NEET Test Series from KOTA - 10 Papers In MS WORD
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Classification of Elements and Periodicity in Properties
89371
The number of elements present in the fourth period is
1 32
2 8
3 18
4 2
Explanation:
For $4^{\text {th }}$ period $\therefore$ The orbital in $4^{\text {th }}$ period is $=4 \mathrm{~s}, 3 \mathrm{~d}, 4 \mathrm{p}$ And the no. of electron in the orbit is $2,10,6$ The number of electron present in the fourth period is 18.
AP-EAMCET (Engg.) 2013
Classification of Elements and Periodicity in Properties
89374
Properties of elements are periodic function of number of present in the nucleus.
1 protons
2 electrons
3 neutrons
4 mesons.
Explanation:
Properties of elements are periodic function of number of protons present in the nucleus. Number of protons $=$ number of electrons. - Physical and chemical properties of elements depend on the number of electrons and their arrangement. Thus, properties of elements are periodic function of number of protons present in the nucleus.
J and K CET-(2012)
Classification of Elements and Periodicity in Properties
89376
Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in
1 forming covalent halides
2 forming polymeric hydrides
3 exhibiting maximum covalency in compounds
4 exhibiting amphoteric nature in their oxides
Explanation:
Beryllium and aluminium are S-block element and P-block element respectively. Exhibiting maximum covalency in compoundly due to diagonal relationship, $\mathrm{Be}$ and $\mathrm{Al}$ have many similar properties. However they differ in exhibiting maximum covalency. Maximum covalency of $\mathrm{Be}=4$ Maximum covalency of $\mathrm{Al}=6$ This is due to absence of d-orbital in $\mathrm{Be}$.
BITSAT-2011
Classification of Elements and Periodicity in Properties
89378
The effective nuclear charge is equal to
1 $\mathrm{Z}-\mathrm{S}$
2 $\mathrm{Z}+\mathrm{S}$
3 $A-Z$
4 $\mathrm{Z}+\mathrm{A}$
Explanation:
The effective nuclear charge is the net positive charge experienced by valence electrons. $\mathrm{Z}=$ atomic number $\mathrm{S}=$ Number of shielding electrons $$ Z_{\text {eff }}=\mathrm{Z}-\mathrm{S} $$
Classification of Elements and Periodicity in Properties
89371
The number of elements present in the fourth period is
1 32
2 8
3 18
4 2
Explanation:
For $4^{\text {th }}$ period $\therefore$ The orbital in $4^{\text {th }}$ period is $=4 \mathrm{~s}, 3 \mathrm{~d}, 4 \mathrm{p}$ And the no. of electron in the orbit is $2,10,6$ The number of electron present in the fourth period is 18.
AP-EAMCET (Engg.) 2013
Classification of Elements and Periodicity in Properties
89374
Properties of elements are periodic function of number of present in the nucleus.
1 protons
2 electrons
3 neutrons
4 mesons.
Explanation:
Properties of elements are periodic function of number of protons present in the nucleus. Number of protons $=$ number of electrons. - Physical and chemical properties of elements depend on the number of electrons and their arrangement. Thus, properties of elements are periodic function of number of protons present in the nucleus.
J and K CET-(2012)
Classification of Elements and Periodicity in Properties
89376
Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in
1 forming covalent halides
2 forming polymeric hydrides
3 exhibiting maximum covalency in compounds
4 exhibiting amphoteric nature in their oxides
Explanation:
Beryllium and aluminium are S-block element and P-block element respectively. Exhibiting maximum covalency in compoundly due to diagonal relationship, $\mathrm{Be}$ and $\mathrm{Al}$ have many similar properties. However they differ in exhibiting maximum covalency. Maximum covalency of $\mathrm{Be}=4$ Maximum covalency of $\mathrm{Al}=6$ This is due to absence of d-orbital in $\mathrm{Be}$.
BITSAT-2011
Classification of Elements and Periodicity in Properties
89378
The effective nuclear charge is equal to
1 $\mathrm{Z}-\mathrm{S}$
2 $\mathrm{Z}+\mathrm{S}$
3 $A-Z$
4 $\mathrm{Z}+\mathrm{A}$
Explanation:
The effective nuclear charge is the net positive charge experienced by valence electrons. $\mathrm{Z}=$ atomic number $\mathrm{S}=$ Number of shielding electrons $$ Z_{\text {eff }}=\mathrm{Z}-\mathrm{S} $$
Classification of Elements and Periodicity in Properties
89371
The number of elements present in the fourth period is
1 32
2 8
3 18
4 2
Explanation:
For $4^{\text {th }}$ period $\therefore$ The orbital in $4^{\text {th }}$ period is $=4 \mathrm{~s}, 3 \mathrm{~d}, 4 \mathrm{p}$ And the no. of electron in the orbit is $2,10,6$ The number of electron present in the fourth period is 18.
