Forces in Mechanism
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
LAWS OF MOTION (ADDITIONAL)

371881 A lift is moving up with an acceleration equal to \(1 / 5\) of that due to gravity. The apparent weight of a \(60 \mathrm{~kg}\) man standing in lift is:

1 \(60 \mathrm{~kg} \mathrm{wt}\)
2 \(72 \mathrm{~kg} \mathrm{wt}\)
3 \(48 \mathrm{~kg} \mathrm{wt}\)
4 Zero
LAWS OF MOTION (ADDITIONAL)

371882 Two masses \(m_{1}\) and \(m_{2}\) are connected by a massless string over a fixed pulley. If \(\mathbf{m}_{1}>\mathbf{m}_{2}\), \(m_{1}\) will move downward and \(m_{2}\) will move upward. What is the acceleration with which the combination of two masses will move? \((g=\) acceleration due to gravity)

1 0
2 \(\mathrm{g}\)
3 \(\left[\left(\mathrm{m}_{1}-\mathrm{m}_{2}\right) /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
4 \(\left[2 \mathrm{~m}_{1} \mathrm{~m}_{2} /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
LAWS OF MOTION (ADDITIONAL)

371883 In the pulley system shown in the figure, the mass of \(A\) is half of that of \(\operatorname{rod} B\). The rod length is \(500 \mathrm{~cm}\). The mass of pulleys and the threads may be neglected. The mass \(A\) is set at the same level as the lower end of the rod and then released. After releasing the mass \(A\), it would reach the top end of the \(\operatorname{rod} B\) in time (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(2.0 \mathrm{~s}\)
2 \(1.0 \mathrm{~s}\)
3 \(3.0 \mathrm{~s}\)
4 \(4.0 \mathrm{~s}\)
LAWS OF MOTION (ADDITIONAL)

371884 Two masses \(m_{1}\) and \(m_{2}\) are attached to a string which passes over a frictionless smooth pulley. When \(m_{1}=10 \mathrm{~kg}, m_{2}=6 \mathrm{~kg}\), the acceleration of masses is

1 \(20 \mathrm{~m} / \mathrm{s}^{2}\)
2 \(5 \mathrm{~m} / \mathrm{s}^{2}\)
3 \(2.5 \mathrm{~m} / \mathrm{s}^{2}\)
4 \(10 \mathrm{~m} / \mathrm{s}^{2}\)
LAWS OF MOTION (ADDITIONAL)

371881 A lift is moving up with an acceleration equal to \(1 / 5\) of that due to gravity. The apparent weight of a \(60 \mathrm{~kg}\) man standing in lift is:

1 \(60 \mathrm{~kg} \mathrm{wt}\)
2 \(72 \mathrm{~kg} \mathrm{wt}\)
3 \(48 \mathrm{~kg} \mathrm{wt}\)
4 Zero
LAWS OF MOTION (ADDITIONAL)

371882 Two masses \(m_{1}\) and \(m_{2}\) are connected by a massless string over a fixed pulley. If \(\mathbf{m}_{1}>\mathbf{m}_{2}\), \(m_{1}\) will move downward and \(m_{2}\) will move upward. What is the acceleration with which the combination of two masses will move? \((g=\) acceleration due to gravity)

1 0
2 \(\mathrm{g}\)
3 \(\left[\left(\mathrm{m}_{1}-\mathrm{m}_{2}\right) /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
4 \(\left[2 \mathrm{~m}_{1} \mathrm{~m}_{2} /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
LAWS OF MOTION (ADDITIONAL)

371883 In the pulley system shown in the figure, the mass of \(A\) is half of that of \(\operatorname{rod} B\). The rod length is \(500 \mathrm{~cm}\). The mass of pulleys and the threads may be neglected. The mass \(A\) is set at the same level as the lower end of the rod and then released. After releasing the mass \(A\), it would reach the top end of the \(\operatorname{rod} B\) in time (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(2.0 \mathrm{~s}\)
2 \(1.0 \mathrm{~s}\)
3 \(3.0 \mathrm{~s}\)
4 \(4.0 \mathrm{~s}\)
LAWS OF MOTION (ADDITIONAL)

371884 Two masses \(m_{1}\) and \(m_{2}\) are attached to a string which passes over a frictionless smooth pulley. When \(m_{1}=10 \mathrm{~kg}, m_{2}=6 \mathrm{~kg}\), the acceleration of masses is

1 \(20 \mathrm{~m} / \mathrm{s}^{2}\)
2 \(5 \mathrm{~m} / \mathrm{s}^{2}\)
3 \(2.5 \mathrm{~m} / \mathrm{s}^{2}\)
4 \(10 \mathrm{~m} / \mathrm{s}^{2}\)
LAWS OF MOTION (ADDITIONAL)

