QBManager

Molecular Basis of Inheritance and

166450 In the given transcription unit, identify the regions I and II respectively.

1 Promoter and Terminator

2 Rho factor and Sigma factor

3 Terminator and Promoter

4 Operator and Inhibitor

Explanation:

There is the promoter region which is the start site of transcription there is a structural gene. there are two strands. The $5^{} - 3^{}$ is the coding strands and the $3^{} - 5^{}$ is the template strand. The transcripction unit has a promoter on the $5^{}$ end (up steam) of the coding strand and terminator on the $3^{}$ end.

Karnataka CET-2018

Molecular Basis of Inheritance and

166466 Rho factor is associated with

1 RNA polymerase

2 Catalysis process of elongation

3 Initiates the transcription

4 Transcription of r-RNA

Explanation:

Exp. A
Rho factor involved in the termination of transcription
Rho function as an axcillary factor for RNA polymerase
(a) RNA Polymerase- RNA polymerase (green) synthesizes RNA by following a strand of DNA. RNA polymerase is an enzyme that is responsible for copying a DNA sequence into an RNA sequence, during the process of transcription.
(b) Catalysis Process of elongation- Basically, elongation is the stages when the RNA strand get longer, the addition of new nucleotides. During elongation, RNA polymerase "walks" along one strand of DNA, known as template strand, in the $3^{}$ to $5^{}$ direction.
(c) Initiates the transcription- Initiation is the beginning of transcription. It occurs when the enzyme RNA polymerase binds to a region of a gene called the Promoter. This signals the DNA to unwind so the enzyme can "read" the bases in one of DNA strands. The enzyme is now ready to make a strand of mRNA with complementary sequence of bases.
(b) Transcription of r-RNA- The genes for 5S rRNA are located inside the nucleolus and are transcribed into pre $5$ rRNA by RNA polymerase III
Transcribed rRNA is bound to ribosomal proteins to form the subunits of ribosome and acts as the physical structure that pushes mRNA and tRNA through the ribosome to process and translate them.

TS EAMCET-10.08.2021 Shift-I

Molecular Basis of Inheritance and

166483 Removal of RNA polymerase III from nucleoplasm will effect the synthesis of:

1 m-RNA

2 r-RNA

3 t-RNA

4 hn-RNA

AIPMT (Screening)-2012

Molecular Basis of Inheritance and

166484 $Extra close brace or missing open brace$ mRNA $Extra close brace or missing open brace$ protein $[A] P r o p o s e d b y$
The figure gives an important concept in the genetic implication of DNA. Fill the blanks A, B and .

1 A - Francis Crick
B - translation
C - transcription

2 A - Maurice Wilkins
B - transcription

- translation

3 A - James Watson
B - replication

- extension

4 A - Erwin Chargaff
B - translation

-

replication

Explanation:

The expression of the genetic material occur normally through the production of proteins. This involves two consecutive steps. These are transcription and translation.
- The DNA codes for the production of messenger RNA (m RNA) during transcription. Messenger RNA carries coded information to ribosomes. The ribosome's read this information and use it for protein synthesis. This process is called translation.
- F.H.C. crick described this undirectional flow of information in 1958 as the, central dogma of molecular biology.
Central dogma :-
DNA $[A] T r a n s c r i p t i o n$ mRNA $[B] T r a n s l a t i o n$ Pr otein.

NEET (Karnataka)-2013

Molecular Basis of Inheritance and

166487 Given below is a sample of a portion of DNA strand giving the base sequence on the opposite strands. What is so special shown in it ?
5'
GAATTC $3^{}$
3' ........... CTTAAG $5^{}$

1 palindromic sequence of base pairs

2 Replication completed

3 Deletion mutation

4 Start codon at the 5' end

Explanation:

$| 5^{} G A A T T C 3^{'} | | 3^{'} C T T A | A G 5^{'}$
They give rise palindromic secquence of compementary base pairs.
Palindromic sequence means Example.
$Extra close brace or missing open brace$
means if a nucleic acid secquence (DNA or RNA) is read same form $5^{}$ to $3^{}$ one strand and $3^{}$ to $5^{}$ .

