NEET Test Series from KOTA - 10 Papers In MS WORD
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LAWS OF MOTION (ADDITIONAL)
372217
Diwali rocket is ejecting \(50 \mathrm{~g}\) of gases/s at a velocity of \(400 \mathrm{~m} / \mathrm{s}\). The acceleration force on the rocket will be
1 22 dyne
2 \(20 \mathrm{~N}\)
3 20 dyne
4 \(100 \mathrm{~N}\)
Explanation:
B Given, Mass of ejecting gases \((\Delta \mathrm{m})=50 \mathrm{~g}=50 \times 10^{-3} \mathrm{~kg}\), velocity \((\mathrm{v})=400 \mathrm{~m} / \mathrm{s}\) The accelerating force \(=\) upward thrust \(=\frac{\Delta \mathrm{m}}{\Delta \mathrm{t}} \cdot \mathrm{v}\) \(=\frac{50 \times 10^{-3}}{1} \times 400=20 \mathrm{~N}\) (g) \\ Motion of Body Connected Together