01. Inheritance of One Gene 1. Law of Dominance 2. Law of Segregation
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Principle of Inheritance and Variation

184406 A cross between two tall garden pea plants produced all tall plants. The possible genotypes of the parents are
(I) TT, TT
(II) TT, Tt
(III) \(\mathbf{T t}, \mathbf{t t}\)
(IV) Tt, Tt

1 (II), (III)
2 (III), (IV)
3 (I), (IV)
4 (I) , (II)
AP EAMCET-2014
Principle of Inheritance and Variation

184407 The genotype of a husband and wife are \(A B \&\) AO. Among the blood of their children, how many different genotypes \& phenotypes are possible?

1 3 genotypes; 3 phenotypes
2 4 genotypes; 3 phenotypes
3 4 phenotypes; 3 genotypes
4 4 phenotypes; 4 genotypes
Karnataka CET-2021
Principle of Inheritance and Variation

184411 Match the following lists:
| | List- I | | List-II |
| :--- | :--- | :--- | :--- |
| (A) | Back cross | (I) | It the genetic make up of an individual. |
| (B) | Test cross | (II) | An individual is having two different alleles for a single character. Consequently it will produce two different types of gametes with reference to a gene. |
| (C) | Heterozygote | (III) | An individual is having two similar or identical alleles for a single character. Hence, it will produce only one kind of gametes with reference to a gene. |
| (D) | Homozygote | (IV) | If the F progeny are mated back to one of their parents. |
| | | (V) | The cross between F progeny (or heterozygotes) and their recessive homozygous parent. | |

1 A - IV, B - V, C - I, D - II
2 A - V, B - III, C - I, D - II
3 A - V, B - IV, C - II, D - I
4 A - IV, B - V, C - II, D - III
TS EAMCET-08.05.2019 Shift-II
Principle of Inheritance and Variation

184413 If a gene has four alleles, number of expected genotypes is
1. Law of Dominance

1 6
2 10
3 12
4 20
TS EAMCET-29.09.2020 Shift-I
NEET DIGITAL LIBRARY
Principle of Inheritance and Variation

184406 A cross between two tall garden pea plants produced all tall plants. The possible genotypes of the parents are
(I) TT, TT
(II) TT, Tt
(III) \(\mathbf{T t}, \mathbf{t t}\)
(IV) Tt, Tt

1 (II), (III)
2 (III), (IV)
3 (I), (IV)
4 (I) , (II)
AP EAMCET-2014
Principle of Inheritance and Variation

184407 The genotype of a husband and wife are \(A B \&\) AO. Among the blood of their children, how many different genotypes \& phenotypes are possible?

1 3 genotypes; 3 phenotypes
2 4 genotypes; 3 phenotypes
3 4 phenotypes; 3 genotypes
4 4 phenotypes; 4 genotypes
Karnataka CET-2021
Principle of Inheritance and Variation

184411 Match the following lists:
| | List- I | | List-II |
| :--- | :--- | :--- | :--- |
| (A) | Back cross | (I) | It the genetic make up of an individual. |
| (B) | Test cross | (II) | An individual is having two different alleles for a single character. Consequently it will produce two different types of gametes with reference to a gene. |
| (C) | Heterozygote | (III) | An individual is having two similar or identical alleles for a single character. Hence, it will produce only one kind of gametes with reference to a gene. |
| (D) | Homozygote | (IV) | If the F progeny are mated back to one of their parents. |
| | | (V) | The cross between F progeny (or heterozygotes) and their recessive homozygous parent. | |

1 A - IV, B - V, C - I, D - II
2 A - V, B - III, C - I, D - II
3 A - V, B - IV, C - II, D - I
4 A - IV, B - V, C - II, D - III
TS EAMCET-08.05.2019 Shift-II
Principle of Inheritance and Variation

184413 If a gene has four alleles, number of expected genotypes is
1. Law of Dominance

1 6
2 10
3 12
4 20
TS EAMCET-29.09.2020 Shift-I
Join With Us for More Updates
Principle of Inheritance and Variation

