03. Uncertainty Principle
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Structure of Atom

238802 If the uncertainty in momentum and uncertainty in the position of a particle are equal. then the uncertaintiy in its velocity would be given by
#[Qdiff: Hard, QCat: Numerical Based, examname: AP EAPCET 24.08.2021, Shift-I
, CG PET -2019]#

1 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{2 \pi}}$
2 $\Delta \mathrm{v} \geq \frac{1}{2 \mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
3 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{\pi}}$
4 $\Delta \mathrm{v} \geq \frac{1}{\mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
Structure of Atom

238822 The de-Broglie wavelength of a particle with mass $1 \mathrm{~kg}$ and velocity $100 \mathrm{~m} / \mathrm{s}$ is
#[Qdiff: Hard, QCat: Numerical Based, examname: JIPMER-2008, NEET-1999
, JCECE - 2007
, AP-EAMCET (Engg.) 1997, 1996 AP - EAMCET - (Medical)-1997]#

1 $6.6 \times 10^{-33} \mathrm{~m}$
2 $6.6 \times 10^{-36} \mathrm{~m}$
3 $3.3 \times 10^{+33} \mathrm{~m}$
4 $3.3 \times 10^{-36} \mathrm{~m}$
Structure of Atom

238825 The minimum values of uncertainties involved in the determination of both the position and velocity of a particle respectively are $1 \times 10^{-10} \mathrm{~m}$ and $1 \times 10^{-10} \mathrm{~ms}^{-1}$. Then, the mass (in $\mathrm{kg}$ ) of the particle is
#[Qdiff: Very Easy, QCat: Theory Based, examname: |---|, |
,
, Kerala-CEE-2015
, $\begin{aligned}
, \end{aligned}$
, {l}
, |${l} { Ans. A
|, Exp: According to Heisenberg uncertainty } |, | { principle - } |, | =}{4 } |, | =}{4 } =}{4 } |, | { Given } =1 10^{-10} , =1 10^{-10} ^{-1}$ |, & \mathrm{m}=\frac{6.626 \times 10^{-34}}{4 \times 3.14 \times
, 10^{-10} \times 10^{-10}} \\
, & \Rightarrow 5.270 \times 10^{-15} \mathrm{~kg}
, 311. Uncertainty principle is valid for
,

1 $5.270 \times 10^{-15}$
2 $5.270 \times 10^{-20}$
3 $5.270 \times 10^{-16}$
4 $5.270 \times 10^{-10}$
5 $5.270 \times 10^{-14}$
Structure of Atom

238830 Which one is a wrong statement?

1 Total orbital angular momentum of electron in s-orbital is equal to zero.
2 An orbital is designated by three quantum numbers while an electron in an atom is designed by four quantum numbers.
3 The electronic configuration of $\mathrm{N}$ atom is
4 The value of $\mathrm{m}$ for $\mathrm{d}_{\mathrm{z}}^2$ is zero.
NEET-2018
For More Updates join with Us
Structure of Atom

238802 If the uncertainty in momentum and uncertainty in the position of a particle are equal. then the uncertaintiy in its velocity would be given by
#[Qdiff: Hard, QCat: Numerical Based, examname: AP EAPCET 24.08.2021, Shift-I
, CG PET -2019]#

1 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{2 \pi}}$
2 $\Delta \mathrm{v} \geq \frac{1}{2 \mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
3 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{\pi}}$
4 $\Delta \mathrm{v} \geq \frac{1}{\mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
Structure of Atom

238822 The de-Broglie wavelength of a particle with mass $1 \mathrm{~kg}$ and velocity $100 \mathrm{~m} / \mathrm{s}$ is
#[Qdiff: Hard, QCat: Numerical Based, examname: JIPMER-2008, NEET-1999
, JCECE - 2007
, AP-EAMCET (Engg.) 1997, 1996 AP - EAMCET - (Medical)-1997]#

