238672
Which of the following transition of an electron in $\mathrm{H}$-atom will emit maximum energy?
1 $\mathrm{n}_6 \longrightarrow \mathrm{n}_5$
2 $\mathrm{n}_1 \longrightarrow \mathrm{n}_2$
3 $\mathrm{n}_3 \longrightarrow \mathrm{n}_2$
4 $\mathrm{n}_4 \longrightarrow \mathrm{n}_3$
Explanation:
We know that energy can we calculated by using formula $(E)=\frac{\mathrm{hc}}{\lambda}$. $\begin{aligned} & \frac{1}{\lambda}=\mathrm{RZ}^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \\ & \mathrm{E}=\mathrm{RZ}^2 \mathrm{hc}\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \end{aligned}$ When, transition is from $\mathrm{n}_3-\mathrm{n}_2$, it produce highest energy.
BCECE-2017
Structure of Atom
238680
Rutherford's experiment on the scattering of $\alpha$-particles showed for the first time that the atom has:
1 electrons
2 Protons
3 Nucleus
4 neutrons
Explanation:
The conclusion of Rutherford from his $\alpha$-ray experiment are: (i) Most of the space inside the atom is empty because most of the alpha-particles passed through the gold foil without getting deflected. (ii) Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space. (iii) A very small fraction of alpha-particles were deflected by $180^{\circ}$. Indicating that all the positive charges and mass of the gold atom were concentrated in very small volume within the atom. From the data he also calculated that the radius of the nucleus is about 105 times less the radius of the atom.
UPTU/UPSEE-2005
Structure of Atom
238654
When $4 p$ orbital in any atom is filled completely, the next electron goes in :
1 $5 \mathrm{~s}$
2 $3 \mathrm{~d}$
3 $4 \mathrm{~d}$
4 $4 \mathrm{f}$
Explanation:
According to the Aufbau principle and (n + 1) rule, the orbitals with increasing order their energies is as follows, $1 \mathrm{~s}<2 \mathrm{~s}<2 \mathrm{p}<3 \mathrm{~s}<3 \mathrm{p}<4 \mathrm{~s}<3 \mathrm{~d}<4 \mathrm{p}<5 \mathrm{~s}$ Therefore, after $4 \mathrm{p}$ orbital is completely filled, the next electron goes in $5 \mathrm{~s}$ orbital.
AP-EAMCET-1991
Structure of Atom
238657
Rutherford's experiment on scattering of $\alpha$ particles showed for the first time that the atom has :
1 nucleus
2 electron
3 proton
4 neutron
Explanation:
Rutherford's show that for first time atom has positively charged nucleus through his অ-particles scattering experiment. Number of scattered particles-
NEET Test Series from KOTA - 10 Papers In MS WORD
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Structure of Atom
238672
Which of the following transition of an electron in $\mathrm{H}$-atom will emit maximum energy?
1 $\mathrm{n}_6 \longrightarrow \mathrm{n}_5$
2 $\mathrm{n}_1 \longrightarrow \mathrm{n}_2$
3 $\mathrm{n}_3 \longrightarrow \mathrm{n}_2$
4 $\mathrm{n}_4 \longrightarrow \mathrm{n}_3$
Explanation:
We know that energy can we calculated by using formula $(E)=\frac{\mathrm{hc}}{\lambda}$. $\begin{aligned} & \frac{1}{\lambda}=\mathrm{RZ}^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \\ & \mathrm{E}=\mathrm{RZ}^2 \mathrm{hc}\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \end{aligned}$ When, transition is from $\mathrm{n}_3-\mathrm{n}_2$, it produce highest energy.
BCECE-2017
Structure of Atom
238680
Rutherford's experiment on the scattering of $\alpha$-particles showed for the first time that the atom has:
1 electrons
2 Protons
3 Nucleus
4 neutrons
Explanation:
The conclusion of Rutherford from his $\alpha$-ray experiment are: (i) Most of the space inside the atom is empty because most of the alpha-particles passed through the gold foil without getting deflected. (ii) Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space. (iii) A very small fraction of alpha-particles were deflected by $180^{\circ}$. Indicating that all the positive charges and mass of the gold atom were concentrated in very small volume within the atom. From the data he also calculated that the radius of the nucleus is about 105 times less the radius of the atom.
UPTU/UPSEE-2005
Structure of Atom
238654
When $4 p$ orbital in any atom is filled completely, the next electron goes in :
1 $5 \mathrm{~s}$
2 $3 \mathrm{~d}$
3 $4 \mathrm{~d}$
4 $4 \mathrm{f}$
Explanation:
According to the Aufbau principle and (n + 1) rule, the orbitals with increasing order their energies is as follows, $1 \mathrm{~s}<2 \mathrm{~s}<2 \mathrm{p}<3 \mathrm{~s}<3 \mathrm{p}<4 \mathrm{~s}<3 \mathrm{~d}<4 \mathrm{p}<5 \mathrm{~s}$ Therefore, after $4 \mathrm{p}$ orbital is completely filled, the next electron goes in $5 \mathrm{~s}$ orbital.
AP-EAMCET-1991
Structure of Atom
238657
Rutherford's experiment on scattering of $\alpha$ particles showed for the first time that the atom has :
1 nucleus
2 electron
3 proton
4 neutron
Explanation:
Rutherford's show that for first time atom has positively charged nucleus through his অ-particles scattering experiment. Number of scattered particles-
238672
Which of the following transition of an electron in $\mathrm{H}$-atom will emit maximum energy?
