368111 Assertion :
In Young’s experiment, for two coherent sources, each of intensity \({I_0}\), the resultant intensity is given by \(I = 4{I_0}{\cos ^2}\frac{\phi }{2}\)
Reason :
Ratio of maximum to minimum intensity is \(\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{{{{\left( {\sqrt {{I_1}} + \sqrt {{I_2}} } \right)}^2}}}{{{{\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)}^2}}}.\)

368112 Statement A :
Interference pattern is made by using yellow light instead of red light, the fringes becomes narrower.
Statement B :
In \(YDSE\), fringe width is given by \(\beta = \frac{{D\lambda }}{d}\).

368113 Young's double slit experiment is conducted with light of wavelength \(\lambda\). The intensity of the bright fringe is \(I_{0}\). The intensity at a point where path difference is \(\lambda / 4\) is given by

368114 In Young's double slit experiment, one of the slit is wider than the other, so that amplitude of the light from one slit is double that of from the other slit. If \(I_{m}\) be the maximum intensity, the resultant intensity \(I\) when they interfere at phase difference \(\phi\) is given by

368111 Assertion :
In Young’s experiment, for two coherent sources, each of intensity \({I_0}\), the resultant intensity is given by \(I = 4{I_0}{\cos ^2}\frac{\phi }{2}\)
Reason :
Ratio of maximum to minimum intensity is \(\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{{{{\left( {\sqrt {{I_1}} + \sqrt {{I_2}} } \right)}^2}}}{{{{\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)}^2}}}.\)

368112 Statement A :
Interference pattern is made by using yellow light instead of red light, the fringes becomes narrower.
Statement B :
In \(YDSE\), fringe width is given by \(\beta = \frac{{D\lambda }}{d}\).

368113 Young's double slit experiment is conducted with light of wavelength \(\lambda\). The intensity of the bright fringe is \(I_{0}\). The intensity at a point where path difference is \(\lambda / 4\) is given by

368114 In Young's double slit experiment, one of the slit is wider than the other, so that amplitude of the light from one slit is double that of from the other slit. If \(I_{m}\) be the maximum intensity, the resultant intensity \(I\) when they interfere at phase difference \(\phi\) is given by

368111 Assertion :
In Young’s experiment, for two coherent sources, each of intensity \({I_0}\), the resultant intensity is given by \(I = 4{I_0}{\cos ^2}\frac{\phi }{2}\)
Reason :
Ratio of maximum to minimum intensity is \(\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{{{{\left( {\sqrt {{I_1}} + \sqrt {{I_2}} } \right)}^2}}}{{{{\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)}^2}}}.\)

368112 Statement A :
Interference pattern is made by using yellow light instead of red light, the fringes becomes narrower.
Statement B :
In \(YDSE\), fringe width is given by \(\beta = \frac{{D\lambda }}{d}\).

368113 Young's double slit experiment is conducted with light of wavelength \(\lambda\). The intensity of the bright fringe is \(I_{0}\). The intensity at a point where path difference is \(\lambda / 4\) is given by

368114 In Young's double slit experiment, one of the slit is wider than the other, so that amplitude of the light from one slit is double that of from the other slit. If \(I_{m}\) be the maximum intensity, the resultant intensity \(I\) when they interfere at phase difference \(\phi\) is given by

368111 Assertion :
In Young’s experiment, for two coherent sources, each of intensity \({I_0}\), the resultant intensity is given by \(I = 4{I_0}{\cos ^2}\frac{\phi }{2}\)
Reason :
Ratio of maximum to minimum intensity is \(\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{{{{\left( {\sqrt {{I_1}} + \sqrt {{I_2}} } \right)}^2}}}{{{{\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)}^2}}}.\)

368112 Statement A :
Interference pattern is made by using yellow light instead of red light, the fringes becomes narrower.
Statement B :
In \(YDSE\), fringe width is given by \(\beta = \frac{{D\lambda }}{d}\).

368113 Young's double slit experiment is conducted with light of wavelength \(\lambda\). The intensity of the bright fringe is \(I_{0}\). The intensity at a point where path difference is \(\lambda / 4\) is given by

368114 In Young's double slit experiment, one of the slit is wider than the other, so that amplitude of the light from one slit is double that of from the other slit. If \(I_{m}\) be the maximum intensity, the resultant intensity \(I\) when they interfere at phase difference \(\phi\) is given by