371612
Find the pressure at which temperature attains its maximum value if the relation between pressure and volume for an ideal is \(P=P_{0}+(1-\alpha) V^{2} ; \alpha>1\)
371613
An ideal gas with adiabatic exponent \((\gamma=1.5)\) undergoes a process in which work done by the gas is same as increase in internal energy of the gas. The molar heat capacity of gas for the process is -
1 \(C = 4\,R\)
2 \(C = 0\)
3 \(C = 2\,R\)
4 \(C = R\)
Explanation:
\(\int P dV = \int {n{C_v}} dt\) \( \Rightarrow dQ = 2dU \Rightarrow nCdT = 2n{C_v}dt\) \( \Rightarrow C = 2{C_v}\) \( \Rightarrow \;\;\;{\mkern 1mu} {\kern 1pt} C = \frac{{2R}}{{1.5 - 1}} = 4R\)
PHXI12:THERMODYNAMICS
371614
A gas expand with temperature according to the relation \(V=K T^{2 / 3}\). What is the work done when the temperature changes by \(30^\circ C\) ?
1 \(20\,R\)
2 \(10\,R\)
3 \(40\,R\)
4 \(30\,R\)
Explanation:
\(W=\int P d V=\int \dfrac{R T}{V} d V\) Since \(V=K T^{2 / 3}\) Hence, \(d V=\dfrac{2}{3} K T^{-1 / 3} d T \quad \therefore \dfrac{d V}{V}=\dfrac{2}{3} \cdot \dfrac{d T}{T}\) Hence \(W=\int_{T_{1}}^{T_{2}} \dfrac{2}{3} \dfrac{R T}{T} d T=\dfrac{2}{3} R\left(T_{2}-T_{1}\right)=\dfrac{2}{3} R(30)=20 R\)
PHXI12:THERMODYNAMICS
371615
Which of the following processes is reversible?
1 Transfer of heat by radiation
2 Transfer of heat by conduction
3 Electrical heating of a nichrome wire
4 Isothermal compression
Explanation:
For process to be reversible it must be quasi-static. For quasi static process all changes take place very slowly. Isothermal process occur very slowly so it is quasi-static and hence it is reversible.
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PHXI12:THERMODYNAMICS
371612
Find the pressure at which temperature attains its maximum value if the relation between pressure and volume for an ideal is \(P=P_{0}+(1-\alpha) V^{2} ; \alpha>1\)
371613
An ideal gas with adiabatic exponent \((\gamma=1.5)\) undergoes a process in which work done by the gas is same as increase in internal energy of the gas. The molar heat capacity of gas for the process is -
1 \(C = 4\,R\)
2 \(C = 0\)
3 \(C = 2\,R\)
4 \(C = R\)
Explanation:
\(\int P dV = \int {n{C_v}} dt\) \( \Rightarrow dQ = 2dU \Rightarrow nCdT = 2n{C_v}dt\) \( \Rightarrow C = 2{C_v}\) \( \Rightarrow \;\;\;{\mkern 1mu} {\kern 1pt} C = \frac{{2R}}{{1.5 - 1}} = 4R\)
PHXI12:THERMODYNAMICS
371614
A gas expand with temperature according to the relation \(V=K T^{2 / 3}\). What is the work done when the temperature changes by \(30^\circ C\) ?
1 \(20\,R\)
2 \(10\,R\)
3 \(40\,R\)
4 \(30\,R\)
Explanation:
\(W=\int P d V=\int \dfrac{R T}{V} d V\) Since \(V=K T^{2 / 3}\) Hence, \(d V=\dfrac{2}{3} K T^{-1 / 3} d T \quad \therefore \dfrac{d V}{V}=\dfrac{2}{3} \cdot \dfrac{d T}{T}\) Hence \(W=\int_{T_{1}}^{T_{2}} \dfrac{2}{3} \dfrac{R T}{T} d T=\dfrac{2}{3} R\left(T_{2}-T_{1}\right)=\dfrac{2}{3} R(30)=20 R\)
PHXI12:THERMODYNAMICS
371615
Which of the following processes is reversible?
1 Transfer of heat by radiation
2 Transfer of heat by conduction
3 Electrical heating of a nichrome wire
4 Isothermal compression
Explanation:
For process to be reversible it must be quasi-static. For quasi static process all changes take place very slowly. Isothermal process occur very slowly so it is quasi-static and hence it is reversible.