AP-EAMCET (Engg.) 2013
Classification of Elements and Periodicity in Properties
89374
Properties of elements are periodic function of number of present in the nucleus.
1 protons
2 electrons
3 neutrons
4 mesons.
Explanation:
Properties of elements are periodic function of number of protons present in the nucleus. Number of protons $=$ number of electrons. - Physical and chemical properties of elements depend on the number of electrons and their arrangement. Thus, properties of elements are periodic function of number of protons present in the nucleus.
J and K CET-(2012)
Classification of Elements and Periodicity in Properties
89376
Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in
1 forming covalent halides
2 forming polymeric hydrides
3 exhibiting maximum covalency in compounds
4 exhibiting amphoteric nature in their oxides
Explanation:
Beryllium and aluminium are S-block element and P-block element respectively. Exhibiting maximum covalency in compoundly due to diagonal relationship, $\mathrm{Be}$ and $\mathrm{Al}$ have many similar properties. However they differ in exhibiting maximum covalency. Maximum covalency of $\mathrm{Be}=4$ Maximum covalency of $\mathrm{Al}=6$ This is due to absence of d-orbital in $\mathrm{Be}$.
BITSAT-2011
Classification of Elements and Periodicity in Properties
89378
The effective nuclear charge is equal to
1 $\mathrm{Z}-\mathrm{S}$
2 $\mathrm{Z}+\mathrm{S}$
3 $A-Z$
4 $\mathrm{Z}+\mathrm{A}$
Explanation:
The effective nuclear charge is the net positive charge experienced by valence electrons. $\mathrm{Z}=$ atomic number $\mathrm{S}=$ Number of shielding electrons $$ Z_{\text {eff }}=\mathrm{Z}-\mathrm{S} $$
Classification of Elements and Periodicity in Properties
89371
The number of elements present in the fourth period is
1 32
2 8
3 18
4 2
Explanation:
For $4^{\text {th }}$ period $\therefore$ The orbital in $4^{\text {th }}$ period is $=4 \mathrm{~s}, 3 \mathrm{~d}, 4 \mathrm{p}$ And the no. of electron in the orbit is $2,10,6$ The number of electron present in the fourth period is 18.
AP-EAMCET (Engg.) 2013
Classification of Elements and Periodicity in Properties
89374
Properties of elements are periodic function of number of present in the nucleus.
1 protons
2 electrons
3 neutrons
4 mesons.
Explanation:
Properties of elements are periodic function of number of protons present in the nucleus. Number of protons $=$ number of electrons. - Physical and chemical properties of elements depend on the number of electrons and their arrangement. Thus, properties of elements are periodic function of number of protons present in the nucleus.
J and K CET-(2012)
Classification of Elements and Periodicity in Properties
89376
Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in
1 forming covalent halides
2 forming polymeric hydrides
3 exhibiting maximum covalency in compounds
4 exhibiting amphoteric nature in their oxides
Explanation:
Beryllium and aluminium are S-block element and P-block element respectively. Exhibiting maximum covalency in compoundly due to diagonal relationship, $\mathrm{Be}$ and $\mathrm{Al}$ have many similar properties. However they differ in exhibiting maximum covalency. Maximum covalency of $\mathrm{Be}=4$ Maximum covalency of $\mathrm{Al}=6$ This is due to absence of d-orbital in $\mathrm{Be}$.
BITSAT-2011
Classification of Elements and Periodicity in Properties
89378
The effective nuclear charge is equal to
1 $\mathrm{Z}-\mathrm{S}$
2 $\mathrm{Z}+\mathrm{S}$
3 $A-Z$
4 $\mathrm{Z}+\mathrm{A}$
Explanation:
The effective nuclear charge is the net positive charge experienced by valence electrons. $\mathrm{Z}=$ atomic number $\mathrm{S}=$ Number of shielding electrons $$ Z_{\text {eff }}=\mathrm{Z}-\mathrm{S} $$