371881 A lift is moving up with an acceleration equal to \(1 / 5\) of that due to gravity. The apparent weight of a \(60 \mathrm{~kg}\) man standing in lift is:

1 \(60 \mathrm{~kg} \mathrm{wt}\)
2 \(72 \mathrm{~kg} \mathrm{wt}\)
3 \(48 \mathrm{~kg} \mathrm{wt}\)
4 Zero
LAWS OF MOTION (ADDITIONAL)

371882 Two masses \(m_{1}\) and \(m_{2}\) are connected by a massless string over a fixed pulley. If \(\mathbf{m}_{1}>\mathbf{m}_{2}\), \(m_{1}\) will move downward and \(m_{2}\) will move upward. What is the acceleration with which the combination of two masses will move? \((g=\) acceleration due to gravity)

1 0
2 \(\mathrm{g}\)
3 \(\left[\left(\mathrm{m}_{1}-\mathrm{m}_{2}\right) /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
4 \(\left[2 \mathrm{~m}_{1} \mathrm{~m}_{2} /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
LAWS OF MOTION (ADDITIONAL)

371883 In the pulley system shown in the figure, the mass of \(A\) is half of that of \(\operatorname{rod} B\). The rod length is \(500 \mathrm{~cm}\). The mass of pulleys and the threads may be neglected. The mass \(A\) is set at the same level as the lower end of the rod and then released. After releasing the mass \(A\), it would reach the top end of the \(\operatorname{rod} B\) in time (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(2.0 \mathrm{~s}\)
2 \(1.0 \mathrm{~s}\)
3 \(3.0 \mathrm{~s}\)
4 \(4.0 \mathrm{~s}\)
LAWS OF MOTION (ADDITIONAL)

371884 Two masses \(m_{1}\) and \(m_{2}\) are attached to a string which passes over a frictionless smooth pulley. When \(m_{1}=10 \mathrm{~kg}, m_{2}=6 \mathrm{~kg}\), the acceleration of masses is

1 \(20 \mathrm{~m} / \mathrm{s}^{2}\)
2 \(5 \mathrm{~m} / \mathrm{s}^{2}\)
3 \(2.5 \mathrm{~m} / \mathrm{s}^{2}\)
4 \(10 \mathrm{~m} / \mathrm{s}^{2}\)
LAWS OF MOTION (ADDITIONAL)

371881 A lift is moving up with an acceleration equal to \(1 / 5\) of that due to gravity. The apparent weight of a \(60 \mathrm{~kg}\) man standing in lift is:

1 \(60 \mathrm{~kg} \mathrm{wt}\)
2 \(72 \mathrm{~kg} \mathrm{wt}\)
3 \(48 \mathrm{~kg} \mathrm{wt}\)
4 Zero
LAWS OF MOTION (ADDITIONAL)

371882 Two masses \(m_{1}\) and \(m_{2}\) are connected by a massless string over a fixed pulley. If \(\mathbf{m}_{1}>\mathbf{m}_{2}\), \(m_{1}\) will move downward and \(m_{2}\) will move upward. What is the acceleration with which the combination of two masses will move? \((g=\) acceleration due to gravity)

1 0
2 \(\mathrm{g}\)
3 \(\left[\left(\mathrm{m}_{1}-\mathrm{m}_{2}\right) /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
4 \(\left[2 \mathrm{~m}_{1} \mathrm{~m}_{2} /\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)\right] \times \mathrm{g}\)
LAWS OF MOTION (ADDITIONAL)

371883 In the pulley system shown in the figure, the mass of \(A\) is half of that of \(\operatorname{rod} B\). The rod length is \(500 \mathrm{~cm}\). The mass of pulleys and the threads may be neglected. The mass \(A\) is set at the same level as the lower end of the rod and then released. After releasing the mass \(A\), it would reach the top end of the \(\operatorname{rod} B\) in time (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(2.0 \mathrm{~s}\)
2 \(1.0 \mathrm{~s}\)
3 \(3.0 \mathrm{~s}\)
4 \(4.0 \mathrm{~s}\)
LAWS OF MOTION (ADDITIONAL)

371884 Two masses \(m_{1}\) and \(m_{2}\) are attached to a string which passes over a frictionless smooth pulley. When \(m_{1}=10 \mathrm{~kg}, m_{2}=6 \mathrm{~kg}\), the acceleration of masses is

1 \(20 \mathrm{~m} / \mathrm{s}^{2}\)
2 \(5 \mathrm{~m} / \mathrm{s}^{2}\)
3 \(2.5 \mathrm{~m} / \mathrm{s}^{2}\)
4 \(10 \mathrm{~m} / \mathrm{s}^{2}\)