2 In domesticated fowls, sex of progeny depends on the type of sperm rather than egg
3 Human males have one of their sexchromosome much shorter than other
4 In male grasshoppers, \(50 \%\) of sperms have no sex chromosome
Explanation:
In case of Domesticated fowls, males are homogametic (zz), \(\mathrm{O}\) are heterogametic (zw) thus it is the ovum which determines the sex of progeny. {|c|c|c|} | | {c}{\(\)} | |---|---| | \(\) | \(\) | |\(\) | \(\) | \(\) | |\(\) | \(\) | \(\) | |
AP EAMCET-03.09.2021 Shift-II
Principle of Inheritance and Variation
184401
\(F_{2}\) generation in a Mendelian cross showed that both genotypic and phenotypic ratio are same as \(1: 2: 1\). It represents a case of:
1 Monohybrid cross with complete dominance
2 Monohybrid cross with incomplete dominance
3 Co-dominance
4 Dihybrid cross
Explanation:
Monohybrid cross with incomplete dominance shows both genotypic and phenotypic ratio as \(1: 2: 1\). The inheritance of flower colour in the dog flower (snapdragon) is a good example which shows incomplete dominance. - Here genotype ratio were \(1: 2: 1\) as in any Mendelian monohybrid cross, but the phenotype ratio had changed from \(3: 1\) dominant recessive ratio to \(1: 2: 1\).
AIPMT (Screening)-2012
Principle of Inheritance and Variation
184404
In sweet peas, genes \(C\) and \(P\) are necessary for colour in flowers. The flowers are white in the absence of either or both the genes. What will be the percentage of coloured flowers in the offspring of the cross Ccpp \(\times \mathbf{c c P p}\) ?
1 \(75 \%\)
2 \(25 \%\)
3 \(100 \%\)
4 \(50 \%\)
Explanation:
When Ccpp \(\times\) ccPp is crossed together, the percentage of coloured flowers in the offspring is \(25 \%\). The phenotypic ratio is \(=3: 1\) is \(75 \%\) white flower \& \(25 \%\) coloured flowers are formed.
AIIMS-1997
Principle of Inheritance and Variation
184408
A self-fertilizing trihybrid plant forms :-
1 4 different gametes and 16 different zygotes
2 8 different gametes and 16 different zygotes
3 8 different gametes and 32 different zygotes
4 8 different gametes and 64 different zygotes
Explanation:
The Genotype of trihybrid would be AaBbCc. Number of gametes \(=(\text { no. of genes studied })^{\mathrm{n}}\), where \(\mathrm{n}=\) number of heterozygous alleles thus number of gametes \(=(2)^{3}=8\) No. of zygotes \(=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^{6}=64\)
2 In domesticated fowls, sex of progeny depends on the type of sperm rather than egg
3 Human males have one of their sexchromosome much shorter than other
4 In male grasshoppers, \(50 \%\) of sperms have no sex chromosome
Explanation:
In case of Domesticated fowls, males are homogametic (zz), \(\mathrm{O}\) are heterogametic (zw) thus it is the ovum which determines the sex of progeny. {|c|c|c|} | | {c}{\(\)} | |---|---| | \(\) | \(\) | |\(\) | \(\) | \(\) | |\(\) | \(\) | \(\) | |
AP EAMCET-03.09.2021 Shift-II
Principle of Inheritance and Variation
184401
\(F_{2}\) generation in a Mendelian cross showed that both genotypic and phenotypic ratio are same as \(1: 2: 1\). It represents a case of:
1 Monohybrid cross with complete dominance
2 Monohybrid cross with incomplete dominance
3 Co-dominance
4 Dihybrid cross
Explanation:
Monohybrid cross with incomplete dominance shows both genotypic and phenotypic ratio as \(1: 2: 1\). The inheritance of flower colour in the dog flower (snapdragon) is a good example which shows incomplete dominance. - Here genotype ratio were \(1: 2: 1\) as in any Mendelian monohybrid cross, but the phenotype ratio had changed from \(3: 1\) dominant recessive ratio to \(1: 2: 1\).
AIPMT (Screening)-2012
Principle of Inheritance and Variation
184404
In sweet peas, genes \(C\) and \(P\) are necessary for colour in flowers. The flowers are white in the absence of either or both the genes. What will be the percentage of coloured flowers in the offspring of the cross Ccpp \(\times \mathbf{c c P p}\) ?
1 \(75 \%\)
2 \(25 \%\)
3 \(100 \%\)
4 \(50 \%\)
Explanation:
When Ccpp \(\times\) ccPp is crossed together, the percentage of coloured flowers in the offspring is \(25 \%\). The phenotypic ratio is \(=3: 1\) is \(75 \%\) white flower \& \(25 \%\) coloured flowers are formed.
