238658
In Rutherford's $\alpha$-ray scattering experiment, the alpha particles are detected using a screen coated with :
1 carbon black
2 platinum black
3 zinc sulphide
4 polytetrafluoro ethylene
Explanation:
Rutherford's Alpha Scattering Experiment directed high energy streams of $\alpha$-particles from a radioactive source at a thin sheet (100 nm thickness) of gold. - In order to study the deflection caused to the $\alpha$ particles, he placed a fluorescent zinc sulphide screen around the thin gold foil.
AP-EAMCET-1999
Structure of Atom
238663
The number of protons. Neutrons and electrons in ${ }_6^{13} \mathrm{C}$ respectively are -
1 $6,7,6$
2 $13,6,6$
3 $6,7,13$
4 $6,6,13$
Explanation:
For $13_{\mathrm{C}_6}$ Atomic number $=$ Number of protons $=6$ Number of neutrons $=$ Atomic mass number of protons $=13-6=7$ Number of electrons $=$ number of protons $=6$
AP EAPCET 20.08.2021 Shift-I
Structure of Atom
238665
In which of the following options, the law of triad is applicable?
1 $\mathrm{Na}, \mathrm{K}, \mathrm{Rb}$
2 $\mathrm{Cl}, \mathrm{Br}, \mathrm{I}$
3 $\mathrm{C}, \mathrm{N}, \mathrm{O}$
4 $\mathrm{Ca}, \mathrm{Sr}$
Explanation:
For Dobereiner's triads, the atomic weight of a middle element is almost average of the other two. The law of triad is applicable to following species. 1)For $\underset{35.5}{\mathrm{Cl}} \mathrm{Br}$ and $\mathrm{I}$ 이.9 $=\frac{35.5+126.9}{2}=81.2$ 2)For Li Na and K $\underset{23}{K}=\frac{7+39}{2}=23$ 3)For $\mathrm{Ca} \quad \mathrm{Sr}$ and $\mathrm{Ba}=\frac{40+137}{2}=88.5$
TS-EAMCET 09.08.2021
Structure of Atom
238667
According to Moseley, a straight line group is obtained on plotting
1 the frequencies of characteristics X-rays of elements against their atomic numbers
2 the square of the frequencies of characteristics X-rays of elements against their atomic numbers
3 the square root of the frequencies of characteristics X-rays of elements against the atomic numbers
4 the reciprocal of the frequencies of characteristics X-rays of elements against the atomic numbers.
Explanation:
According to Moseley, the square root of the frequencies of characteristic X-rays of elements against the atomic numbers. $\sqrt{v}=\mathrm{a}(\mathrm{Z}-\mathrm{b})$ where, $a=$ Proportionality constant $\mathrm{b}=$ Another constant $\mathrm{Z}=$ Atomic number
238658
In Rutherford's $\alpha$-ray scattering experiment, the alpha particles are detected using a screen coated with :
1 carbon black
2 platinum black
3 zinc sulphide
4 polytetrafluoro ethylene
Explanation:
Rutherford's Alpha Scattering Experiment directed high energy streams of $\alpha$-particles from a radioactive source at a thin sheet (100 nm thickness) of gold. - In order to study the deflection caused to the $\alpha$ particles, he placed a fluorescent zinc sulphide screen around the thin gold foil.
AP-EAMCET-1999
Structure of Atom
238663
The number of protons. Neutrons and electrons in ${ }_6^{13} \mathrm{C}$ respectively are -
1 $6,7,6$
2 $13,6,6$
3 $6,7,13$
4 $6,6,13$
Explanation:
For $13_{\mathrm{C}_6}$ Atomic number $=$ Number of protons $=6$ Number of neutrons $=$ Atomic mass number of protons $=13-6=7$ Number of electrons $=$ number of protons $=6$
AP EAPCET 20.08.2021 Shift-I
Structure of Atom
238665
In which of the following options, the law of triad is applicable?
1 $\mathrm{Na}, \mathrm{K}, \mathrm{Rb}$
2 $\mathrm{Cl}, \mathrm{Br}, \mathrm{I}$
3 $\mathrm{C}, \mathrm{N}, \mathrm{O}$
4 $\mathrm{Ca}, \mathrm{Sr}$
Explanation:
For Dobereiner's triads, the atomic weight of a middle element is almost average of the other two. The law of triad is applicable to following species. 1)For $\underset{35.5}{\mathrm{Cl}} \mathrm{Br}$ and $\mathrm{I}$ 이.9 $=\frac{35.5+126.9}{2}=81.2$ 2)For Li Na and K $\underset{23}{K}=\frac{7+39}{2}=23$ 3)For $\mathrm{Ca} \quad \mathrm{Sr}$ and $\mathrm{Ba}=\frac{40+137}{2}=88.5$
TS-EAMCET 09.08.2021
Structure of Atom
238667
According to Moseley, a straight line group is obtained on plotting
1 the frequencies of characteristics X-rays of elements against their atomic numbers
2 the square of the frequencies of characteristics X-rays of elements against their atomic numbers
3 the square root of the frequencies of characteristics X-rays of elements against the atomic numbers
4 the reciprocal of the frequencies of characteristics X-rays of elements against the atomic numbers.
