Friction, and Inclined Plane Friction Motion
LAWS OF MOTION (ADDITIONAL)

372137 If coefficient of static friction is \(\mu_{\mathrm{s}}\) and coefficient of kinetic friction is \(\mu_{\mathrm{k}}\), which is correct?

1 \(\mu_{\mathrm{s}}=\mu_{\mathrm{k}}\)
2 \(\mu_{\mathrm{s}}>\mu_{\mathrm{k}}\)
3 \(\mu_{\mathrm{s}} \lt \mu_{\mathrm{k}}\)
4 Cannot predict
LAWS OF MOTION (ADDITIONAL)

372138 The coefficient of friction between the tyres and the road is 0.25 . The maximum speed with which car can be driven round a curve of radius \(40 \mathrm{~m}\) without skidding is (assume \(\mathrm{g}=10\) \(\mathbf{m s}^{-2}\) )

1 \(40 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}\)
3 \(15 \mathrm{~ms}^{-1}\)
4 \(10 \mathrm{~ms}^{-1}\)
LAWS OF MOTION (ADDITIONAL)

372139 A block rests on a rough horizontal surface, \(\mu\) is the coefficient of friction between the block and the surface. A force mg pulls the block. This force acts an angle \(\theta\) with the vertical side of the block. The mass of the block is \(\mathrm{m}\). The block can be pulled along the surface, if \(\cot \frac{\theta}{2}\)

1 \(>\mu\)
2 \(=\mu\)
3 \( \lt \mu\)
4 \(\frac{\mu}{6}\)
LAWS OF MOTION (ADDITIONAL)

372140 An army vehicle of mass \(1000 \mathrm{~kg}\) is moving with velocity of \(10 \mathrm{~m} / \mathrm{s}\) and is acted upon by a forward force of \(1000 \mathrm{~N}\) due to the engine and a retarding force of \(500 \mathrm{~N}\) due to the friction. What will be its velocity after \(10 \mathrm{~s}\) ?

1 \(5 \mathrm{~m} / \mathrm{s}\)
2 \(10 \mathrm{~m} / \mathrm{s}\)
3 \(15 \mathrm{~m} / \mathrm{s}\)
4 \(20 \mathrm{~m} / \mathrm{s}\)
LAWS OF MOTION (ADDITIONAL)

372137 If coefficient of static friction is \(\mu_{\mathrm{s}}\) and coefficient of kinetic friction is \(\mu_{\mathrm{k}}\), which is correct?

1 \(\mu_{\mathrm{s}}=\mu_{\mathrm{k}}\)
2 \(\mu_{\mathrm{s}}>\mu_{\mathrm{k}}\)
3 \(\mu_{\mathrm{s}} \lt \mu_{\mathrm{k}}\)
4 Cannot predict
LAWS OF MOTION (ADDITIONAL)

372138 The coefficient of friction between the tyres and the road is 0.25 . The maximum speed with which car can be driven round a curve of radius \(40 \mathrm{~m}\) without skidding is (assume \(\mathrm{g}=10\) \(\mathbf{m s}^{-2}\) )

1 \(40 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}\)
3 \(15 \mathrm{~ms}^{-1}\)
4 \(10 \mathrm{~ms}^{-1}\)
LAWS OF MOTION (ADDITIONAL)

372139 A block rests on a rough horizontal surface, \(\mu\) is the coefficient of friction between the block and the surface. A force mg pulls the block. This force acts an angle \(\theta\) with the vertical side of the block. The mass of the block is \(\mathrm{m}\). The block can be pulled along the surface, if \(\cot \frac{\theta}{2}\)

1 \(>\mu\)
2 \(=\mu\)
3 \( \lt \mu\)
4 \(\frac{\mu}{6}\)
LAWS OF MOTION (ADDITIONAL)

372140 An army vehicle of mass \(1000 \mathrm{~kg}\) is moving with velocity of \(10 \mathrm{~m} / \mathrm{s}\) and is acted upon by a forward force of \(1000 \mathrm{~N}\) due to the engine and a retarding force of \(500 \mathrm{~N}\) due to the friction. What will be its velocity after \(10 \mathrm{~s}\) ?

1 \(5 \mathrm{~m} / \mathrm{s}\)
2 \(10 \mathrm{~m} / \mathrm{s}\)
3 \(15 \mathrm{~m} / \mathrm{s}\)
4 \(20 \mathrm{~m} / \mathrm{s}\)
LAWS OF MOTION (ADDITIONAL)

372137 If coefficient of static friction is \(\mu_{\mathrm{s}}\) and coefficient of kinetic friction is \(\mu_{\mathrm{k}}\), which is correct?

