367666
To observe diffraction, the size of the obstacle
1 Should be \(\lambda /2\), where \(\lambda \) is the wavelength
2 Should be of the order of wavelength
3 Has no relation to wavelength
4 Should be much larger than the wavelength
Explanation:
To observe diffraction, the size of the obstacle should be of the order of wavelength.
KCET - 2015
PHXII10:WAVE OPTICS
367667
Assertion : Out of radio waves and microwaves, the former undergoes more diffraction. Reason : Radio waves have greater frequency compared to microwaves.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radio waves are of longer \(\lambda\) and diffract more than microwaves. So correct option is (3).
PHXII10:WAVE OPTICS
367668
In a Fraunhofer diffraction at a single slit, if yellow light illuminating the slit is replaced by blue light, then diffraction bands
1 Remain unchanged
2 Become wider
3 Disappear
4 Become narrower
Explanation:
Width of diffraction bands is directly proportional to the wavelength of light used. Thus, if yellow light is replaced by blue light, diffraction bands become narrower because \({\lambda _{{\rm{blue}}}} < {\lambda _{{\rm{yellow}}}}\)
PHXII10:WAVE OPTICS
367669
Assertion : No diffraction is produced in sound waves near a very small opening. Reason : For diffraction to take place the aperture of opening should be the same order as wavelength of the waves.
1 Both Assertion and Reasons are true and the Reason is a correct explanation of the Assertion.
2 Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
3 Assertion is true but the Reason is false.
4 Assertion is false but Reason is true.
Explanation:
The condition for first minima is \(\sin \theta = \frac{\lambda }{a}{\rm{ }}\). The diffraction of sound is only possible when the size of opening should be of the same order as its wavelength and the wavelength of sound is of the order of \(1.0\,m,\) hence, for a very small opening no diffraction is produced in sound since \(\sin \theta > 1{\rm{ }}\) . So option (1) is correct.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII10:WAVE OPTICS
367666
To observe diffraction, the size of the obstacle
1 Should be \(\lambda /2\), where \(\lambda \) is the wavelength
2 Should be of the order of wavelength
3 Has no relation to wavelength
4 Should be much larger than the wavelength
Explanation:
To observe diffraction, the size of the obstacle should be of the order of wavelength.
KCET - 2015
PHXII10:WAVE OPTICS
367667
Assertion : Out of radio waves and microwaves, the former undergoes more diffraction. Reason : Radio waves have greater frequency compared to microwaves.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radio waves are of longer \(\lambda\) and diffract more than microwaves. So correct option is (3).
PHXII10:WAVE OPTICS
367668
In a Fraunhofer diffraction at a single slit, if yellow light illuminating the slit is replaced by blue light, then diffraction bands
1 Remain unchanged
2 Become wider
3 Disappear
4 Become narrower
Explanation:
Width of diffraction bands is directly proportional to the wavelength of light used. Thus, if yellow light is replaced by blue light, diffraction bands become narrower because \({\lambda _{{\rm{blue}}}} < {\lambda _{{\rm{yellow}}}}\)
PHXII10:WAVE OPTICS
367669
Assertion : No diffraction is produced in sound waves near a very small opening. Reason : For diffraction to take place the aperture of opening should be the same order as wavelength of the waves.
1 Both Assertion and Reasons are true and the Reason is a correct explanation of the Assertion.
2 Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
3 Assertion is true but the Reason is false.
4 Assertion is false but Reason is true.
Explanation:
The condition for first minima is \(\sin \theta = \frac{\lambda }{a}{\rm{ }}\). The diffraction of sound is only possible when the size of opening should be of the same order as its wavelength and the wavelength of sound is of the order of \(1.0\,m,\) hence, for a very small opening no diffraction is produced in sound since \(\sin \theta > 1{\rm{ }}\) . So option (1) is correct.
367666
To observe diffraction, the size of the obstacle
1 Should be \(\lambda /2\), where \(\lambda \) is the wavelength
2 Should be of the order of wavelength
3 Has no relation to wavelength
4 Should be much larger than the wavelength
Explanation:
To observe diffraction, the size of the obstacle should be of the order of wavelength.
KCET - 2015
PHXII10:WAVE OPTICS
367667
Assertion : Out of radio waves and microwaves, the former undergoes more diffraction. Reason : Radio waves have greater frequency compared to microwaves.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radio waves are of longer \(\lambda\) and diffract more than microwaves. So correct option is (3).
PHXII10:WAVE OPTICS
367668
In a Fraunhofer diffraction at a single slit, if yellow light illuminating the slit is replaced by blue light, then diffraction bands
1 Remain unchanged
2 Become wider
3 Disappear
4 Become narrower
Explanation:
Width of diffraction bands is directly proportional to the wavelength of light used. Thus, if yellow light is replaced by blue light, diffraction bands become narrower because \({\lambda _{{\rm{blue}}}} < {\lambda _{{\rm{yellow}}}}\)
PHXII10:WAVE OPTICS
367669
Assertion : No diffraction is produced in sound waves near a very small opening. Reason : For diffraction to take place the aperture of opening should be the same order as wavelength of the waves.
1 Both Assertion and Reasons are true and the Reason is a correct explanation of the Assertion.
2 Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
3 Assertion is true but the Reason is false.
4 Assertion is false but Reason is true.
Explanation:
The condition for first minima is \(\sin \theta = \frac{\lambda }{a}{\rm{ }}\). The diffraction of sound is only possible when the size of opening should be of the same order as its wavelength and the wavelength of sound is of the order of \(1.0\,m,\) hence, for a very small opening no diffraction is produced in sound since \(\sin \theta > 1{\rm{ }}\) . So option (1) is correct.
367666
To observe diffraction, the size of the obstacle
1 Should be \(\lambda /2\), where \(\lambda \) is the wavelength
2 Should be of the order of wavelength
3 Has no relation to wavelength
4 Should be much larger than the wavelength
Explanation:
To observe diffraction, the size of the obstacle should be of the order of wavelength.
KCET - 2015
PHXII10:WAVE OPTICS
367667
Assertion : Out of radio waves and microwaves, the former undergoes more diffraction. Reason : Radio waves have greater frequency compared to microwaves.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radio waves are of longer \(\lambda\) and diffract more than microwaves. So correct option is (3).
PHXII10:WAVE OPTICS
367668
In a Fraunhofer diffraction at a single slit, if yellow light illuminating the slit is replaced by blue light, then diffraction bands
1 Remain unchanged
2 Become wider
3 Disappear
4 Become narrower
Explanation:
Width of diffraction bands is directly proportional to the wavelength of light used. Thus, if yellow light is replaced by blue light, diffraction bands become narrower because \({\lambda _{{\rm{blue}}}} < {\lambda _{{\rm{yellow}}}}\)
PHXII10:WAVE OPTICS
367669
Assertion : No diffraction is produced in sound waves near a very small opening. Reason : For diffraction to take place the aperture of opening should be the same order as wavelength of the waves.
1 Both Assertion and Reasons are true and the Reason is a correct explanation of the Assertion.
2 Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
3 Assertion is true but the Reason is false.
4 Assertion is false but Reason is true.
Explanation:
The condition for first minima is \(\sin \theta = \frac{\lambda }{a}{\rm{ }}\). The diffraction of sound is only possible when the size of opening should be of the same order as its wavelength and the wavelength of sound is of the order of \(1.0\,m,\) hence, for a very small opening no diffraction is produced in sound since \(\sin \theta > 1{\rm{ }}\) . So option (1) is correct.