367683
In single slit fraunhofer diffraction which type of wavefront is required?
1 Cylindrical
2 Spherical
3 Elliptical
4 Plane
Explanation:
PHXII10:WAVE OPTICS
367684
If \({I_1}\) is the intensity of the principal maximum in the single slit diffraction pattern then, with doubling the slit width, the intensity becomes
1 \({I_1}\)
2 \({I_1}/2\)
3 \(2{I_1}\)
4 \(4{I_1}\)
Explanation:
If we assume that the initial no of sources for a width \(a\) is \(N\) then the number of sources become \(2N\) after doubling the slit width \({I_1} = {N^2}{I_0}\) \({I_2} = {\left( {2N} \right)^2}{I_0} \Rightarrow {I_2} = 4{I_1}\)
PHXII10:WAVE OPTICS
367685
The ratio of \({2^{nd}}\) maximum intensity to the \({1^{st}}\) maximum intensity in a diffraction is
1 \(4/9\)
2 \(9/25\)
3 \(5/9\)
4 \(25/49\)
Explanation:
The \(1st{\rm{ }}\) maximum intensity is \({I_1} = \frac{4}{{9{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) The \(2nd\) maximum intensity is \({I_2} = \frac{4}{{25{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) \(\frac{{{I_2}}}{{{I_1}}} = \frac{9}{{25}}\)
367683
In single slit fraunhofer diffraction which type of wavefront is required?
1 Cylindrical
2 Spherical
3 Elliptical
4 Plane
Explanation:
PHXII10:WAVE OPTICS
367684
If \({I_1}\) is the intensity of the principal maximum in the single slit diffraction pattern then, with doubling the slit width, the intensity becomes
1 \({I_1}\)
2 \({I_1}/2\)
3 \(2{I_1}\)
4 \(4{I_1}\)
Explanation:
If we assume that the initial no of sources for a width \(a\) is \(N\) then the number of sources become \(2N\) after doubling the slit width \({I_1} = {N^2}{I_0}\) \({I_2} = {\left( {2N} \right)^2}{I_0} \Rightarrow {I_2} = 4{I_1}\)
PHXII10:WAVE OPTICS
367685
The ratio of \({2^{nd}}\) maximum intensity to the \({1^{st}}\) maximum intensity in a diffraction is
1 \(4/9\)
2 \(9/25\)
3 \(5/9\)
4 \(25/49\)
Explanation:
The \(1st{\rm{ }}\) maximum intensity is \({I_1} = \frac{4}{{9{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) The \(2nd\) maximum intensity is \({I_2} = \frac{4}{{25{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) \(\frac{{{I_2}}}{{{I_1}}} = \frac{9}{{25}}\)
367683
In single slit fraunhofer diffraction which type of wavefront is required?
1 Cylindrical
2 Spherical
3 Elliptical
4 Plane
Explanation:
PHXII10:WAVE OPTICS
367684
If \({I_1}\) is the intensity of the principal maximum in the single slit diffraction pattern then, with doubling the slit width, the intensity becomes
1 \({I_1}\)
2 \({I_1}/2\)
3 \(2{I_1}\)
4 \(4{I_1}\)
Explanation:
If we assume that the initial no of sources for a width \(a\) is \(N\) then the number of sources become \(2N\) after doubling the slit width \({I_1} = {N^2}{I_0}\) \({I_2} = {\left( {2N} \right)^2}{I_0} \Rightarrow {I_2} = 4{I_1}\)
PHXII10:WAVE OPTICS
367685
The ratio of \({2^{nd}}\) maximum intensity to the \({1^{st}}\) maximum intensity in a diffraction is
1 \(4/9\)
2 \(9/25\)
3 \(5/9\)
4 \(25/49\)
Explanation:
The \(1st{\rm{ }}\) maximum intensity is \({I_1} = \frac{4}{{9{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) The \(2nd\) maximum intensity is \({I_2} = \frac{4}{{25{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) \(\frac{{{I_2}}}{{{I_1}}} = \frac{9}{{25}}\)
367683
In single slit fraunhofer diffraction which type of wavefront is required?
1 Cylindrical
2 Spherical
3 Elliptical
4 Plane
Explanation:
PHXII10:WAVE OPTICS
367684
If \({I_1}\) is the intensity of the principal maximum in the single slit diffraction pattern then, with doubling the slit width, the intensity becomes
1 \({I_1}\)
2 \({I_1}/2\)
3 \(2{I_1}\)
4 \(4{I_1}\)
Explanation:
If we assume that the initial no of sources for a width \(a\) is \(N\) then the number of sources become \(2N\) after doubling the slit width \({I_1} = {N^2}{I_0}\) \({I_2} = {\left( {2N} \right)^2}{I_0} \Rightarrow {I_2} = 4{I_1}\)
PHXII10:WAVE OPTICS
367685
The ratio of \({2^{nd}}\) maximum intensity to the \({1^{st}}\) maximum intensity in a diffraction is
1 \(4/9\)
2 \(9/25\)
3 \(5/9\)
4 \(25/49\)
Explanation:
The \(1st{\rm{ }}\) maximum intensity is \({I_1} = \frac{4}{{9{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) The \(2nd\) maximum intensity is \({I_2} = \frac{4}{{25{\pi ^2}}}\left( {{N^2}{I_0}} \right)\) \(\frac{{{I_2}}}{{{I_1}}} = \frac{9}{{25}}\)
