Explanation:
Here, \(Q_{1}=6 \times 10^{5} \mathrm{cal}\)
\({T_1} = 227^\circ C = 227 + 273 = 500\;\,K\)
\({T_2} = 127^\circ C = 127 + 273 = 400\,\;K\)
Work done/cycle, \(W=\) ?
As, \(\frac{{{Q_2}}}{{{Q_1}}} = \frac{{{T_2}}}{{{T_1}}}{\rm{ or }}{Q_2} = \frac{{{T_2}}}{{{T_1}}} \times {Q_1}\)
\( = \frac{{400}}{{500}} \times 6 \times {10^5}\)
\( = 4.8 \times {10^5}cal\)
As, \(\quad W = {Q_1} - {Q_2} = 6 \times {10^5} - 4.8 \times {10^5}\)
\((\because \,\,\,1\,cal = 4.2\,J)\)
\( = 1.2 \times {10^5} \times 4.2\,J\)
\( \Rightarrow \quad W = 5.04 \times {10^5}\;J \approx 5 \times {10^5}\;J\)