AIPMT (Screening)-2011

Molecular Basis of Inheritance and

166450 In the given transcription unit, identify the regions I and II respectively.

1 Promoter and Terminator

2 Rho factor and Sigma factor

3 Terminator and Promoter

4 Operator and Inhibitor

Explanation:

There is the promoter region which is the start site of transcription there is a structural gene. there are two strands. The $5^{} - 3^{}$ is the coding strands and the $3^{} - 5^{}$ is the template strand. The transcripction unit has a promoter on the $5^{}$ end (up steam) of the coding strand and terminator on the $3^{}$ end.

Karnataka CET-2018

Molecular Basis of Inheritance and

166466 Rho factor is associated with

1 RNA polymerase

2 Catalysis process of elongation

3 Initiates the transcription

4 Transcription of r-RNA

Explanation:

Exp. A
Rho factor involved in the termination of transcription
Rho function as an axcillary factor for RNA polymerase
(a) RNA Polymerase- RNA polymerase (green) synthesizes RNA by following a strand of DNA. RNA polymerase is an enzyme that is responsible for copying a DNA sequence into an RNA sequence, during the process of transcription.
(b) Catalysis Process of elongation- Basically, elongation is the stages when the RNA strand get longer, the addition of new nucleotides. During elongation, RNA polymerase "walks" along one strand of DNA, known as template strand, in the $3^{}$ to $5^{}$ direction.
(c) Initiates the transcription- Initiation is the beginning of transcription. It occurs when the enzyme RNA polymerase binds to a region of a gene called the Promoter. This signals the DNA to unwind so the enzyme can "read" the bases in one of DNA strands. The enzyme is now ready to make a strand of mRNA with complementary sequence of bases.
(b) Transcription of r-RNA- The genes for 5S rRNA are located inside the nucleolus and are transcribed into pre $5$ rRNA by RNA polymerase III
Transcribed rRNA is bound to ribosomal proteins to form the subunits of ribosome and acts as the physical structure that pushes mRNA and tRNA through the ribosome to process and translate them.

TS EAMCET-10.08.2021 Shift-I

Molecular Basis of Inheritance and

166483 Removal of RNA polymerase III from nucleoplasm will effect the synthesis of:

1 m-RNA

2 r-RNA

3 t-RNA

4 hn-RNA

AIPMT (Screening)-2012

Molecular Basis of Inheritance and

166484 $Extra close brace or missing open brace$ mRNA $Extra close brace or missing open brace$ protein $[A] P r o p o s e d b y$
The figure gives an important concept in the genetic implication of DNA. Fill the blanks A, B and .

1 A - Francis Crick
B - translation
C - transcription

2 A - Maurice Wilkins
B - transcription

- translation

3 A - James Watson
B - replication

- extension

4 A - Erwin Chargaff
B - translation

-

replication

Explanation:

The expression of the genetic material occur normally through the production of proteins. This involves two consecutive steps. These are transcription and translation.
- The DNA codes for the production of messenger RNA (m RNA) during transcription. Messenger RNA carries coded information to ribosomes. The ribosome's read this information and use it for protein synthesis. This process is called translation.
- F.H.C. crick described this undirectional flow of information in 1958 as the, central dogma of molecular biology.
Central dogma :-
DNA $[A] T r a n s c r i p t i o n$ mRNA $[B] T r a n s l a t i o n$ Pr otein.

NEET (Karnataka)-2013

Molecular Basis of Inheritance and

166487 Given below is a sample of a portion of DNA strand giving the base sequence on the opposite strands. What is so special shown in it ?
5'
GAATTC $3^{}$
3' ........... CTTAAG $5^{}$

1 palindromic sequence of base pairs

2 Replication completed

3 Deletion mutation

4 Start codon at the 5' end

Explanation:

$| 5^{} G A A T T C 3^{'} | | 3^{'} C T T A | A G 5^{'}$
They give rise palindromic secquence of compementary base pairs.
Palindromic sequence means Example.
$Extra close brace or missing open brace$
means if a nucleic acid secquence (DNA or RNA) is read same form $5^{}$ to $3^{}$ one strand and $3^{}$ to $5^{}$ .

