371774
Physical independence of force is a consequence of:
1 third law of motion
2 second law of motion
3 first law of motion
4 all of these laws
5 none of the above
Explanation:
C Newton \(1^{\text {st }}\) law of motion states that when a body of mass ' \(\mathrm{m}\) ' moving with acceleration ' \(\mathrm{a}\) ', then the mathematical value of force acting on the body is product of mass and acceleration. So, \(1^{\text {st }}\) law of motion show physical independency of force as force is independent of mass and acceleration.
Kerala CEE 2004
LAWS OF MOTION (ADDITIONAL)
371775
Which of the following is NOT an illustration of Newton's third law?
1 Flight of a jet plane
2 A cricket player lowering his hands while catching a cricket ball
3 Walking on floor
4 Rebounding of a rubber ball
Explanation:
B Newton third law says that every action has an equal and opposite reaction. So, bowler catching a ball moves his hand backward is an example of phenomenon under taken by momentum because while lowering his hand he is trying to slow down the ball to get a lesser effect of momentum.
UPSEE - 2009
LAWS OF MOTION (ADDITIONAL)
371776
A machine gun fires a bullet of mass \(40 \mathrm{~g}\) with a velocity \(1200 \mathrm{~m} / \mathrm{s}\). The man holding it can exert a maximum force of \(144 \mathrm{~N}\) on the gun. How many bullets can be fired per second at the most?
1 Only one
2 Three
3 Can fire any number of bullets
4 \(144 \times 48\)
Explanation:
B Let, \(\mathrm{n}=\) no. of bullet fired per second, \(\therefore \quad \mathrm{F}_{\mathrm{ext}}=\mathrm{n}\left[\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}\right]\) Where, \(\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}=\) Rate of change of momentum of each bullet. \(\mathrm{F}_{\text {ext }}=\mathrm{n}\left[\frac{\mathrm{mv}-0}{\Delta \mathrm{t}}\right]\) \(144=\mathrm{n} \times \frac{40 \times 1200}{1}\) \(\therefore \quad \mathrm{n} =\frac{144}{40 \times 1200 \times 10^{-3}}\) \(\mathrm{n} =\frac{144}{4 \times 12}\) \(\mathrm{n} =3\) \(144=\mathrm{n} \times \frac{40 \times 1200 \times 10^{-3}}{1}\) Hence, number of bullet fired per second \(=3\)
UPSEE - 2008
LAWS OF MOTION (ADDITIONAL)
371777
A block of mass \(M\) is pulled along a horizontal frictionless surface by a rope of mass \(M / 2\). If a force \(2 \mathrm{Mg}\) is applied at one end of the rope, the force which the rope exerts on the block is-
1 \(2 \mathrm{Mg} / 3\)
2 \(2 \mathrm{Mg}\)
3 \(4 \mathrm{Mg} / 3\)
4 zero
Explanation:
C We know that, \(\mathrm{F}_{\mathrm{Ext}}=\mathrm{Ma}\) \(2 \mathrm{Mg}=\left(\mathrm{M}+\frac{\mathrm{M}}{2}\right) \mathrm{a} {\left[\because \text { Total mass }=\mathrm{M}+\frac{\mathrm{M}}{2}\right]}\) \(\frac{2 \mathrm{Mg}}{\frac{3 \mathrm{M}}{2}}=\mathrm{a} {[\because \mathrm{F}=2 \mathrm{mg}]}\) \(\mathrm{a}=\frac{4 \mathrm{~g}}{3}\) Force applied on the block \((\mathrm{F})=\mathrm{Ma}\) \(=\mathrm{M} \times \frac{4 \mathrm{~g}}{3}\) \(=\frac{4 \mathrm{Mg}}{3}\)
371774
Physical independence of force is a consequence of:
1 third law of motion
2 second law of motion
3 first law of motion
4 all of these laws
5 none of the above
Explanation:
C Newton \(1^{\text {st }}\) law of motion states that when a body of mass ' \(\mathrm{m}\) ' moving with acceleration ' \(\mathrm{a}\) ', then the mathematical value of force acting on the body is product of mass and acceleration. So, \(1^{\text {st }}\) law of motion show physical independency of force as force is independent of mass and acceleration.
Kerala CEE 2004
LAWS OF MOTION (ADDITIONAL)
371775
Which of the following is NOT an illustration of Newton's third law?
1 Flight of a jet plane
2 A cricket player lowering his hands while catching a cricket ball
3 Walking on floor
4 Rebounding of a rubber ball
Explanation:
B Newton third law says that every action has an equal and opposite reaction. So, bowler catching a ball moves his hand backward is an example of phenomenon under taken by momentum because while lowering his hand he is trying to slow down the ball to get a lesser effect of momentum.
UPSEE - 2009
LAWS OF MOTION (ADDITIONAL)
371776
A machine gun fires a bullet of mass \(40 \mathrm{~g}\) with a velocity \(1200 \mathrm{~m} / \mathrm{s}\). The man holding it can exert a maximum force of \(144 \mathrm{~N}\) on the gun. How many bullets can be fired per second at the most?
