NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII10:WAVE OPTICS
367730
For fraunhofer single slit diffraction:
1 Width of the central maxima is proportional to \(\lambda \)
2 On increasing the slit width, the width of central maxima decreases
3 On making the slit width \(a = \lambda \), central fringe spreads in the range \(90^\circ \)
4 All of the above are correct
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
367731
The width of the diffraction band varies
1 Inversely as the wavelength
2 Directly as the width of the slit
3 Directly as the distance between the slit and the screen
4 Inversely as the size of the source from which the slit is illuminated.
Explanation:
Linear width of the diffraction band, \(\beta = \frac{{D\lambda }}{a}\) where \(D\) = distance between slit and the screen, \(a\) = width of the slit, \(\lambda = \) wavelength. Hence, \(\beta \propto D\).
KCET - 2006
PHXII10:WAVE OPTICS
367732
Light of wavelength \(550\,nm\) falls normally on a slit of width \(22.0 \times {10^{ - 5}}\,cm\). The angular position of the second minima from the central maximum will be (in radians):
1 \(\dfrac{\pi}{4}\)
2 \(\dfrac{\pi}{8}\)
3 \(\dfrac{\pi}{12}\)
4 \(\dfrac{\pi}{6}\)
Explanation:
Angular position of \(2^{\text {nd }}\) maxima from central maxima is \(\theta \) where \(\sin \theta = \frac{{3\lambda }}{{2a}} = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\) \(\theta \simeq \frac{\pi }{8}\,\,rad\)
JEE - 2018
PHXII10:WAVE OPTICS
367733
Which of the statements are correct with reference to single slit diffraction pattern? I. Fringes are of unequal width II. Fringes are of equal width III. Light energy is conserved IV. Intensities of all bright fringes are equal
1 I and III
2 I and IV
3 II and IV
4 II and III
Explanation:
For single slit diffraction, the central maximum is wider and more intense than other bright fringes which are less bright as a result of energy conservation.
1 Width of the central maxima is proportional to \(\lambda \)
2 On increasing the slit width, the width of central maxima decreases
3 On making the slit width \(a = \lambda \), central fringe spreads in the range \(90^\circ \)
4 All of the above are correct
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
367731
The width of the diffraction band varies
1 Inversely as the wavelength
2 Directly as the width of the slit
3 Directly as the distance between the slit and the screen
4 Inversely as the size of the source from which the slit is illuminated.
Explanation:
Linear width of the diffraction band, \(\beta = \frac{{D\lambda }}{a}\) where \(D\) = distance between slit and the screen, \(a\) = width of the slit, \(\lambda = \) wavelength. Hence, \(\beta \propto D\).
KCET - 2006
PHXII10:WAVE OPTICS
367732
Light of wavelength \(550\,nm\) falls normally on a slit of width \(22.0 \times {10^{ - 5}}\,cm\). The angular position of the second minima from the central maximum will be (in radians):
1 \(\dfrac{\pi}{4}\)
2 \(\dfrac{\pi}{8}\)
3 \(\dfrac{\pi}{12}\)
4 \(\dfrac{\pi}{6}\)
Explanation:
Angular position of \(2^{\text {nd }}\) maxima from central maxima is \(\theta \) where \(\sin \theta = \frac{{3\lambda }}{{2a}} = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\) \(\theta \simeq \frac{\pi }{8}\,\,rad\)
JEE - 2018
PHXII10:WAVE OPTICS
367733
Which of the statements are correct with reference to single slit diffraction pattern? I. Fringes are of unequal width II. Fringes are of equal width III. Light energy is conserved IV. Intensities of all bright fringes are equal
1 I and III
2 I and IV
3 II and IV
4 II and III
Explanation:
For single slit diffraction, the central maximum is wider and more intense than other bright fringes which are less bright as a result of energy conservation.
1 Width of the central maxima is proportional to \(\lambda \)
2 On increasing the slit width, the width of central maxima decreases
3 On making the slit width \(a = \lambda \), central fringe spreads in the range \(90^\circ \)
4 All of the above are correct
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
367731
The width of the diffraction band varies
1 Inversely as the wavelength
2 Directly as the width of the slit
3 Directly as the distance between the slit and the screen
4 Inversely as the size of the source from which the slit is illuminated.
Explanation:
Linear width of the diffraction band, \(\beta = \frac{{D\lambda }}{a}\) where \(D\) = distance between slit and the screen, \(a\) = width of the slit, \(\lambda = \) wavelength. Hence, \(\beta \propto D\).
KCET - 2006
PHXII10:WAVE OPTICS
367732
Light of wavelength \(550\,nm\) falls normally on a slit of width \(22.0 \times {10^{ - 5}}\,cm\). The angular position of the second minima from the central maximum will be (in radians):
1 \(\dfrac{\pi}{4}\)
2 \(\dfrac{\pi}{8}\)
3 \(\dfrac{\pi}{12}\)
4 \(\dfrac{\pi}{6}\)
Explanation:
Angular position of \(2^{\text {nd }}\) maxima from central maxima is \(\theta \) where \(\sin \theta = \frac{{3\lambda }}{{2a}} = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\) \(\theta \simeq \frac{\pi }{8}\,\,rad\)
JEE - 2018
PHXII10:WAVE OPTICS
367733
Which of the statements are correct with reference to single slit diffraction pattern? I. Fringes are of unequal width II. Fringes are of equal width III. Light energy is conserved IV. Intensities of all bright fringes are equal
1 I and III
2 I and IV
3 II and IV
4 II and III
Explanation:
For single slit diffraction, the central maximum is wider and more intense than other bright fringes which are less bright as a result of energy conservation.
1 Width of the central maxima is proportional to \(\lambda \)
2 On increasing the slit width, the width of central maxima decreases
3 On making the slit width \(a = \lambda \), central fringe spreads in the range \(90^\circ \)
4 All of the above are correct
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
367731
The width of the diffraction band varies
1 Inversely as the wavelength
2 Directly as the width of the slit
3 Directly as the distance between the slit and the screen
4 Inversely as the size of the source from which the slit is illuminated.
Explanation:
Linear width of the diffraction band, \(\beta = \frac{{D\lambda }}{a}\) where \(D\) = distance between slit and the screen, \(a\) = width of the slit, \(\lambda = \) wavelength. Hence, \(\beta \propto D\).
KCET - 2006
PHXII10:WAVE OPTICS
367732
Light of wavelength \(550\,nm\) falls normally on a slit of width \(22.0 \times {10^{ - 5}}\,cm\). The angular position of the second minima from the central maximum will be (in radians):
1 \(\dfrac{\pi}{4}\)
2 \(\dfrac{\pi}{8}\)
3 \(\dfrac{\pi}{12}\)
4 \(\dfrac{\pi}{6}\)
Explanation:
Angular position of \(2^{\text {nd }}\) maxima from central maxima is \(\theta \) where \(\sin \theta = \frac{{3\lambda }}{{2a}} = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\) \(\theta \simeq \frac{\pi }{8}\,\,rad\)
JEE - 2018
PHXII10:WAVE OPTICS
367733
Which of the statements are correct with reference to single slit diffraction pattern? I. Fringes are of unequal width II. Fringes are of equal width III. Light energy is conserved IV. Intensities of all bright fringes are equal
1 I and III
2 I and IV
3 II and IV
4 II and III
Explanation:
For single slit diffraction, the central maximum is wider and more intense than other bright fringes which are less bright as a result of energy conservation.