AIPMT (Screening)-2011

Molecular Basis of Inheritance and

166450 In the given transcription unit, identify the regions I and II respectively.

1 Promoter and Terminator

2 Rho factor and Sigma factor

3 Terminator and Promoter

4 Operator and Inhibitor

Explanation:

There is the promoter region which is the start site of transcription there is a structural gene. there are two strands. The $5^{} - 3^{}$ is the coding strands and the $3^{} - 5^{}$ is the template strand. The transcripction unit has a promoter on the $5^{}$ end (up steam) of the coding strand and terminator on the $3^{}$ end.

Karnataka CET-2018

Molecular Basis of Inheritance and

166466 Rho factor is associated with

1 RNA polymerase

2 Catalysis process of elongation

3 Initiates the transcription

4 Transcription of r-RNA

Explanation:

Exp. A
Rho factor involved in the termination of transcription
Rho function as an axcillary factor for RNA polymerase
(a) RNA Polymerase- RNA polymerase (green) synthesizes RNA by following a strand of DNA. RNA polymerase is an enzyme that is responsible for copying a DNA sequence into an RNA sequence, during the process of transcription.
(b) Catalysis Process of elongation- Basically, elongation is the stages when the RNA strand get longer, the addition of new nucleotides. During elongation, RNA polymerase "walks" along one strand of DNA, known as template strand, in the $3^{}$ to $5^{}$ direction.
(c) Initiates the transcription- Initiation is the beginning of transcription. It occurs when the enzyme RNA polymerase binds to a region of a gene called the Promoter. This signals the DNA to unwind so the enzyme can "read" the bases in one of DNA strands. The enzyme is now ready to make a strand of mRNA with complementary sequence of bases.
(b) Transcription of r-RNA- The genes for 5S rRNA are located inside the nucleolus and are transcribed into pre $5$ rRNA by RNA polymerase III
Transcribed rRNA is bound to ribosomal proteins to form the subunits of ribosome and acts as the physical structure that pushes mRNA and tRNA through the ribosome to process and translate them.

TS EAMCET-10.08.2021 Shift-I

Molecular Basis of Inheritance and

166483 Removal of RNA polymerase III from nucleoplasm will effect the synthesis of:

1 m-RNA

2 r-RNA

3 t-RNA

4 hn-RNA

AIPMT (Screening)-2012

Molecular Basis of Inheritance and

166484 $Extra close brace or missing open brace$ mRNA $Extra close brace or missing open brace$ protein $[A] P r o p o s e d b y$
The figure gives an important concept in the genetic implication of DNA. Fill the blanks A, B and .

1 A - Francis Crick
B - translation
C - transcription

2 A - Maurice Wilkins
B - transcription

- translation

3 A - James Watson
B - replication

- extension

4 A - Erwin Chargaff
B - translation

-

replication

Explanation:

The expression of the genetic material occur normally through the production of proteins. This involves two consecutive steps. These are transcription and translation.
- The DNA codes for the production of messenger RNA (m RNA) during transcription. Messenger RNA carries coded information to ribosomes. The ribosome's read this information and use it for protein synthesis. This process is called translation.
- F.H.C. crick described this undirectional flow of information in 1958 as the, central dogma of molecular biology.
Central dogma :-
DNA $[A] T r a n s c r i p t i o n$ mRNA $[B] T r a n s l a t i o n$ Pr otein.

NEET (Karnataka)-2013

Molecular Basis of Inheritance and

166487 Given below is a sample of a portion of DNA strand giving the base sequence on the opposite strands. What is so special shown in it ?
5'
GAATTC $3^{}$
3' ........... CTTAAG $5^{}$

1 palindromic sequence of base pairs

2 Replication completed

3 Deletion mutation

4 Start codon at the 5' end

Explanation:

$| 5^{} G A A T T C 3^{'} | | 3^{'} C T T A | A G 5^{'}$
They give rise palindromic secquence of compementary base pairs.
Palindromic sequence means Example.
$Extra close brace or missing open brace$
means if a nucleic acid secquence (DNA or RNA) is read same form $5^{}$ to $3^{}$ one strand and $3^{}$ to $5^{}$ .