1 $6.6 \times 10^{-33} \mathrm{~m}$
2 $6.6 \times 10^{-36} \mathrm{~m}$
3 $3.3 \times 10^{+33} \mathrm{~m}$
4 $3.3 \times 10^{-36} \mathrm{~m}$
Structure of Atom

238825 The minimum values of uncertainties involved in the determination of both the position and velocity of a particle respectively are $1 \times 10^{-10} \mathrm{~m}$ and $1 \times 10^{-10} \mathrm{~ms}^{-1}$. Then, the mass (in $\mathrm{kg}$ ) of the particle is
#[Qdiff: Very Easy, QCat: Theory Based, examname: |---|, |
,
, Kerala-CEE-2015
, $\begin{aligned}
, \end{aligned}$
, {l}
, |${l} { Ans. A
|, Exp: According to Heisenberg uncertainty } |, | { principle - } |, | =}{4 } |, | =}{4 } =}{4 } |, | { Given } =1 10^{-10} , =1 10^{-10} ^{-1}$ |, & \mathrm{m}=\frac{6.626 \times 10^{-34}}{4 \times 3.14 \times
, 10^{-10} \times 10^{-10}} \\
, & \Rightarrow 5.270 \times 10^{-15} \mathrm{~kg}
, 311. Uncertainty principle is valid for
,

1 $5.270 \times 10^{-15}$
2 $5.270 \times 10^{-20}$
3 $5.270 \times 10^{-16}$
4 $5.270 \times 10^{-10}$
5 $5.270 \times 10^{-14}$
Structure of Atom

238830 Which one is a wrong statement?

1 Total orbital angular momentum of electron in s-orbital is equal to zero.
2 An orbital is designated by three quantum numbers while an electron in an atom is designed by four quantum numbers.
3 The electronic configuration of $\mathrm{N}$ atom is
4 The value of $\mathrm{m}$ for $\mathrm{d}_{\mathrm{z}}^2$ is zero.
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Structure of Atom

238802 If the uncertainty in momentum and uncertainty in the position of a particle are equal. then the uncertaintiy in its velocity would be given by
#[Qdiff: Hard, QCat: Numerical Based, examname: AP EAPCET 24.08.2021, Shift-I
, CG PET -2019]#

1 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{2 \pi}}$
2 $\Delta \mathrm{v} \geq \frac{1}{2 \mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
3 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{\pi}}$
4 $\Delta \mathrm{v} \geq \frac{1}{\mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
Structure of Atom

238822 The de-Broglie wavelength of a particle with mass $1 \mathrm{~kg}$ and velocity $100 \mathrm{~m} / \mathrm{s}$ is
#[Qdiff: Hard, QCat: Numerical Based, examname: JIPMER-2008, NEET-1999
, JCECE - 2007
, AP-EAMCET (Engg.) 1997, 1996 AP - EAMCET - (Medical)-1997]#

1 $6.6 \times 10^{-33} \mathrm{~m}$
2 $6.6 \times 10^{-36} \mathrm{~m}$
3 $3.3 \times 10^{+33} \mathrm{~m}$
4 $3.3 \times 10^{-36} \mathrm{~m}$
Structure of Atom

238825 The minimum values of uncertainties involved in the determination of both the position and velocity of a particle respectively are $1 \times 10^{-10} \mathrm{~m}$ and $1 \times 10^{-10} \mathrm{~ms}^{-1}$. Then, the mass (in $\mathrm{kg}$ ) of the particle is
#[Qdiff: Very Easy, QCat: Theory Based, examname: |---|, |
,
, Kerala-CEE-2015
, $\begin{aligned}
, \end{aligned}$
, {l}
, |${l} { Ans. A
|, Exp: According to Heisenberg uncertainty } |, | { principle - } |, | =}{4 } |, | =}{4 } =}{4 } |, | { Given } =1 10^{-10} , =1 10^{-10} ^{-1}$ |, & \mathrm{m}=\frac{6.626 \times 10^{-34}}{4 \times 3.14 \times
, 10^{-10} \times 10^{-10}} \\
, & \Rightarrow 5.270 \times 10^{-15} \mathrm{~kg}
, 311. Uncertainty principle is valid for
,