371612
Find the pressure at which temperature attains its maximum value if the relation between pressure and volume for an ideal is \(P=P_{0}+(1-\alpha) V^{2} ; \alpha>1\)
371613
An ideal gas with adiabatic exponent \((\gamma=1.5)\) undergoes a process in which work done by the gas is same as increase in internal energy of the gas. The molar heat capacity of gas for the process is -
1 \(C = 4\,R\)
2 \(C = 0\)
3 \(C = 2\,R\)
4 \(C = R\)
Explanation:
\(\int P dV = \int {n{C_v}} dt\) \( \Rightarrow dQ = 2dU \Rightarrow nCdT = 2n{C_v}dt\) \( \Rightarrow C = 2{C_v}\) \( \Rightarrow \;\;\;{\mkern 1mu} {\kern 1pt} C = \frac{{2R}}{{1.5 - 1}} = 4R\)
PHXI12:THERMODYNAMICS
371614
A gas expand with temperature according to the relation \(V=K T^{2 / 3}\). What is the work done when the temperature changes by \(30^\circ C\) ?
1 \(20\,R\)
2 \(10\,R\)
3 \(40\,R\)
4 \(30\,R\)
Explanation:
\(W=\int P d V=\int \dfrac{R T}{V} d V\) Since \(V=K T^{2 / 3}\) Hence, \(d V=\dfrac{2}{3} K T^{-1 / 3} d T \quad \therefore \dfrac{d V}{V}=\dfrac{2}{3} \cdot \dfrac{d T}{T}\) Hence \(W=\int_{T_{1}}^{T_{2}} \dfrac{2}{3} \dfrac{R T}{T} d T=\dfrac{2}{3} R\left(T_{2}-T_{1}\right)=\dfrac{2}{3} R(30)=20 R\)
PHXI12:THERMODYNAMICS
371615
Which of the following processes is reversible?
1 Transfer of heat by radiation
2 Transfer of heat by conduction
3 Electrical heating of a nichrome wire
4 Isothermal compression
Explanation:
For process to be reversible it must be quasi-static. For quasi static process all changes take place very slowly. Isothermal process occur very slowly so it is quasi-static and hence it is reversible.
371612
Find the pressure at which temperature attains its maximum value if the relation between pressure and volume for an ideal is \(P=P_{0}+(1-\alpha) V^{2} ; \alpha>1\)
371613
An ideal gas with adiabatic exponent \((\gamma=1.5)\) undergoes a process in which work done by the gas is same as increase in internal energy of the gas. The molar heat capacity of gas for the process is -
1 \(C = 4\,R\)
2 \(C = 0\)
3 \(C = 2\,R\)
4 \(C = R\)
Explanation:
\(\int P dV = \int {n{C_v}} dt\) \( \Rightarrow dQ = 2dU \Rightarrow nCdT = 2n{C_v}dt\) \( \Rightarrow C = 2{C_v}\) \( \Rightarrow \;\;\;{\mkern 1mu} {\kern 1pt} C = \frac{{2R}}{{1.5 - 1}} = 4R\)
PHXI12:THERMODYNAMICS
371614
A gas expand with temperature according to the relation \(V=K T^{2 / 3}\). What is the work done when the temperature changes by \(30^\circ C\) ?
1 \(20\,R\)
2 \(10\,R\)
3 \(40\,R\)
4 \(30\,R\)
Explanation:
\(W=\int P d V=\int \dfrac{R T}{V} d V\) Since \(V=K T^{2 / 3}\) Hence, \(d V=\dfrac{2}{3} K T^{-1 / 3} d T \quad \therefore \dfrac{d V}{V}=\dfrac{2}{3} \cdot \dfrac{d T}{T}\) Hence \(W=\int_{T_{1}}^{T_{2}} \dfrac{2}{3} \dfrac{R T}{T} d T=\dfrac{2}{3} R\left(T_{2}-T_{1}\right)=\dfrac{2}{3} R(30)=20 R\)
PHXI12:THERMODYNAMICS
371615
Which of the following processes is reversible?
1 Transfer of heat by radiation
2 Transfer of heat by conduction
3 Electrical heating of a nichrome wire
4 Isothermal compression
Explanation:
For process to be reversible it must be quasi-static. For quasi static process all changes take place very slowly. Isothermal process occur very slowly so it is quasi-static and hence it is reversible.