AIPMT (Screening)-2011

Molecular Basis of Inheritance and

166450 In the given transcription unit, identify the regions I and II respectively.

1 Promoter and Terminator

2 Rho factor and Sigma factor

3 Terminator and Promoter

4 Operator and Inhibitor

Explanation:

There is the promoter region which is the start site of transcription there is a structural gene. there are two strands. The $5^{} - 3^{}$ is the coding strands and the $3^{} - 5^{}$ is the template strand. The transcripction unit has a promoter on the $5^{}$ end (up steam) of the coding strand and terminator on the $3^{}$ end.

Karnataka CET-2018

Molecular Basis of Inheritance and

166466 Rho factor is associated with

1 RNA polymerase

2 Catalysis process of elongation

3 Initiates the transcription

4 Transcription of r-RNA

Explanation:

Exp. A
Rho factor involved in the termination of transcription
Rho function as an axcillary factor for RNA polymerase
(a) RNA Polymerase- RNA polymerase (green) synthesizes RNA by following a strand of DNA. RNA polymerase is an enzyme that is responsible for copying a DNA sequence into an RNA sequence, during the process of transcription.
(b) Catalysis Process of elongation- Basically, elongation is the stages when the RNA strand get longer, the addition of new nucleotides. During elongation, RNA polymerase "walks" along one strand of DNA, known as template strand, in the $3^{}$ to $5^{}$ direction.
(c) Initiates the transcription- Initiation is the beginning of transcription. It occurs when the enzyme RNA polymerase binds to a region of a gene called the Promoter. This signals the DNA to unwind so the enzyme can "read" the bases in one of DNA strands. The enzyme is now ready to make a strand of mRNA with complementary sequence of bases.
(b) Transcription of r-RNA- The genes for 5S rRNA are located inside the nucleolus and are transcribed into pre $5$ rRNA by RNA polymerase III
Transcribed rRNA is bound to ribosomal proteins to form the subunits of ribosome and acts as the physical structure that pushes mRNA and tRNA through the ribosome to process and translate them.

TS EAMCET-10.08.2021 Shift-I

Molecular Basis of Inheritance and

166483 Removal of RNA polymerase III from nucleoplasm will effect the synthesis of:

1 m-RNA

2 r-RNA

3 t-RNA

4 hn-RNA

AIPMT (Screening)-2012

Molecular Basis of Inheritance and

166484 $Extra close brace or missing open brace$ mRNA $Extra close brace or missing open brace$ protein $[A] P r o p o s e d b y$
The figure gives an important concept in the genetic implication of DNA. Fill the blanks A, B and .

1 A - Francis Crick
B - translation
C - transcription

2 A - Maurice Wilkins
B - transcription

- translation

3 A - James Watson
B - replication

- extension

4 A - Erwin Chargaff
B - translation

-

replication

Explanation:

The expression of the genetic material occur normally through the production of proteins. This involves two consecutive steps. These are transcription and translation.
- The DNA codes for the production of messenger RNA (m RNA) during transcription. Messenger RNA carries coded information to ribosomes. The ribosome's read this information and use it for protein synthesis. This process is called translation.
- F.H.C. crick described this undirectional flow of information in 1958 as the, central dogma of molecular biology.
Central dogma :-
DNA $[A] T r a n s c r i p t i o n$ mRNA $[B] T r a n s l a t i o n$ Pr otein.

NEET (Karnataka)-2013

Molecular Basis of Inheritance and

166487 Given below is a sample of a portion of DNA strand giving the base sequence on the opposite strands. What is so special shown in it ?
5'
GAATTC $3^{}$
3' ........... CTTAAG $5^{}$

1 palindromic sequence of base pairs

2 Replication completed

3 Deletion mutation

4 Start codon at the 5' end

Explanation:

$| 5^{} G A A T T C 3^{'} | | 3^{'} C T T A | A G 5^{'}$
They give rise palindromic secquence of compementary base pairs.
Palindromic sequence means Example.
$Extra close brace or missing open brace$
means if a nucleic acid secquence (DNA or RNA) is read same form $5^{}$ to $3^{}$ one strand and $3^{}$ to $5^{}$ .