1 $5.270 \times 10^{-15}$
2 $5.270 \times 10^{-20}$
3 $5.270 \times 10^{-16}$
4 $5.270 \times 10^{-10}$
5 $5.270 \times 10^{-14}$
Structure of Atom

238830 Which one is a wrong statement?

1 Total orbital angular momentum of electron in s-orbital is equal to zero.
2 An orbital is designated by three quantum numbers while an electron in an atom is designed by four quantum numbers.
3 The electronic configuration of $\mathrm{N}$ atom is
4 The value of $\mathrm{m}$ for $\mathrm{d}_{\mathrm{z}}^2$ is zero.
NEET-2018
Join With Us for More Updates
Structure of Atom

238802 If the uncertainty in momentum and uncertainty in the position of a particle are equal. then the uncertaintiy in its velocity would be given by
#[Qdiff: Hard, QCat: Numerical Based, examname: AP EAPCET 24.08.2021, Shift-I
, CG PET -2019]#

1 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{2 \pi}}$
2 $\Delta \mathrm{v} \geq \frac{1}{2 \mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
3 $\Delta \mathrm{v} \geq \sqrt{\frac{\mathrm{h}}{\pi}}$
4 $\Delta \mathrm{v} \geq \frac{1}{\mathrm{~m}} \sqrt{\frac{\mathrm{h}}{\pi}}$
Structure of Atom

238822 The de-Broglie wavelength of a particle with mass $1 \mathrm{~kg}$ and velocity $100 \mathrm{~m} / \mathrm{s}$ is
#[Qdiff: Hard, QCat: Numerical Based, examname: JIPMER-2008, NEET-1999
, JCECE - 2007
, AP-EAMCET (Engg.) 1997, 1996 AP - EAMCET - (Medical)-1997]#

1 $6.6 \times 10^{-33} \mathrm{~m}$
2 $6.6 \times 10^{-36} \mathrm{~m}$
3 $3.3 \times 10^{+33} \mathrm{~m}$
4 $3.3 \times 10^{-36} \mathrm{~m}$
Structure of Atom

238825 The minimum values of uncertainties involved in the determination of both the position and velocity of a particle respectively are $1 \times 10^{-10} \mathrm{~m}$ and $1 \times 10^{-10} \mathrm{~ms}^{-1}$. Then, the mass (in $\mathrm{kg}$ ) of the particle is
#[Qdiff: Very Easy, QCat: Theory Based, examname: |---|, |
,
, Kerala-CEE-2015
, $\begin{aligned}
, \end{aligned}$
, {l}
, |${l} { Ans. A
|, Exp: According to Heisenberg uncertainty } |, | { principle - } |, | =}{4 } |, | =}{4 } =}{4 } |, | { Given } =1 10^{-10} , =1 10^{-10} ^{-1}$ |, & \mathrm{m}=\frac{6.626 \times 10^{-34}}{4 \times 3.14 \times
, 10^{-10} \times 10^{-10}} \\
, & \Rightarrow 5.270 \times 10^{-15} \mathrm{~kg}
, 311. Uncertainty principle is valid for
,

1 $5.270 \times 10^{-15}$
2 $5.270 \times 10^{-20}$
3 $5.270 \times 10^{-16}$
4 $5.270 \times 10^{-10}$
5 $5.270 \times 10^{-14}$
Structure of Atom

238830 Which one is a wrong statement?

1 Total orbital angular momentum of electron in s-orbital is equal to zero.
2 An orbital is designated by three quantum numbers while an electron in an atom is designed by four quantum numbers.
3 The electronic configuration of $\mathrm{N}$ atom is
4 The value of $\mathrm{m}$ for $\mathrm{d}_{\mathrm{z}}^2$ is zero.
NEET-2018
For More Updates join with Us