QBManager

Molecular Basis of Inheritance and

166371 Match the entries in Column I with those of Column II and choose the correct answer.

Column - I	Column - II
----------	------------
(A) Restriction endonucleases	(R) Arber
(B) Polymerase chain reaction	(S) Karry Mullis
(C) DNA fingerprinting	(Q) Alec Jeffreys
(D) Monoclonal antibodies	(P) Kohler Milstein

1 A - (R) B - (S) C - (Q) D - (P)

2 A - (R) B - (Q) C - (S) D - (P)

3 A - (Q) B - (R) C - (S) D - (P)

4 A - (Q) B - (S) C - (R) D - (Q)

Karnataka CET-2013

Molecular Basis of Inheritance and

166387 Math list-I and list-II and select the correct answer using the code

S. No.	List - I (Enzyme)	List - II (Enzyme Function)
------------	-------------------------------	----------------------------------------------------------
1.	Ligase	Joins segments of DNA together
2.	DNA Polymerase	Synthesizes new DNA strands by adding nucleotides
3.	Helicase	Breaks the hydrogen bonds between complementary pairs during DNA replication

1 1,2 and 3 are correct

2 1 and 2 are correct

3 1,2 and 4 are correct

4 1 and 3 are correct

BHU PMT (Mains)-2006

Molecular Basis of Inheritance and

166428 Match the following lists:
Here’s your table, properly formatted for clarity:

	List - I		List - II
---	-----------------------------------------------	---	-------------------------------
A)	E. coli has	I)	\(\mathbf{6.6 \times 10^{9} \, \text{bp}}\)
B)	Diploid human cell has	II)	\(3^{\prime}-5^{\prime}\) polarity
C)	DNA dependent RNA polymerase catalyzes in	III)	\(4.6 \times 10^{6} \, \text{bp}\)
D)	The continuous replication is with	IV)	\(5^{\prime}-3^{\prime}-\) direction

The correct match is :

1 A - III B - I C - IV D - II

2 A - III B - IV C - II D - I

3 A - II B - III C - IV D - I

4 A - I B - III C - II D - IV

List-I	List-II
-------	--------
(A) E-coli has	4.6 × 10^6 bp
(B) Diploid human cell has	6–6 × 10^9 bp
(C) DNA dependent RNA polymerase catalyzes in	5'– 3' direction
(D) The continuous Replication occurs with	3'– 5' polarity

TS EAMCET-31.07.2022 Shift-I

Molecular Basis of Inheritance and

166441 Match the following lists:

List-I	List-II	List-III
------------------------------------	------------------------------	---------------------------------------------
(A) Template strand	(i) Before structural gene	(I) DNA replication semi-conservative mode
(B) Location of promoter	(ii) Faba beans	(II) DNA with 3'-5' polarity
(C) Okazaki fragments	(iii) Transcriptase	(III) \(5^{}\) end of coding strand
(D) Taylor experiments	(iv) \(5^{}-3^{}\) polarity	(IV) DNA ligase

1 A - ii, II B - i, III C - iii, IV D - iv, I

2 A - iii, II B - i, III C - iv, IV D - ii, I

3 A - iii, III B - ii, IV C - i, I D - iv, II

4 A - iv, II B - ii, IV C - i, III D - iii, I

List - I	List - II	List - III
----------------------------------	-----------------------------------	----------------------------------------
Template strand	Transcriptase	DNA with 3'-5' Polarity
Location of promoter	Before structural Gene	5' end of coding strand
Okazaki fragment	5' - 3' polarity	DNA ligase
Taylor experiment	Faba beans	DNA replication semiconservative mode.

TS EAMCET-29.09.2020 Shift-I

Molecular Basis of Inheritance and

166371 Match the entries in Column I with those of Column II and choose the correct answer.

Column - I	Column - II
----------	------------
(A) Restriction endonucleases	(R) Arber
(B) Polymerase chain reaction	(S) Karry Mullis
(C) DNA fingerprinting	(Q) Alec Jeffreys
(D) Monoclonal antibodies	(P) Kohler Milstein

1 A - (R) B - (S) C - (Q) D - (P)

2 A - (R) B - (Q) C - (S) D - (P)

3 A - (Q) B - (R) C - (S) D - (P)

4 A - (Q) B - (S) C - (R) D - (Q)

Karnataka CET-2013

Molecular Basis of Inheritance and

166387 Math list-I and list-II and select the correct answer using the code

S. No.	List - I (Enzyme)	List - II (Enzyme Function)
------------	-------------------------------	----------------------------------------------------------
1.	Ligase	Joins segments of DNA together
2.	DNA Polymerase	Synthesizes new DNA strands by adding nucleotides
3.	Helicase	Breaks the hydrogen bonds between complementary pairs during DNA replication

