01. Atomic, Molecular and Equivalent Masses
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Some Basic Concepts of Chemistry

228268 What is the mass of one molecule of yellow phosphorus? (Atomic mass, $\mathbf{P}=\mathbf{3 0}$ )

1 $1.993 \times 10^{-22} \mathrm{~kg}$
2 $1.993 \times 10^{-19} \mathrm{mg}$
3 $4.983 \times 10^{-20} \mathrm{mg}$
4 $4.983 \times 10^{-23} \mathrm{~g}$
MHT CET-2014
Some Basic Concepts of Chemistry

228251 What is the actual volume occupied by water molecules present in $20 \mathrm{~cm}^3$ of water?

1 $20 \mathrm{~cm}^3$
2 $10 \mathrm{~cm}^3$
3 $40 \mathrm{~cm}^3$
4 $24.89 \mathrm{dm}^3$
MHT CET-2017
Some Basic Concepts of Chemistry

228252 $0.126 \mathrm{~g}$ of an acid is needed to completely neutralize $20 \mathrm{~mL} 0.1 \mathrm{~N}(\mathrm{NaOH}$ solution. The equivalent weight of the acid is

1 53
2 40
3 45
4 63
WB-JEE-2017
Some Basic Concepts of Chemistry

228253 When $2.46 \mathrm{~g}$ of a hydrated salt $\left(\mathrm{MSO}_4 \times \mathrm{xH}_2 \mathrm{O}\right)$ is completely dehydrated $1.20 \mathrm{~g}$ of anhydrous salt is obtained. If the molecular weight of anhydrous salt is $120 \mathrm{~g} \mathrm{~mol}^{-1}$, what is the value of $x$ ?

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5 7
Kerala-CEE-2016
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Some Basic Concepts of Chemistry

228268 What is the mass of one molecule of yellow phosphorus? (Atomic mass, $\mathbf{P}=\mathbf{3 0}$ )

1 $1.993 \times 10^{-22} \mathrm{~kg}$
2 $1.993 \times 10^{-19} \mathrm{mg}$
3 $4.983 \times 10^{-20} \mathrm{mg}$
4 $4.983 \times 10^{-23} \mathrm{~g}$
MHT CET-2014
Some Basic Concepts of Chemistry

228251 What is the actual volume occupied by water molecules present in $20 \mathrm{~cm}^3$ of water?

1 $20 \mathrm{~cm}^3$
2 $10 \mathrm{~cm}^3$
3 $40 \mathrm{~cm}^3$
4 $24.89 \mathrm{dm}^3$
MHT CET-2017
Some Basic Concepts of Chemistry

228252 $0.126 \mathrm{~g}$ of an acid is needed to completely neutralize $20 \mathrm{~mL} 0.1 \mathrm{~N}(\mathrm{NaOH}$ solution. The equivalent weight of the acid is

1 53
2 40
3 45
4 63
WB-JEE-2017
Some Basic Concepts of Chemistry

228253 When $2.46 \mathrm{~g}$ of a hydrated salt $\left(\mathrm{MSO}_4 \times \mathrm{xH}_2 \mathrm{O}\right)$ is completely dehydrated $1.20 \mathrm{~g}$ of anhydrous salt is obtained. If the molecular weight of anhydrous salt is $120 \mathrm{~g} \mathrm{~mol}^{-1}$, what is the value of $x$ ?

1 2
2 4
3 5
4 6
5 7
Kerala-CEE-2016
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Some Basic Concepts of Chemistry

228268 What is the mass of one molecule of yellow phosphorus? (Atomic mass, $\mathbf{P}=\mathbf{3 0}$ )

1 $1.993 \times 10^{-22} \mathrm{~kg}$
2 $1.993 \times 10^{-19} \mathrm{mg}$
3 $4.983 \times 10^{-20} \mathrm{mg}$
4 $4.983 \times 10^{-23} \mathrm{~g}$
MHT CET-2014
Some Basic Concepts of Chemistry

228251 What is the actual volume occupied by water molecules present in $20 \mathrm{~cm}^3$ of water?

1 $20 \mathrm{~cm}^3$
2 $10 \mathrm{~cm}^3$
3 $40 \mathrm{~cm}^3$
4 $24.89 \mathrm{dm}^3$
MHT CET-2017
Some Basic Concepts of Chemistry

228252 $0.126 \mathrm{~g}$ of an acid is needed to completely neutralize $20 \mathrm{~mL} 0.1 \mathrm{~N}(\mathrm{NaOH}$ solution. The equivalent weight of the acid is

1 53
2 40
3 45
4 63
WB-JEE-2017
Some Basic Concepts of Chemistry

228253 When $2.46 \mathrm{~g}$ of a hydrated salt $\left(\mathrm{MSO}_4 \times \mathrm{xH}_2 \mathrm{O}\right)$ is completely dehydrated $1.20 \mathrm{~g}$ of anhydrous salt is obtained. If the molecular weight of anhydrous salt is $120 \mathrm{~g} \mathrm{~mol}^{-1}$, what is the value of $x$ ?

1 2
2 4
3 5
4 6
5 7
Kerala-CEE-2016
NEET DIGITAL LIBRARY
Some Basic Concepts of Chemistry

228268 What is the mass of one molecule of yellow phosphorus? (Atomic mass, $\mathbf{P}=\mathbf{3 0}$ )

1 $1.993 \times 10^{-22} \mathrm{~kg}$
2 $1.993 \times 10^{-19} \mathrm{mg}$
3 $4.983 \times 10^{-20} \mathrm{mg}$
4 $4.983 \times 10^{-23} \mathrm{~g}$
MHT CET-2014
Some Basic Concepts of Chemistry

228251 What is the actual volume occupied by water molecules present in $20 \mathrm{~cm}^3$ of water?

1 $20 \mathrm{~cm}^3$
2 $10 \mathrm{~cm}^3$
3 $40 \mathrm{~cm}^3$
4 $24.89 \mathrm{dm}^3$
MHT CET-2017
Some Basic Concepts of Chemistry

228252 $0.126 \mathrm{~g}$ of an acid is needed to completely neutralize $20 \mathrm{~mL} 0.1 \mathrm{~N}(\mathrm{NaOH}$ solution. The equivalent weight of the acid is

1 53
2 40
3 45
4 63
WB-JEE-2017
Some Basic Concepts of Chemistry

228253 When $2.46 \mathrm{~g}$ of a hydrated salt $\left(\mathrm{MSO}_4 \times \mathrm{xH}_2 \mathrm{O}\right)$ is completely dehydrated $1.20 \mathrm{~g}$ of anhydrous salt is obtained. If the molecular weight of anhydrous salt is $120 \mathrm{~g} \mathrm{~mol}^{-1}$, what is the value of $x$ ?

1 2
2 4
3 5
4 6
5 7
Kerala-CEE-2016
Join With Us for More Updates