1 $\mathrm{n}_6 \longrightarrow \mathrm{n}_5$
2 $\mathrm{n}_1 \longrightarrow \mathrm{n}_2$
3 $\mathrm{n}_3 \longrightarrow \mathrm{n}_2$
4 $\mathrm{n}_4 \longrightarrow \mathrm{n}_3$
Explanation:
We know that energy can we calculated by using formula $(E)=\frac{\mathrm{hc}}{\lambda}$. $\begin{aligned} & \frac{1}{\lambda}=\mathrm{RZ}^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \\ & \mathrm{E}=\mathrm{RZ}^2 \mathrm{hc}\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \end{aligned}$ When, transition is from $\mathrm{n}_3-\mathrm{n}_2$, it produce highest energy.
BCECE-2017
Structure of Atom
238680
Rutherford's experiment on the scattering of $\alpha$-particles showed for the first time that the atom has:
1 electrons
2 Protons
3 Nucleus
4 neutrons
Explanation:
The conclusion of Rutherford from his $\alpha$-ray experiment are: (i) Most of the space inside the atom is empty because most of the alpha-particles passed through the gold foil without getting deflected. (ii) Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space. (iii) A very small fraction of alpha-particles were deflected by $180^{\circ}$. Indicating that all the positive charges and mass of the gold atom were concentrated in very small volume within the atom. From the data he also calculated that the radius of the nucleus is about 105 times less the radius of the atom.
UPTU/UPSEE-2005
Structure of Atom
238654
When $4 p$ orbital in any atom is filled completely, the next electron goes in :
1 $5 \mathrm{~s}$
2 $3 \mathrm{~d}$
3 $4 \mathrm{~d}$
4 $4 \mathrm{f}$
Explanation:
According to the Aufbau principle and (n + 1) rule, the orbitals with increasing order their energies is as follows, $1 \mathrm{~s}<2 \mathrm{~s}<2 \mathrm{p}<3 \mathrm{~s}<3 \mathrm{p}<4 \mathrm{~s}<3 \mathrm{~d}<4 \mathrm{p}<5 \mathrm{~s}$ Therefore, after $4 \mathrm{p}$ orbital is completely filled, the next electron goes in $5 \mathrm{~s}$ orbital.
AP-EAMCET-1991
Structure of Atom
238657
Rutherford's experiment on scattering of $\alpha$ particles showed for the first time that the atom has :
1 nucleus
2 electron
3 proton
4 neutron
Explanation:
Rutherford's show that for first time atom has positively charged nucleus through his অ-particles scattering experiment. Number of scattered particles-
238672
Which of the following transition of an electron in $\mathrm{H}$-atom will emit maximum energy?
1 $\mathrm{n}_6 \longrightarrow \mathrm{n}_5$
2 $\mathrm{n}_1 \longrightarrow \mathrm{n}_2$
3 $\mathrm{n}_3 \longrightarrow \mathrm{n}_2$
4 $\mathrm{n}_4 \longrightarrow \mathrm{n}_3$
Explanation:
We know that energy can we calculated by using formula $(E)=\frac{\mathrm{hc}}{\lambda}$. $\begin{aligned} & \frac{1}{\lambda}=\mathrm{RZ}^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \\ & \mathrm{E}=\mathrm{RZ}^2 \mathrm{hc}\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \end{aligned}$ When, transition is from $\mathrm{n}_3-\mathrm{n}_2$, it produce highest energy.
BCECE-2017
Structure of Atom
238680
Rutherford's experiment on the scattering of $\alpha$-particles showed for the first time that the atom has:
1 electrons
2 Protons
3 Nucleus
4 neutrons
Explanation:
The conclusion of Rutherford from his $\alpha$-ray experiment are: (i) Most of the space inside the atom is empty because most of the alpha-particles passed through the gold foil without getting deflected. (ii) Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space. (iii) A very small fraction of alpha-particles were deflected by $180^{\circ}$. Indicating that all the positive charges and mass of the gold atom were concentrated in very small volume within the atom. From the data he also calculated that the radius of the nucleus is about 105 times less the radius of the atom.
UPTU/UPSEE-2005
Structure of Atom
238654
When $4 p$ orbital in any atom is filled completely, the next electron goes in :
1 $5 \mathrm{~s}$
2 $3 \mathrm{~d}$
3 $4 \mathrm{~d}$
4 $4 \mathrm{f}$
Explanation:
According to the Aufbau principle and (n + 1) rule, the orbitals with increasing order their energies is as follows, $1 \mathrm{~s}<2 \mathrm{~s}<2 \mathrm{p}<3 \mathrm{~s}<3 \mathrm{p}<4 \mathrm{~s}<3 \mathrm{~d}<4 \mathrm{p}<5 \mathrm{~s}$ Therefore, after $4 \mathrm{p}$ orbital is completely filled, the next electron goes in $5 \mathrm{~s}$ orbital.
AP-EAMCET-1991
Structure of Atom
238657
Rutherford's experiment on scattering of $\alpha$ particles showed for the first time that the atom has :
1 nucleus
2 electron
3 proton
4 neutron
Explanation:
Rutherford's show that for first time atom has positively charged nucleus through his অ-particles scattering experiment. Number of scattered particles-
