The size of element decreases from left to right in a period. Hence the decreasing order of atomic radius is - $$ \underset{143}{\mathrm{Al}}>\underset{117}{\mathrm{Si}}>\underset{74}{\mathrm{~N}}>\underset{64}{\mathrm{~F}} $$
TS EAMCET-2017
Classification of Elements and Periodicity in Properties
89446
The correct order of the atomic radii of $\mathrm{C}$, $\mathrm{Cs}$, $A l$ and $S$ is
1 $\mathrm{C}<\mathrm{S}<\mathrm{Al}<\mathrm{Cs}$
2 $\mathrm{C}<\mathrm{S}<\mathrm{Cs}<\mathrm{Al}$
3 $\mathrm{S}<\mathrm{C}<\mathrm{Cs}<\mathrm{Al}$
4 $\mathrm{S}<\mathrm{C}<\mathrm{Al}<\mathrm{Cs}$
Explanation:
On moving from left to right in a period atomic radii decreases and the moving from top to bottom in a group atomic radii increases. $\therefore$ The order of increasing atomic radii are$\underset{170}{\mathrm{C}}<\underset{180}{\mathrm{~S}}<\underset{184}{\mathrm{Al}}<\underset{300}{\mathrm{Cs}}$ Atomic radii $(\mathrm{pm})$
(JEE Main 2019
Classification of Elements and Periodicity in Properties
89447
For which of the following ionic species radius would be maximum?
1 $\mathrm{C}^{4-}$
2 $\mathrm{N}^{3-}$
3 $\mathrm{O}^{2-}$
4 $\mathrm{Mg}^{2+}$
Explanation:
Among the isoelectronic species ionic radius increase with increase in negative charge or decrease in positive charge. Therefore, the order of ionic radius maximum in $\mathrm{C}^{4-}$ and increasing order of ionic radius are- $\mathrm{Mg}^{2+}<\mathrm{O}^{2-}<\mathrm{N}^{3-}<\mathrm{C}^{4-}$