1 \(\mu_{\mathrm{s}}=\mu_{\mathrm{k}}\)
2 \(\mu_{\mathrm{s}}>\mu_{\mathrm{k}}\)
3 \(\mu_{\mathrm{s}} \lt \mu_{\mathrm{k}}\)
4 Cannot predict
LAWS OF MOTION (ADDITIONAL)

372138 The coefficient of friction between the tyres and the road is 0.25 . The maximum speed with which car can be driven round a curve of radius \(40 \mathrm{~m}\) without skidding is (assume \(\mathrm{g}=10\) \(\mathbf{m s}^{-2}\) )

1 \(40 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}\)
3 \(15 \mathrm{~ms}^{-1}\)
4 \(10 \mathrm{~ms}^{-1}\)
LAWS OF MOTION (ADDITIONAL)

372139 A block rests on a rough horizontal surface, \(\mu\) is the coefficient of friction between the block and the surface. A force mg pulls the block. This force acts an angle \(\theta\) with the vertical side of the block. The mass of the block is \(\mathrm{m}\). The block can be pulled along the surface, if \(\cot \frac{\theta}{2}\)

1 \(>\mu\)
2 \(=\mu\)
3 \( \lt \mu\)
4 \(\frac{\mu}{6}\)
LAWS OF MOTION (ADDITIONAL)

372140 An army vehicle of mass \(1000 \mathrm{~kg}\) is moving with velocity of \(10 \mathrm{~m} / \mathrm{s}\) and is acted upon by a forward force of \(1000 \mathrm{~N}\) due to the engine and a retarding force of \(500 \mathrm{~N}\) due to the friction. What will be its velocity after \(10 \mathrm{~s}\) ?

1 \(5 \mathrm{~m} / \mathrm{s}\)
2 \(10 \mathrm{~m} / \mathrm{s}\)
3 \(15 \mathrm{~m} / \mathrm{s}\)
4 \(20 \mathrm{~m} / \mathrm{s}\)
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LAWS OF MOTION (ADDITIONAL)

372137 If coefficient of static friction is \(\mu_{\mathrm{s}}\) and coefficient of kinetic friction is \(\mu_{\mathrm{k}}\), which is correct?

1 \(\mu_{\mathrm{s}}=\mu_{\mathrm{k}}\)
2 \(\mu_{\mathrm{s}}>\mu_{\mathrm{k}}\)
3 \(\mu_{\mathrm{s}} \lt \mu_{\mathrm{k}}\)
4 Cannot predict
LAWS OF MOTION (ADDITIONAL)

372138 The coefficient of friction between the tyres and the road is 0.25 . The maximum speed with which car can be driven round a curve of radius \(40 \mathrm{~m}\) without skidding is (assume \(\mathrm{g}=10\) \(\mathbf{m s}^{-2}\) )

1 \(40 \mathrm{~ms}^{-1}\)
2 \(20 \mathrm{~ms}^{-1}\)
3 \(15 \mathrm{~ms}^{-1}\)
4 \(10 \mathrm{~ms}^{-1}\)
LAWS OF MOTION (ADDITIONAL)

372139 A block rests on a rough horizontal surface, \(\mu\) is the coefficient of friction between the block and the surface. A force mg pulls the block. This force acts an angle \(\theta\) with the vertical side of the block. The mass of the block is \(\mathrm{m}\). The block can be pulled along the surface, if \(\cot \frac{\theta}{2}\)

1 \(>\mu\)
2 \(=\mu\)
3 \( \lt \mu\)
4 \(\frac{\mu}{6}\)
LAWS OF MOTION (ADDITIONAL)

372140 An army vehicle of mass \(1000 \mathrm{~kg}\) is moving with velocity of \(10 \mathrm{~m} / \mathrm{s}\) and is acted upon by a forward force of \(1000 \mathrm{~N}\) due to the engine and a retarding force of \(500 \mathrm{~N}\) due to the friction. What will be its velocity after \(10 \mathrm{~s}\) ?

1 \(5 \mathrm{~m} / \mathrm{s}\)
2 \(10 \mathrm{~m} / \mathrm{s}\)
3 \(15 \mathrm{~m} / \mathrm{s}\)
4 \(20 \mathrm{~m} / \mathrm{s}\)