368085
In Young’s experiment intensity at a point on the screen is \(75\% \) of the maximum value. Minimum phase difference between the waves arriving at this point from the two slits will be
368086
In a double slit experiment, the slit seperation is \(0.20\;cm\) and the slit to screen distance is \(100\;cm\). The positions of the first three minima, if wavellength of the source is \(500\;nm\) is
368087
In the young’s double slit experiment using a monochromatic light of wavelength \(\lambda \), the path difference (\(n\) is an integer) corresponding to any point having half the peak intensity is:
368088
If the slits in Young’s double slit experiment are of unequal width, then
1 The bright fringes will have unequal spacing
2 The bright fringes will have unequal brightness
3 The fringes do not appear
4 The dark fringes are not perfectly dark.
Explanation:
When the slits are of unequal widths, the source intensities are also unequal, i.e. \({I_1}{\rm{ }} \ne {\rm{ }}{I_2}\) \(\therefore \) Minimum intensity \({I_{\min }} = {\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)^2} \ne 0\) i.e., the dark fringes are not perfectly dark.
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII10:WAVE OPTICS
368085
In Young’s experiment intensity at a point on the screen is \(75\% \) of the maximum value. Minimum phase difference between the waves arriving at this point from the two slits will be
368086
In a double slit experiment, the slit seperation is \(0.20\;cm\) and the slit to screen distance is \(100\;cm\). The positions of the first three minima, if wavellength of the source is \(500\;nm\) is
368087
In the young’s double slit experiment using a monochromatic light of wavelength \(\lambda \), the path difference (\(n\) is an integer) corresponding to any point having half the peak intensity is:
368088
If the slits in Young’s double slit experiment are of unequal width, then
1 The bright fringes will have unequal spacing
2 The bright fringes will have unequal brightness
3 The fringes do not appear
4 The dark fringes are not perfectly dark.
Explanation:
When the slits are of unequal widths, the source intensities are also unequal, i.e. \({I_1}{\rm{ }} \ne {\rm{ }}{I_2}\) \(\therefore \) Minimum intensity \({I_{\min }} = {\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)^2} \ne 0\) i.e., the dark fringes are not perfectly dark.
368085
In Young’s experiment intensity at a point on the screen is \(75\% \) of the maximum value. Minimum phase difference between the waves arriving at this point from the two slits will be
368086
In a double slit experiment, the slit seperation is \(0.20\;cm\) and the slit to screen distance is \(100\;cm\). The positions of the first three minima, if wavellength of the source is \(500\;nm\) is
368087
In the young’s double slit experiment using a monochromatic light of wavelength \(\lambda \), the path difference (\(n\) is an integer) corresponding to any point having half the peak intensity is:
368088
If the slits in Young’s double slit experiment are of unequal width, then
1 The bright fringes will have unequal spacing
2 The bright fringes will have unequal brightness
3 The fringes do not appear
4 The dark fringes are not perfectly dark.
Explanation:
When the slits are of unequal widths, the source intensities are also unequal, i.e. \({I_1}{\rm{ }} \ne {\rm{ }}{I_2}\) \(\therefore \) Minimum intensity \({I_{\min }} = {\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)^2} \ne 0\) i.e., the dark fringes are not perfectly dark.
368085
In Young’s experiment intensity at a point on the screen is \(75\% \) of the maximum value. Minimum phase difference between the waves arriving at this point from the two slits will be
368086
In a double slit experiment, the slit seperation is \(0.20\;cm\) and the slit to screen distance is \(100\;cm\). The positions of the first three minima, if wavellength of the source is \(500\;nm\) is
368087
In the young’s double slit experiment using a monochromatic light of wavelength \(\lambda \), the path difference (\(n\) is an integer) corresponding to any point having half the peak intensity is:
368088
If the slits in Young’s double slit experiment are of unequal width, then
1 The bright fringes will have unequal spacing
2 The bright fringes will have unequal brightness
3 The fringes do not appear
4 The dark fringes are not perfectly dark.
Explanation:
When the slits are of unequal widths, the source intensities are also unequal, i.e. \({I_1}{\rm{ }} \ne {\rm{ }}{I_2}\) \(\therefore \) Minimum intensity \({I_{\min }} = {\left( {\sqrt {{I_1}} - \sqrt {{I_2}} } \right)^2} \ne 0\) i.e., the dark fringes are not perfectly dark.