AIIMS-1997
Principle of Inheritance and Variation
184408
A self-fertilizing trihybrid plant forms :-
1 4 different gametes and 16 different zygotes
2 8 different gametes and 16 different zygotes
3 8 different gametes and 32 different zygotes
4 8 different gametes and 64 different zygotes
Explanation:
The Genotype of trihybrid would be AaBbCc. Number of gametes \(=(\text { no. of genes studied })^{\mathrm{n}}\), where \(\mathrm{n}=\) number of heterozygous alleles thus number of gametes \(=(2)^{3}=8\) No. of zygotes \(=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^{6}=64\)
2 In domesticated fowls, sex of progeny depends on the type of sperm rather than egg
3 Human males have one of their sexchromosome much shorter than other
4 In male grasshoppers, \(50 \%\) of sperms have no sex chromosome
Explanation:
In case of Domesticated fowls, males are homogametic (zz), \(\mathrm{O}\) are heterogametic (zw) thus it is the ovum which determines the sex of progeny. {|c|c|c|} | | {c}{\(\)} | |---|---| | \(\) | \(\) | |\(\) | \(\) | \(\) | |\(\) | \(\) | \(\) | |
AP EAMCET-03.09.2021 Shift-II
Principle of Inheritance and Variation
184401
\(F_{2}\) generation in a Mendelian cross showed that both genotypic and phenotypic ratio are same as \(1: 2: 1\). It represents a case of:
1 Monohybrid cross with complete dominance
2 Monohybrid cross with incomplete dominance
3 Co-dominance
4 Dihybrid cross
Explanation:
Monohybrid cross with incomplete dominance shows both genotypic and phenotypic ratio as \(1: 2: 1\). The inheritance of flower colour in the dog flower (snapdragon) is a good example which shows incomplete dominance. - Here genotype ratio were \(1: 2: 1\) as in any Mendelian monohybrid cross, but the phenotype ratio had changed from \(3: 1\) dominant recessive ratio to \(1: 2: 1\).
AIPMT (Screening)-2012
Principle of Inheritance and Variation
184404
In sweet peas, genes \(C\) and \(P\) are necessary for colour in flowers. The flowers are white in the absence of either or both the genes. What will be the percentage of coloured flowers in the offspring of the cross Ccpp \(\times \mathbf{c c P p}\) ?
1 \(75 \%\)
2 \(25 \%\)
3 \(100 \%\)
4 \(50 \%\)
Explanation:
When Ccpp \(\times\) ccPp is crossed together, the percentage of coloured flowers in the offspring is \(25 \%\). The phenotypic ratio is \(=3: 1\) is \(75 \%\) white flower \& \(25 \%\) coloured flowers are formed.
AIIMS-1997
Principle of Inheritance and Variation
184408
A self-fertilizing trihybrid plant forms :-
1 4 different gametes and 16 different zygotes
2 8 different gametes and 16 different zygotes
3 8 different gametes and 32 different zygotes
4 8 different gametes and 64 different zygotes
Explanation:
The Genotype of trihybrid would be AaBbCc. Number of gametes \(=(\text { no. of genes studied })^{\mathrm{n}}\), where \(\mathrm{n}=\) number of heterozygous alleles thus number of gametes \(=(2)^{3}=8\) No. of zygotes \(=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^{6}=64\)
2 In domesticated fowls, sex of progeny depends on the type of sperm rather than egg
3 Human males have one of their sexchromosome much shorter than other
4 In male grasshoppers, \(50 \%\) of sperms have no sex chromosome
Explanation:
In case of Domesticated fowls, males are homogametic (zz), \(\mathrm{O}\) are heterogametic (zw) thus it is the ovum which determines the sex of progeny. {|c|c|c|} | | {c}{\(\)} | |---|---| | \(\) | \(\) | |\(\) | \(\) | \(\) | |\(\) | \(\) | \(\) | |
AP EAMCET-03.09.2021 Shift-II
Principle of Inheritance and Variation
184401
\(F_{2}\) generation in a Mendelian cross showed that both genotypic and phenotypic ratio are same as \(1: 2: 1\). It represents a case of:
1 Monohybrid cross with complete dominance
2 Monohybrid cross with incomplete dominance
3 Co-dominance
4 Dihybrid cross
Explanation:
Monohybrid cross with incomplete dominance shows both genotypic and phenotypic ratio as \(1: 2: 1\). The inheritance of flower colour in the dog flower (snapdragon) is a good example which shows incomplete dominance. - Here genotype ratio were \(1: 2: 1\) as in any Mendelian monohybrid cross, but the phenotype ratio had changed from \(3: 1\) dominant recessive ratio to \(1: 2: 1\).
AIPMT (Screening)-2012
Principle of Inheritance and Variation
184404
In sweet peas, genes \(C\) and \(P\) are necessary for colour in flowers. The flowers are white in the absence of either or both the genes. What will be the percentage of coloured flowers in the offspring of the cross Ccpp \(\times \mathbf{c c P p}\) ?
1 \(75 \%\)
2 \(25 \%\)
3 \(100 \%\)
4 \(50 \%\)
Explanation:
When Ccpp \(\times\) ccPp is crossed together, the percentage of coloured flowers in the offspring is \(25 \%\). The phenotypic ratio is \(=3: 1\) is \(75 \%\) white flower \& \(25 \%\) coloured flowers are formed.
AIIMS-1997
Principle of Inheritance and Variation
184408
A self-fertilizing trihybrid plant forms :-
1 4 different gametes and 16 different zygotes
2 8 different gametes and 16 different zygotes
3 8 different gametes and 32 different zygotes
4 8 different gametes and 64 different zygotes
Explanation:
The Genotype of trihybrid would be AaBbCc. Number of gametes \(=(\text { no. of genes studied })^{\mathrm{n}}\), where \(\mathrm{n}=\) number of heterozygous alleles thus number of gametes \(=(2)^{3}=8\) No. of zygotes \(=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^{6}=64\)