184406 A cross between two tall garden pea plants produced all tall plants. The possible genotypes of the parents are
(I) TT, TT
(II) TT, Tt
(III) \(\mathbf{T t}, \mathbf{t t}\)
(IV) Tt, Tt

1 (II), (III)
2 (III), (IV)
3 (I), (IV)
4 (I) , (II)
AP EAMCET-2014
Principle of Inheritance and Variation

184407 The genotype of a husband and wife are \(A B \&\) AO. Among the blood of their children, how many different genotypes \& phenotypes are possible?

1 3 genotypes; 3 phenotypes
2 4 genotypes; 3 phenotypes
3 4 phenotypes; 3 genotypes
4 4 phenotypes; 4 genotypes
Karnataka CET-2021
Principle of Inheritance and Variation

184411 Match the following lists:
| | List- I | | List-II |
| :--- | :--- | :--- | :--- |
| (A) | Back cross | (I) | It the genetic make up of an individual. |
| (B) | Test cross | (II) | An individual is having two different alleles for a single character. Consequently it will produce two different types of gametes with reference to a gene. |
| (C) | Heterozygote | (III) | An individual is having two similar or identical alleles for a single character. Hence, it will produce only one kind of gametes with reference to a gene. |
| (D) | Homozygote | (IV) | If the F progeny are mated back to one of their parents. |
| | | (V) | The cross between F progeny (or heterozygotes) and their recessive homozygous parent. | |

1 A - IV, B - V, C - I, D - II
2 A - V, B - III, C - I, D - II
3 A - V, B - IV, C - II, D - I
4 A - IV, B - V, C - II, D - III
TS EAMCET-08.05.2019 Shift-II
Principle of Inheritance and Variation

184413 If a gene has four alleles, number of expected genotypes is
1. Law of Dominance

1 6
2 10
3 12
4 20
TS EAMCET-29.09.2020 Shift-I
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Principle of Inheritance and Variation

184406 A cross between two tall garden pea plants produced all tall plants. The possible genotypes of the parents are
(I) TT, TT
(II) TT, Tt
(III) \(\mathbf{T t}, \mathbf{t t}\)
(IV) Tt, Tt

1 (II), (III)
2 (III), (IV)
3 (I), (IV)
4 (I) , (II)
AP EAMCET-2014
Principle of Inheritance and Variation

184407 The genotype of a husband and wife are \(A B \&\) AO. Among the blood of their children, how many different genotypes \& phenotypes are possible?

1 3 genotypes; 3 phenotypes
2 4 genotypes; 3 phenotypes
3 4 phenotypes; 3 genotypes
4 4 phenotypes; 4 genotypes
Karnataka CET-2021
Principle of Inheritance and Variation

184411 Match the following lists:
| | List- I | | List-II |
| :--- | :--- | :--- | :--- |
| (A) | Back cross | (I) | It the genetic make up of an individual. |
| (B) | Test cross | (II) | An individual is having two different alleles for a single character. Consequently it will produce two different types of gametes with reference to a gene. |
| (C) | Heterozygote | (III) | An individual is having two similar or identical alleles for a single character. Hence, it will produce only one kind of gametes with reference to a gene. |
| (D) | Homozygote | (IV) | If the F progeny are mated back to one of their parents. |
| | | (V) | The cross between F progeny (or heterozygotes) and their recessive homozygous parent. | |

1 A - IV, B - V, C - I, D - II
2 A - V, B - III, C - I, D - II
3 A - V, B - IV, C - II, D - I
4 A - IV, B - V, C - II, D - III
TS EAMCET-08.05.2019 Shift-II
Principle of Inheritance and Variation

184413 If a gene has four alleles, number of expected genotypes is
1. Law of Dominance

1 6
2 10
3 12
4 20
TS EAMCET-29.09.2020 Shift-I
NEET DIGITAL LIBRARY