03. Hardy Winberg Principle
« Previous Topic: 02. Adaptive Radiation Next Topic: 04. Brief Account of Evolution »
Evolution

185095 In a population of 800 rabbits showing HardyWeinberg equilibrium, the frequency of recessive individuals was 0.16 . What is the frequency of heterozygous individuals?

1 0.36
2 0.4
3 0.48
4 0.84
Karnataka CET-20.05.2023
Evolution

185097 Match the phenomenon listed under column I with those listed under column II. Select the correct answer from the options given.
| | Column I | | Column II |
| :---: | :---: | :---: | :---: |
| A | Warburg effect | p | Change in gene frequency by chance |
| B | Pasteur effect | q | Postponing severance in the leaves by applying cytokinin |
| C | Emerson effect | $\mathbf{r}$ | Decline in the consumption of respiratory substrate due to a change from anaerobic to aerobic respiration |
| D | Wright effect | s | Inhibitory effect of $\mathrm{O}_2$ on photosynthesis |
| | | t | Enhancement of photosynthesis by subjecting chlorophyll to the effect of two different wavelengths of light |

1 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{s}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{q}\)
2 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{t}, \mathrm{D}=\mathrm{p}\)
3 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{t}, \mathrm{C}=\mathrm{q}, \mathrm{D}=\mathrm{r}\)
4 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{s}\)
Karnataka CET-2008
Evolution

185103 Which of the following defines Hardy Weinberg's law?

1 \(p^{2}+2 p q+q^{2}=1\)
2 \(p^{2}+3 p q+q^{2}=1\)
3 \(\mathrm{P}^{2}+2 \mathrm{pq}+\mathrm{q}^{2}=0\)
4 \(q^{2}+p^{2}+2 p q=0\)
DUMET-2008
Evolution

185106 Frequency of an autosomal lethal gene is 0.4 . The frequency of carrier in a population or 200 individual is:

1 72
2 96
3 104
4 36
VMMC-2006
Evolution

185109 A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele ' \(A\) ' is 0.7 , genotype frequency of ' \(\mathrm{Aa}\) ' is:

1 0.21
2 0.42
3 0.36
4 0.7
AP EAMCET-2003
NEET DIGITAL LIBRARY
Evolution

185095 In a population of 800 rabbits showing HardyWeinberg equilibrium, the frequency of recessive individuals was 0.16 . What is the frequency of heterozygous individuals?

1 0.36
2 0.4
3 0.48
4 0.84
Karnataka CET-20.05.2023
Evolution

185097 Match the phenomenon listed under column I with those listed under column II. Select the correct answer from the options given.
| | Column I | | Column II |
| :---: | :---: | :---: | :---: |
| A | Warburg effect | p | Change in gene frequency by chance |
| B | Pasteur effect | q | Postponing severance in the leaves by applying cytokinin |
| C | Emerson effect | $\mathbf{r}$ | Decline in the consumption of respiratory substrate due to a change from anaerobic to aerobic respiration |
| D | Wright effect | s | Inhibitory effect of $\mathrm{O}_2$ on photosynthesis |
| | | t | Enhancement of photosynthesis by subjecting chlorophyll to the effect of two different wavelengths of light |

1 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{s}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{q}\)
2 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{t}, \mathrm{D}=\mathrm{p}\)
3 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{t}, \mathrm{C}=\mathrm{q}, \mathrm{D}=\mathrm{r}\)
4 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{s}\)
Karnataka CET-2008
Evolution

185103 Which of the following defines Hardy Weinberg's law?

1 \(p^{2}+2 p q+q^{2}=1\)
2 \(p^{2}+3 p q+q^{2}=1\)
3 \(\mathrm{P}^{2}+2 \mathrm{pq}+\mathrm{q}^{2}=0\)
4 \(q^{2}+p^{2}+2 p q=0\)
DUMET-2008
Evolution

185106 Frequency of an autosomal lethal gene is 0.4 . The frequency of carrier in a population or 200 individual is:

1 72
2 96
3 104
4 36
VMMC-2006
Evolution

185109 A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele ' \(A\) ' is 0.7 , genotype frequency of ' \(\mathrm{Aa}\) ' is:

1 0.21
2 0.42
3 0.36
4 0.7
AP EAMCET-2003
Join With Us for More Updates
Evolution

185095 In a population of 800 rabbits showing HardyWeinberg equilibrium, the frequency of recessive individuals was 0.16 . What is the frequency of heterozygous individuals?

1 0.36
2 0.4
3 0.48
4 0.84
Karnataka CET-20.05.2023
Evolution

185097 Match the phenomenon listed under column I with those listed under column II. Select the correct answer from the options given.
| | Column I | | Column II |
| :---: | :---: | :---: | :---: |
| A | Warburg effect | p | Change in gene frequency by chance |
| B | Pasteur effect | q | Postponing severance in the leaves by applying cytokinin |
| C | Emerson effect | $\mathbf{r}$ | Decline in the consumption of respiratory substrate due to a change from anaerobic to aerobic respiration |
| D | Wright effect | s | Inhibitory effect of $\mathrm{O}_2$ on photosynthesis |
| | | t | Enhancement of photosynthesis by subjecting chlorophyll to the effect of two different wavelengths of light |