1 1,2 and 3 are correct

2 1 and 2 are correct

3 1,2 and 4 are correct

4 1 and 3 are correct

BHU PMT (Mains)-2006

Molecular Basis of Inheritance and

166428 Match the following lists:
Here’s your table, properly formatted for clarity:

	List - I		List - II
---	-----------------------------------------------	---	-------------------------------
A)	E. coli has	I)	\(\mathbf{6.6 \times 10^{9} \, \text{bp}}\)
B)	Diploid human cell has	II)	\(3^{\prime}-5^{\prime}\) polarity
C)	DNA dependent RNA polymerase catalyzes in	III)	\(4.6 \times 10^{6} \, \text{bp}\)
D)	The continuous replication is with	IV)	\(5^{\prime}-3^{\prime}-\) direction

The correct match is :

1 A - III B - I C - IV D - II

2 A - III B - IV C - II D - I

3 A - II B - III C - IV D - I

4 A - I B - III C - II D - IV

List-I	List-II
-------	--------
(A) E-coli has	4.6 × 10^6 bp
(B) Diploid human cell has	6–6 × 10^9 bp
(C) DNA dependent RNA polymerase catalyzes in	5'– 3' direction
(D) The continuous Replication occurs with	3'– 5' polarity

TS EAMCET-31.07.2022 Shift-I

Molecular Basis of Inheritance and

166441 Match the following lists:

List-I	List-II	List-III
------------------------------------	------------------------------	---------------------------------------------
(A) Template strand	(i) Before structural gene	(I) DNA replication semi-conservative mode
(B) Location of promoter	(ii) Faba beans	(II) DNA with 3'-5' polarity
(C) Okazaki fragments	(iii) Transcriptase	(III) \(5^{}\) end of coding strand
(D) Taylor experiments	(iv) \(5^{}-3^{}\) polarity	(IV) DNA ligase

1 A - ii, II B - i, III C - iii, IV D - iv, I

2 A - iii, II B - i, III C - iv, IV D - ii, I

3 A - iii, III B - ii, IV C - i, I D - iv, II

4 A - iv, II B - ii, IV C - i, III D - iii, I

List - I	List - II	List - III
----------------------------------	-----------------------------------	----------------------------------------
Template strand	Transcriptase	DNA with 3'-5' Polarity
Location of promoter	Before structural Gene	5' end of coding strand
Okazaki fragment	5' - 3' polarity	DNA ligase
Taylor experiment	Faba beans	DNA replication semiconservative mode.

TS EAMCET-29.09.2020 Shift-I

Molecular Basis of Inheritance and

166371 Match the entries in Column I with those of Column II and choose the correct answer.

Column - I	Column - II
----------	------------
(A) Restriction endonucleases	(R) Arber
(B) Polymerase chain reaction	(S) Karry Mullis
(C) DNA fingerprinting	(Q) Alec Jeffreys
(D) Monoclonal antibodies	(P) Kohler Milstein

1 A - (R) B - (S) C - (Q) D - (P)

2 A - (R) B - (Q) C - (S) D - (P)

3 A - (Q) B - (R) C - (S) D - (P)

4 A - (Q) B - (S) C - (R) D - (Q)

Karnataka CET-2013

Molecular Basis of Inheritance and

166387 Math list-I and list-II and select the correct answer using the code

S. No.	List - I (Enzyme)	List - II (Enzyme Function)
------------	-------------------------------	----------------------------------------------------------
1.	Ligase	Joins segments of DNA together
2.	DNA Polymerase	Synthesizes new DNA strands by adding nucleotides
3.	Helicase	Breaks the hydrogen bonds between complementary pairs during DNA replication

1 1,2 and 3 are correct

2 1 and 2 are correct

3 1,2 and 4 are correct

4 1 and 3 are correct

BHU PMT (Mains)-2006

Molecular Basis of Inheritance and

166428 Match the following lists:
Here’s your table, properly formatted for clarity:

	List - I		List - II
---	-----------------------------------------------	---	-------------------------------
A)	E. coli has	I)	\(\mathbf{6.6 \times 10^{9} \, \text{bp}}\)
B)	Diploid human cell has	II)	\(3^{\prime}-5^{\prime}\) polarity
C)	DNA dependent RNA polymerase catalyzes in	III)	\(4.6 \times 10^{6} \, \text{bp}\)
D)	The continuous replication is with	IV)	\(5^{\prime}-3^{\prime}-\) direction

The correct match is :

1 A - III B - I C - IV D - II

2 A - III B - IV C - II D - I

3 A - II B - III C - IV D - I

4 A - I B - III C - II D - IV

List-I	List-II
-------	--------
(A) E-coli has	4.6 × 10^6 bp
(B) Diploid human cell has	6–6 × 10^9 bp
(C) DNA dependent RNA polymerase catalyzes in	5'– 3' direction
(D) The continuous Replication occurs with	3'– 5' polarity