1 Only one
2 Three
3 Can fire any number of bullets
4 \(144 \times 48\)
Explanation:
B Let, \(\mathrm{n}=\) no. of bullet fired per second, \(\therefore \quad \mathrm{F}_{\mathrm{ext}}=\mathrm{n}\left[\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}\right]\) Where, \(\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}=\) Rate of change of momentum of each bullet. \(\mathrm{F}_{\text {ext }}=\mathrm{n}\left[\frac{\mathrm{mv}-0}{\Delta \mathrm{t}}\right]\) \(144=\mathrm{n} \times \frac{40 \times 1200}{1}\) \(\therefore \quad \mathrm{n} =\frac{144}{40 \times 1200 \times 10^{-3}}\) \(\mathrm{n} =\frac{144}{4 \times 12}\) \(\mathrm{n} =3\) \(144=\mathrm{n} \times \frac{40 \times 1200 \times 10^{-3}}{1}\) Hence, number of bullet fired per second \(=3\)
UPSEE - 2008
LAWS OF MOTION (ADDITIONAL)
371777
A block of mass \(M\) is pulled along a horizontal frictionless surface by a rope of mass \(M / 2\). If a force \(2 \mathrm{Mg}\) is applied at one end of the rope, the force which the rope exerts on the block is-
1 \(2 \mathrm{Mg} / 3\)
2 \(2 \mathrm{Mg}\)
3 \(4 \mathrm{Mg} / 3\)
4 zero
Explanation:
C We know that, \(\mathrm{F}_{\mathrm{Ext}}=\mathrm{Ma}\) \(2 \mathrm{Mg}=\left(\mathrm{M}+\frac{\mathrm{M}}{2}\right) \mathrm{a} {\left[\because \text { Total mass }=\mathrm{M}+\frac{\mathrm{M}}{2}\right]}\) \(\frac{2 \mathrm{Mg}}{\frac{3 \mathrm{M}}{2}}=\mathrm{a} {[\because \mathrm{F}=2 \mathrm{mg}]}\) \(\mathrm{a}=\frac{4 \mathrm{~g}}{3}\) Force applied on the block \((\mathrm{F})=\mathrm{Ma}\) \(=\mathrm{M} \times \frac{4 \mathrm{~g}}{3}\) \(=\frac{4 \mathrm{Mg}}{3}\)
371774
Physical independence of force is a consequence of:
1 third law of motion
2 second law of motion
3 first law of motion
4 all of these laws
5 none of the above
Explanation:
C Newton \(1^{\text {st }}\) law of motion states that when a body of mass ' \(\mathrm{m}\) ' moving with acceleration ' \(\mathrm{a}\) ', then the mathematical value of force acting on the body is product of mass and acceleration. So, \(1^{\text {st }}\) law of motion show physical independency of force as force is independent of mass and acceleration.
Kerala CEE 2004
LAWS OF MOTION (ADDITIONAL)
371775
Which of the following is NOT an illustration of Newton's third law?
1 Flight of a jet plane
2 A cricket player lowering his hands while catching a cricket ball
3 Walking on floor
4 Rebounding of a rubber ball
Explanation:
B Newton third law says that every action has an equal and opposite reaction. So, bowler catching a ball moves his hand backward is an example of phenomenon under taken by momentum because while lowering his hand he is trying to slow down the ball to get a lesser effect of momentum.
UPSEE - 2009
LAWS OF MOTION (ADDITIONAL)
371776
A machine gun fires a bullet of mass \(40 \mathrm{~g}\) with a velocity \(1200 \mathrm{~m} / \mathrm{s}\). The man holding it can exert a maximum force of \(144 \mathrm{~N}\) on the gun. How many bullets can be fired per second at the most?