1 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{s}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{q}\)
2 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{t}, \mathrm{D}=\mathrm{p}\)
3 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{t}, \mathrm{C}=\mathrm{q}, \mathrm{D}=\mathrm{r}\)
4 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{s}\)
Karnataka CET-2008
Evolution

185103 Which of the following defines Hardy Weinberg's law?

1 \(p^{2}+2 p q+q^{2}=1\)
2 \(p^{2}+3 p q+q^{2}=1\)
3 \(\mathrm{P}^{2}+2 \mathrm{pq}+\mathrm{q}^{2}=0\)
4 \(q^{2}+p^{2}+2 p q=0\)
DUMET-2008
Evolution

185106 Frequency of an autosomal lethal gene is 0.4 . The frequency of carrier in a population or 200 individual is:

1 72
2 96
3 104
4 36
VMMC-2006
Evolution

185109 A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele ' \(A\) ' is 0.7 , genotype frequency of ' \(\mathrm{Aa}\) ' is:

1 0.21
2 0.42
3 0.36
4 0.7
AP EAMCET-2003
For More Updates join with Us
Evolution

185095 In a population of 800 rabbits showing HardyWeinberg equilibrium, the frequency of recessive individuals was 0.16 . What is the frequency of heterozygous individuals?

1 0.36
2 0.4
3 0.48
4 0.84
Karnataka CET-20.05.2023
Evolution

185097 Match the phenomenon listed under column I with those listed under column II. Select the correct answer from the options given.
| | Column I | | Column II |
| :---: | :---: | :---: | :---: |
| A | Warburg effect | p | Change in gene frequency by chance |
| B | Pasteur effect | q | Postponing severance in the leaves by applying cytokinin |
| C | Emerson effect | $\mathbf{r}$ | Decline in the consumption of respiratory substrate due to a change from anaerobic to aerobic respiration |
| D | Wright effect | s | Inhibitory effect of $\mathrm{O}_2$ on photosynthesis |
| | | t | Enhancement of photosynthesis by subjecting chlorophyll to the effect of two different wavelengths of light |

1 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{s}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{q}\)
2 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{t}, \mathrm{D}=\mathrm{p}\)
3 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{t}, \mathrm{C}=\mathrm{q}, \mathrm{D}=\mathrm{r}\)
4 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{s}\)
Karnataka CET-2008
Evolution

185103 Which of the following defines Hardy Weinberg's law?

1 \(p^{2}+2 p q+q^{2}=1\)
2 \(p^{2}+3 p q+q^{2}=1\)
3 \(\mathrm{P}^{2}+2 \mathrm{pq}+\mathrm{q}^{2}=0\)
4 \(q^{2}+p^{2}+2 p q=0\)
DUMET-2008
Evolution

185106 Frequency of an autosomal lethal gene is 0.4 . The frequency of carrier in a population or 200 individual is:

1 72
2 96
3 104
4 36
VMMC-2006
Evolution

185109 A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele ' \(A\) ' is 0.7 , genotype frequency of ' \(\mathrm{Aa}\) ' is:

1 0.21
2 0.42
3 0.36
4 0.7
AP EAMCET-2003
NEET DIGITAL LIBRARY
Evolution

185095 In a population of 800 rabbits showing HardyWeinberg equilibrium, the frequency of recessive individuals was 0.16 . What is the frequency of heterozygous individuals?

1 0.36
2 0.4
3 0.48
4 0.84
Karnataka CET-20.05.2023
Evolution

185097 Match the phenomenon listed under column I with those listed under column II. Select the correct answer from the options given.
| | Column I | | Column II |
| :---: | :---: | :---: | :---: |
| A | Warburg effect | p | Change in gene frequency by chance |
| B | Pasteur effect | q | Postponing severance in the leaves by applying cytokinin |
| C | Emerson effect | $\mathbf{r}$ | Decline in the consumption of respiratory substrate due to a change from anaerobic to aerobic respiration |
| D | Wright effect | s | Inhibitory effect of $\mathrm{O}_2$ on photosynthesis |
| | | t | Enhancement of photosynthesis by subjecting chlorophyll to the effect of two different wavelengths of light |

1 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{s}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{q}\)
2 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{t}, \mathrm{D}=\mathrm{p}\)
3 \(\mathrm{A}=\mathrm{s}, \mathrm{B}=\mathrm{t}, \mathrm{C}=\mathrm{q}, \mathrm{D}=\mathrm{r}\)
4 \(\mathrm{A}=\mathrm{t}, \mathrm{B}=\mathrm{r}, \mathrm{C}=\mathrm{p}, \mathrm{D}=\mathrm{s}\)
Karnataka CET-2008
Evolution

185103 Which of the following defines Hardy Weinberg's law?

1 \(p^{2}+2 p q+q^{2}=1\)
2 \(p^{2}+3 p q+q^{2}=1\)
3 \(\mathrm{P}^{2}+2 \mathrm{pq}+\mathrm{q}^{2}=0\)
4 \(q^{2}+p^{2}+2 p q=0\)
DUMET-2008
Evolution

185106 Frequency of an autosomal lethal gene is 0.4 . The frequency of carrier in a population or 200 individual is:

1 72
2 96
3 104
4 36
VMMC-2006
Evolution

185109 A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele ' \(A\) ' is 0.7 , genotype frequency of ' \(\mathrm{Aa}\) ' is:

1 0.21
2 0.42
3 0.36
4 0.7
AP EAMCET-2003