228765 On electrolysis of aqueous solution of a halide of a metal ' $M$ ' by passing 1.5 ampere current for 10 minutes deposits $0.2938 \mathrm{~g}$ of metal. If the atomic mass of the metal is $63 \mathrm{gm} / \mathrm{mole}$, then what will be the formula of the metal halide?
228765 On electrolysis of aqueous solution of a halide of a metal ' $M$ ' by passing 1.5 ampere current for 10 minutes deposits $0.2938 \mathrm{~g}$ of metal. If the atomic mass of the metal is $63 \mathrm{gm} / \mathrm{mole}$, then what will be the formula of the metal halide?
228765 On electrolysis of aqueous solution of a halide of a metal ' $M$ ' by passing 1.5 ampere current for 10 minutes deposits $0.2938 \mathrm{~g}$ of metal. If the atomic mass of the metal is $63 \mathrm{gm} / \mathrm{mole}$, then what will be the formula of the metal halide?
228765 On electrolysis of aqueous solution of a halide of a metal ' $M$ ' by passing 1.5 ampere current for 10 minutes deposits $0.2938 \mathrm{~g}$ of metal. If the atomic mass of the metal is $63 \mathrm{gm} / \mathrm{mole}$, then what will be the formula of the metal halide?