1 Only one
2 Three
3 Can fire any number of bullets
4 \(144 \times 48\)
Explanation:
B Let, \(\mathrm{n}=\) no. of bullet fired per second, \(\therefore \quad \mathrm{F}_{\mathrm{ext}}=\mathrm{n}\left[\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}\right]\) Where, \(\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}=\) Rate of change of momentum of each bullet. \(\mathrm{F}_{\text {ext }}=\mathrm{n}\left[\frac{\mathrm{mv}-0}{\Delta \mathrm{t}}\right]\) \(144=\mathrm{n} \times \frac{40 \times 1200}{1}\) \(\therefore \quad \mathrm{n} =\frac{144}{40 \times 1200 \times 10^{-3}}\) \(\mathrm{n} =\frac{144}{4 \times 12}\) \(\mathrm{n} =3\) \(144=\mathrm{n} \times \frac{40 \times 1200 \times 10^{-3}}{1}\) Hence, number of bullet fired per second \(=3\)
UPSEE - 2008
LAWS OF MOTION (ADDITIONAL)
371777
A block of mass \(M\) is pulled along a horizontal frictionless surface by a rope of mass \(M / 2\). If a force \(2 \mathrm{Mg}\) is applied at one end of the rope, the force which the rope exerts on the block is-
1 \(2 \mathrm{Mg} / 3\)
2 \(2 \mathrm{Mg}\)
3 \(4 \mathrm{Mg} / 3\)
4 zero
Explanation:
C We know that, \(\mathrm{F}_{\mathrm{Ext}}=\mathrm{Ma}\) \(2 \mathrm{Mg}=\left(\mathrm{M}+\frac{\mathrm{M}}{2}\right) \mathrm{a} {\left[\because \text { Total mass }=\mathrm{M}+\frac{\mathrm{M}}{2}\right]}\) \(\frac{2 \mathrm{Mg}}{\frac{3 \mathrm{M}}{2}}=\mathrm{a} {[\because \mathrm{F}=2 \mathrm{mg}]}\) \(\mathrm{a}=\frac{4 \mathrm{~g}}{3}\) Force applied on the block \((\mathrm{F})=\mathrm{Ma}\) \(=\mathrm{M} \times \frac{4 \mathrm{~g}}{3}\) \(=\frac{4 \mathrm{Mg}}{3}\)
371774
Physical independence of force is a consequence of:
1 third law of motion
2 second law of motion
3 first law of motion
4 all of these laws
5 none of the above
Explanation:
C Newton \(1^{\text {st }}\) law of motion states that when a body of mass ' \(\mathrm{m}\) ' moving with acceleration ' \(\mathrm{a}\) ', then the mathematical value of force acting on the body is product of mass and acceleration. So, \(1^{\text {st }}\) law of motion show physical independency of force as force is independent of mass and acceleration.
Kerala CEE 2004
LAWS OF MOTION (ADDITIONAL)
371775
Which of the following is NOT an illustration of Newton's third law?
1 Flight of a jet plane
2 A cricket player lowering his hands while catching a cricket ball
3 Walking on floor
4 Rebounding of a rubber ball
Explanation:
B Newton third law says that every action has an equal and opposite reaction. So, bowler catching a ball moves his hand backward is an example of phenomenon under taken by momentum because while lowering his hand he is trying to slow down the ball to get a lesser effect of momentum.
UPSEE - 2009
LAWS OF MOTION (ADDITIONAL)
371776
A machine gun fires a bullet of mass \(40 \mathrm{~g}\) with a velocity \(1200 \mathrm{~m} / \mathrm{s}\). The man holding it can exert a maximum force of \(144 \mathrm{~N}\) on the gun. How many bullets can be fired per second at the most?
1 Only one
2 Three
3 Can fire any number of bullets
4 \(144 \times 48\)
Explanation:
B Let, \(\mathrm{n}=\) no. of bullet fired per second, \(\therefore \quad \mathrm{F}_{\mathrm{ext}}=\mathrm{n}\left[\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}\right]\) Where, \(\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}=\) Rate of change of momentum of each bullet. \(\mathrm{F}_{\text {ext }}=\mathrm{n}\left[\frac{\mathrm{mv}-0}{\Delta \mathrm{t}}\right]\) \(144=\mathrm{n} \times \frac{40 \times 1200}{1}\) \(\therefore \quad \mathrm{n} =\frac{144}{40 \times 1200 \times 10^{-3}}\) \(\mathrm{n} =\frac{144}{4 \times 12}\) \(\mathrm{n} =3\) \(144=\mathrm{n} \times \frac{40 \times 1200 \times 10^{-3}}{1}\) Hence, number of bullet fired per second \(=3\)
UPSEE - 2008
LAWS OF MOTION (ADDITIONAL)
371777
A block of mass \(M\) is pulled along a horizontal frictionless surface by a rope of mass \(M / 2\). If a force \(2 \mathrm{Mg}\) is applied at one end of the rope, the force which the rope exerts on the block is-
1 \(2 \mathrm{Mg} / 3\)
2 \(2 \mathrm{Mg}\)
3 \(4 \mathrm{Mg} / 3\)
4 zero
Explanation:
C We know that, \(\mathrm{F}_{\mathrm{Ext}}=\mathrm{Ma}\) \(2 \mathrm{Mg}=\left(\mathrm{M}+\frac{\mathrm{M}}{2}\right) \mathrm{a} {\left[\because \text { Total mass }=\mathrm{M}+\frac{\mathrm{M}}{2}\right]}\) \(\frac{2 \mathrm{Mg}}{\frac{3 \mathrm{M}}{2}}=\mathrm{a} {[\because \mathrm{F}=2 \mathrm{mg}]}\) \(\mathrm{a}=\frac{4 \mathrm{~g}}{3}\) Force applied on the block \((\mathrm{F})=\mathrm{Ma}\) \(=\mathrm{M} \times \frac{4 \mathrm{~g}}{3}\) \(=\frac{4 \mathrm{Mg}}{3}\)