AIPMT (Screening)-2011

Molecular Basis of Inheritance and

166450 In the given transcription unit, identify the regions I and II respectively.

1 Promoter and Terminator

2 Rho factor and Sigma factor

3 Terminator and Promoter

4 Operator and Inhibitor

Explanation:

There is the promoter region which is the start site of transcription there is a structural gene. there are two strands. The $5^{} - 3^{}$ is the coding strands and the $3^{} - 5^{}$ is the template strand. The transcripction unit has a promoter on the $5^{}$ end (up steam) of the coding strand and terminator on the $3^{}$ end.

Karnataka CET-2018

Molecular Basis of Inheritance and

166466 Rho factor is associated with

1 RNA polymerase

2 Catalysis process of elongation

3 Initiates the transcription

4 Transcription of r-RNA

Explanation:

Exp. A
Rho factor involved in the termination of transcription
Rho function as an axcillary factor for RNA polymerase
(a) RNA Polymerase- RNA polymerase (green) synthesizes RNA by following a strand of DNA. RNA polymerase is an enzyme that is responsible for copying a DNA sequence into an RNA sequence, during the process of transcription.
(b) Catalysis Process of elongation- Basically, elongation is the stages when the RNA strand get longer, the addition of new nucleotides. During elongation, RNA polymerase "walks" along one strand of DNA, known as template strand, in the $3^{}$ to $5^{}$ direction.
(c) Initiates the transcription- Initiation is the beginning of transcription. It occurs when the enzyme RNA polymerase binds to a region of a gene called the Promoter. This signals the DNA to unwind so the enzyme can "read" the bases in one of DNA strands. The enzyme is now ready to make a strand of mRNA with complementary sequence of bases.
(b) Transcription of r-RNA- The genes for 5S rRNA are located inside the nucleolus and are transcribed into pre $5$ rRNA by RNA polymerase III
Transcribed rRNA is bound to ribosomal proteins to form the subunits of ribosome and acts as the physical structure that pushes mRNA and tRNA through the ribosome to process and translate them.

TS EAMCET-10.08.2021 Shift-I

Molecular Basis of Inheritance and

166483 Removal of RNA polymerase III from nucleoplasm will effect the synthesis of:

1 m-RNA

2 r-RNA

3 t-RNA

4 hn-RNA

AIPMT (Screening)-2012

Molecular Basis of Inheritance and

166484 $Extra close brace or missing open brace$ mRNA $Extra close brace or missing open brace$ protein $[A] P r o p o s e d b y$
The figure gives an important concept in the genetic implication of DNA. Fill the blanks A, B and .

1 A - Francis Crick
B - translation
C - transcription

2 A - Maurice Wilkins
B - transcription

- translation

3 A - James Watson
B - replication

- extension

4 A - Erwin Chargaff
B - translation

-

replication

Explanation:

The expression of the genetic material occur normally through the production of proteins. This involves two consecutive steps. These are transcription and translation.
- The DNA codes for the production of messenger RNA (m RNA) during transcription. Messenger RNA carries coded information to ribosomes. The ribosome's read this information and use it for protein synthesis. This process is called translation.
- F.H.C. crick described this undirectional flow of information in 1958 as the, central dogma of molecular biology.
Central dogma :-
DNA $[A] T r a n s c r i p t i o n$ mRNA $[B] T r a n s l a t i o n$ Pr otein.

NEET (Karnataka)-2013

Molecular Basis of Inheritance and

166487 Given below is a sample of a portion of DNA strand giving the base sequence on the opposite strands. What is so special shown in it ?
5'
GAATTC $3^{}$
3' ........... CTTAAG $5^{}$

1 palindromic sequence of base pairs

2 Replication completed

3 Deletion mutation

4 Start codon at the 5' end

Explanation:

$| 5^{} G A A T T C 3^{'} | | 3^{'} C T T A | A G 5^{'}$
They give rise palindromic secquence of compementary base pairs.
Palindromic sequence means Example.
$Extra close brace or missing open brace$
means if a nucleic acid secquence (DNA or RNA) is read same form $5^{}$ to $3^{}$ one strand and $3^{}$ to $5^{}$ .

AIPMT (Screening)-2011