166388
Restriction enzymes recognize and cleave/cut at specific site of the molecule of
1 DNA
2 carbohydrates
3 fats
4 vitamis.
Explanation:
Restriction enzyme are use and restriction endonuclease enzyme that cleave or cut specific site of the DNA molecule.
AMU-1995
Molecular Basis of Inheritance and
166390
Okazaki fragments form:
1 leading strand
2 lagging strand
3 non sense strand
4 senseful strand
Explanation:
Okazaki fragment are newly synthesized short sequence of DNA which are synthesized discontinuously and later joined together by the enzyme DNA ligase to create the lagging strand during DNA replication.
AIIMS-2000
Molecular Basis of Inheritance and
166393
E. Coli has only \(4.6 \times 10^{6}\) base pairs and completes the process of replication within 18 minutes; then the average rate of polymerisation is approximately
1 1000 base pairs
2 2000** base pairs
3 3000 base pairs
4 4000 base pairs
Explanation:
E. coli takes about 18 minutes to duplicate its genome of \(4.6 \times 10^{6}\) base pairs that means the average rate of polymerization has to be approximately 2000** base pair per second.
NEET-2020 Phase-II
Molecular Basis of Inheritance and
166394
Which is the "Only enzyme" that has "Capability" to catalyse Initiation, Elongation and Termination in the process of transcription in prokaryotes?
1 DNase
2 DNA dependent DNA polymerase
3 DNA dependent RNA polymerase
4 DNA Ligase
Explanation:
DNA dependent RNA polymerase of prokaryotes has the ability to initiate elongate and terminate the process of transcription.
166388
Restriction enzymes recognize and cleave/cut at specific site of the molecule of
1 DNA
2 carbohydrates
3 fats
4 vitamis.
Explanation:
Restriction enzyme are use and restriction endonuclease enzyme that cleave or cut specific site of the DNA molecule.
AMU-1995
Molecular Basis of Inheritance and
166390
Okazaki fragments form:
1 leading strand
2 lagging strand
3 non sense strand
4 senseful strand
Explanation:
Okazaki fragment are newly synthesized short sequence of DNA which are synthesized discontinuously and later joined together by the enzyme DNA ligase to create the lagging strand during DNA replication.
AIIMS-2000
Molecular Basis of Inheritance and
166393
E. Coli has only \(4.6 \times 10^{6}\) base pairs and completes the process of replication within 18 minutes; then the average rate of polymerisation is approximately
1 1000 base pairs
2 2000** base pairs
3 3000 base pairs
4 4000 base pairs
Explanation:
E. coli takes about 18 minutes to duplicate its genome of \(4.6 \times 10^{6}\) base pairs that means the average rate of polymerization has to be approximately 2000** base pair per second.
NEET-2020 Phase-II
Molecular Basis of Inheritance and
166394
Which is the "Only enzyme" that has "Capability" to catalyse Initiation, Elongation and Termination in the process of transcription in prokaryotes?
1 DNase
2 DNA dependent DNA polymerase
3 DNA dependent RNA polymerase
4 DNA Ligase
Explanation:
DNA dependent RNA polymerase of prokaryotes has the ability to initiate elongate and terminate the process of transcription.
166388
Restriction enzymes recognize and cleave/cut at specific site of the molecule of
1 DNA
2 carbohydrates
3 fats
4 vitamis.
Explanation:
Restriction enzyme are use and restriction endonuclease enzyme that cleave or cut specific site of the DNA molecule.
AMU-1995
Molecular Basis of Inheritance and
166390
Okazaki fragments form:
1 leading strand
2 lagging strand
3 non sense strand
4 senseful strand
Explanation:
Okazaki fragment are newly synthesized short sequence of DNA which are synthesized discontinuously and later joined together by the enzyme DNA ligase to create the lagging strand during DNA replication.
AIIMS-2000
Molecular Basis of Inheritance and
166393
E. Coli has only \(4.6 \times 10^{6}\) base pairs and completes the process of replication within 18 minutes; then the average rate of polymerisation is approximately
1 1000 base pairs
2 2000** base pairs
3 3000 base pairs
4 4000 base pairs
Explanation:
E. coli takes about 18 minutes to duplicate its genome of \(4.6 \times 10^{6}\) base pairs that means the average rate of polymerization has to be approximately 2000** base pair per second.
NEET-2020 Phase-II
Molecular Basis of Inheritance and
166394
Which is the "Only enzyme" that has "Capability" to catalyse Initiation, Elongation and Termination in the process of transcription in prokaryotes?
1 DNase
2 DNA dependent DNA polymerase
3 DNA dependent RNA polymerase
4 DNA Ligase
Explanation:
DNA dependent RNA polymerase of prokaryotes has the ability to initiate elongate and terminate the process of transcription.
166388
Restriction enzymes recognize and cleave/cut at specific site of the molecule of
1 DNA
2 carbohydrates
3 fats
4 vitamis.
Explanation:
Restriction enzyme are use and restriction endonuclease enzyme that cleave or cut specific site of the DNA molecule.
AMU-1995
Molecular Basis of Inheritance and
166390
Okazaki fragments form:
1 leading strand
2 lagging strand
3 non sense strand
4 senseful strand
Explanation:
Okazaki fragment are newly synthesized short sequence of DNA which are synthesized discontinuously and later joined together by the enzyme DNA ligase to create the lagging strand during DNA replication.
AIIMS-2000
Molecular Basis of Inheritance and
166393
E. Coli has only \(4.6 \times 10^{6}\) base pairs and completes the process of replication within 18 minutes; then the average rate of polymerisation is approximately
1 1000 base pairs
2 2000** base pairs
3 3000 base pairs
4 4000 base pairs
Explanation:
E. coli takes about 18 minutes to duplicate its genome of \(4.6 \times 10^{6}\) base pairs that means the average rate of polymerization has to be approximately 2000** base pair per second.
NEET-2020 Phase-II
Molecular Basis of Inheritance and
166394
Which is the "Only enzyme" that has "Capability" to catalyse Initiation, Elongation and Termination in the process of transcription in prokaryotes?
1 DNase
2 DNA dependent DNA polymerase
3 DNA dependent RNA polymerase
4 DNA Ligase
Explanation:
DNA dependent RNA polymerase of prokaryotes has the ability to initiate elongate and terminate the process of transcription.