TS EAMCET-31.07.2022 Shift-I

Molecular Basis of Inheritance and

166441 Match the following lists:

List-I	List-II	List-III
------------------------------------	------------------------------	---------------------------------------------
(A) Template strand	(i) Before structural gene	(I) DNA replication semi-conservative mode
(B) Location of promoter	(ii) Faba beans	(II) DNA with 3'-5' polarity
(C) Okazaki fragments	(iii) Transcriptase	(III) \(5^{}\) end of coding strand
(D) Taylor experiments	(iv) \(5^{}-3^{}\) polarity	(IV) DNA ligase

1 A - ii, II B - i, III C - iii, IV D - iv, I

2 A - iii, II B - i, III C - iv, IV D - ii, I

3 A - iii, III B - ii, IV C - i, I D - iv, II

4 A - iv, II B - ii, IV C - i, III D - iii, I

List - I	List - II	List - III
----------------------------------	-----------------------------------	----------------------------------------
Template strand	Transcriptase	DNA with 3'-5' Polarity
Location of promoter	Before structural Gene	5' end of coding strand
Okazaki fragment	5' - 3' polarity	DNA ligase
Taylor experiment	Faba beans	DNA replication semiconservative mode.

TS EAMCET-29.09.2020 Shift-I

Molecular Basis of Inheritance and

166371 Match the entries in Column I with those of Column II and choose the correct answer.

Column - I	Column - II
----------	------------
(A) Restriction endonucleases	(R) Arber
(B) Polymerase chain reaction	(S) Karry Mullis
(C) DNA fingerprinting	(Q) Alec Jeffreys
(D) Monoclonal antibodies	(P) Kohler Milstein

1 A - (R) B - (S) C - (Q) D - (P)

2 A - (R) B - (Q) C - (S) D - (P)

3 A - (Q) B - (R) C - (S) D - (P)

4 A - (Q) B - (S) C - (R) D - (Q)

Karnataka CET-2013

Molecular Basis of Inheritance and

166387 Math list-I and list-II and select the correct answer using the code

S. No.	List - I (Enzyme)	List - II (Enzyme Function)
------------	-------------------------------	----------------------------------------------------------
1.	Ligase	Joins segments of DNA together
2.	DNA Polymerase	Synthesizes new DNA strands by adding nucleotides
3.	Helicase	Breaks the hydrogen bonds between complementary pairs during DNA replication

1 1,2 and 3 are correct

2 1 and 2 are correct

3 1,2 and 4 are correct

4 1 and 3 are correct

BHU PMT (Mains)-2006

Molecular Basis of Inheritance and

166428 Match the following lists:
Here’s your table, properly formatted for clarity:

	List - I		List - II
---	-----------------------------------------------	---	-------------------------------
A)	E. coli has	I)	\(\mathbf{6.6 \times 10^{9} \, \text{bp}}\)
B)	Diploid human cell has	II)	\(3^{\prime}-5^{\prime}\) polarity
C)	DNA dependent RNA polymerase catalyzes in	III)	\(4.6 \times 10^{6} \, \text{bp}\)
D)	The continuous replication is with	IV)	\(5^{\prime}-3^{\prime}-\) direction

The correct match is :

1 A - III B - I C - IV D - II

2 A - III B - IV C - II D - I

3 A - II B - III C - IV D - I

4 A - I B - III C - II D - IV

List-I	List-II
-------	--------
(A) E-coli has	4.6 × 10^6 bp
(B) Diploid human cell has	6–6 × 10^9 bp
(C) DNA dependent RNA polymerase catalyzes in	5'– 3' direction
(D) The continuous Replication occurs with	3'– 5' polarity

TS EAMCET-31.07.2022 Shift-I

Molecular Basis of Inheritance and

166441 Match the following lists:

List-I	List-II	List-III
------------------------------------	------------------------------	---------------------------------------------
(A) Template strand	(i) Before structural gene	(I) DNA replication semi-conservative mode
(B) Location of promoter	(ii) Faba beans	(II) DNA with 3'-5' polarity
(C) Okazaki fragments	(iii) Transcriptase	(III) \(5^{}\) end of coding strand
(D) Taylor experiments	(iv) \(5^{}-3^{}\) polarity	(IV) DNA ligase

1 A - ii, II B - i, III C - iii, IV D - iv, I

2 A - iii, II B - i, III C - iv, IV D - ii, I

3 A - iii, III B - ii, IV C - i, I D - iv, II

4 A - iv, II B - ii, IV C - i, III D - iii, I

List - I	List - II	List - III
----------------------------------	-----------------------------------	----------------------------------------
Template strand	Transcriptase	DNA with 3'-5' Polarity
Location of promoter	Before structural Gene	5' end of coding strand
Okazaki fragment	5' - 3' polarity	DNA ligase
Taylor experiment	Faba beans	DNA replication semiconservative mode.

TS EAMCET-29.09.2020 Shift-I

Question Bank Series

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