Explanation:
According to Moseley, the square root of the frequencies of characteristic X-rays of elements against the atomic numbers. $\sqrt{v}=\mathrm{a}(\mathrm{Z}-\mathrm{b})$ where, $a=$ Proportionality constant $\mathrm{b}=$ Another constant $\mathrm{Z}=$ Atomic number
238658
In Rutherford's $\alpha$-ray scattering experiment, the alpha particles are detected using a screen coated with :
1 carbon black
2 platinum black
3 zinc sulphide
4 polytetrafluoro ethylene
Explanation:
Rutherford's Alpha Scattering Experiment directed high energy streams of $\alpha$-particles from a radioactive source at a thin sheet (100 nm thickness) of gold. - In order to study the deflection caused to the $\alpha$ particles, he placed a fluorescent zinc sulphide screen around the thin gold foil.
AP-EAMCET-1999
Structure of Atom
238663
The number of protons. Neutrons and electrons in ${ }_6^{13} \mathrm{C}$ respectively are -
1 $6,7,6$
2 $13,6,6$
3 $6,7,13$
4 $6,6,13$
Explanation:
For $13_{\mathrm{C}_6}$ Atomic number $=$ Number of protons $=6$ Number of neutrons $=$ Atomic mass number of protons $=13-6=7$ Number of electrons $=$ number of protons $=6$
AP EAPCET 20.08.2021 Shift-I
Structure of Atom
238665
In which of the following options, the law of triad is applicable?
1 $\mathrm{Na}, \mathrm{K}, \mathrm{Rb}$
2 $\mathrm{Cl}, \mathrm{Br}, \mathrm{I}$
3 $\mathrm{C}, \mathrm{N}, \mathrm{O}$
4 $\mathrm{Ca}, \mathrm{Sr}$
Explanation:
For Dobereiner's triads, the atomic weight of a middle element is almost average of the other two. The law of triad is applicable to following species. 1)For $\underset{35.5}{\mathrm{Cl}} \mathrm{Br}$ and $\mathrm{I}$ 이.9 $=\frac{35.5+126.9}{2}=81.2$ 2)For Li Na and K $\underset{23}{K}=\frac{7+39}{2}=23$ 3)For $\mathrm{Ca} \quad \mathrm{Sr}$ and $\mathrm{Ba}=\frac{40+137}{2}=88.5$
TS-EAMCET 09.08.2021
Structure of Atom
238667
According to Moseley, a straight line group is obtained on plotting
1 the frequencies of characteristics X-rays of elements against their atomic numbers
2 the square of the frequencies of characteristics X-rays of elements against their atomic numbers
3 the square root of the frequencies of characteristics X-rays of elements against the atomic numbers
4 the reciprocal of the frequencies of characteristics X-rays of elements against the atomic numbers.
Explanation:
According to Moseley, the square root of the frequencies of characteristic X-rays of elements against the atomic numbers. $\sqrt{v}=\mathrm{a}(\mathrm{Z}-\mathrm{b})$ where, $a=$ Proportionality constant $\mathrm{b}=$ Another constant $\mathrm{Z}=$ Atomic number
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Structure of Atom
238658
In Rutherford's $\alpha$-ray scattering experiment, the alpha particles are detected using a screen coated with :
1 carbon black
2 platinum black
3 zinc sulphide
4 polytetrafluoro ethylene
Explanation:
Rutherford's Alpha Scattering Experiment directed high energy streams of $\alpha$-particles from a radioactive source at a thin sheet (100 nm thickness) of gold. - In order to study the deflection caused to the $\alpha$ particles, he placed a fluorescent zinc sulphide screen around the thin gold foil.
AP-EAMCET-1999
Structure of Atom
238663
The number of protons. Neutrons and electrons in ${ }_6^{13} \mathrm{C}$ respectively are -
1 $6,7,6$
2 $13,6,6$
3 $6,7,13$
4 $6,6,13$
Explanation:
For $13_{\mathrm{C}_6}$ Atomic number $=$ Number of protons $=6$ Number of neutrons $=$ Atomic mass number of protons $=13-6=7$ Number of electrons $=$ number of protons $=6$
AP EAPCET 20.08.2021 Shift-I
Structure of Atom
238665
In which of the following options, the law of triad is applicable?
1 $\mathrm{Na}, \mathrm{K}, \mathrm{Rb}$
2 $\mathrm{Cl}, \mathrm{Br}, \mathrm{I}$
3 $\mathrm{C}, \mathrm{N}, \mathrm{O}$
4 $\mathrm{Ca}, \mathrm{Sr}$
Explanation:
For Dobereiner's triads, the atomic weight of a middle element is almost average of the other two. The law of triad is applicable to following species. 1)For $\underset{35.5}{\mathrm{Cl}} \mathrm{Br}$ and $\mathrm{I}$ 이.9 $=\frac{35.5+126.9}{2}=81.2$ 2)For Li Na and K $\underset{23}{K}=\frac{7+39}{2}=23$ 3)For $\mathrm{Ca} \quad \mathrm{Sr}$ and $\mathrm{Ba}=\frac{40+137}{2}=88.5$
TS-EAMCET 09.08.2021
Structure of Atom
238667
According to Moseley, a straight line group is obtained on plotting
1 the frequencies of characteristics X-rays of elements against their atomic numbers
2 the square of the frequencies of characteristics X-rays of elements against their atomic numbers
3 the square root of the frequencies of characteristics X-rays of elements against the atomic numbers
4 the reciprocal of the frequencies of characteristics X-rays of elements against the atomic numbers.
Explanation:
According to Moseley, the square root of the frequencies of characteristic X-rays of elements against the atomic numbers. $\sqrt{v}=\mathrm{a}(\mathrm{Z}-\mathrm{b})$ where, $a=$ Proportionality constant $\mathrm{b}=$ Another constant $\mathrm{Z}=$ Atomic number
