367717
A parallel beam of light of wavelength \(3141.59\mathop A\limits^ \circ \) is incident on a small aperture. After passing through the aperture, the beam is no longer parallel but diverges at \(1^\circ \) to the incident direction. What is the diameter of the aperture?
1 \(0.18\;m\)
2 \(180\;m\)
3 \(18\;m\)
4 \(18\;\mu m\)
Explanation:
From diffraction at a single slit, size of aperture, \(a = \frac{\lambda }{{\sin \theta }}\) or, \(a = \frac{{3141.59 \times {{10}^{ - 10}}}}{{\sin {1^0}}} = 18 \times {10^{ - 6}}m = 18\mu m\)
PHXII10:WAVE OPTICS
367718
The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length \(1\,m\).The width of slit is \(0.3\,mm\). If third minimum is formed at a distance of \(5\,mm\) from central maximum, then wavelength of light will be
367719
A single slit of width \(0.1\,mm\) is illuminated by a parallel beam of light of wavelength \(6000\,\mathop A\limits^o \) and diffraction bands are observed on a screen \(0.5\,m\) from the slit. The distance of the third dark band from the central bright band is
367720
How wil the diffraction pattern change when yellow lights is replaced by green light? The fringe will be
1 Wider
2 Narrower
3 Brighter
4 Fainter
Explanation:
\({\lambda _y} > {\lambda _G}\) Fringe width in diffraction \( \propto \,\lambda {\rm{ }}\) If yellow light is replaced with green light then central fringe becomes narrow
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII10:WAVE OPTICS
367717
A parallel beam of light of wavelength \(3141.59\mathop A\limits^ \circ \) is incident on a small aperture. After passing through the aperture, the beam is no longer parallel but diverges at \(1^\circ \) to the incident direction. What is the diameter of the aperture?
1 \(0.18\;m\)
2 \(180\;m\)
3 \(18\;m\)
4 \(18\;\mu m\)
Explanation:
From diffraction at a single slit, size of aperture, \(a = \frac{\lambda }{{\sin \theta }}\) or, \(a = \frac{{3141.59 \times {{10}^{ - 10}}}}{{\sin {1^0}}} = 18 \times {10^{ - 6}}m = 18\mu m\)
PHXII10:WAVE OPTICS
367718
The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length \(1\,m\).The width of slit is \(0.3\,mm\). If third minimum is formed at a distance of \(5\,mm\) from central maximum, then wavelength of light will be
367719
A single slit of width \(0.1\,mm\) is illuminated by a parallel beam of light of wavelength \(6000\,\mathop A\limits^o \) and diffraction bands are observed on a screen \(0.5\,m\) from the slit. The distance of the third dark band from the central bright band is
367720
How wil the diffraction pattern change when yellow lights is replaced by green light? The fringe will be
1 Wider
2 Narrower
3 Brighter
4 Fainter
Explanation:
\({\lambda _y} > {\lambda _G}\) Fringe width in diffraction \( \propto \,\lambda {\rm{ }}\) If yellow light is replaced with green light then central fringe becomes narrow
367717
A parallel beam of light of wavelength \(3141.59\mathop A\limits^ \circ \) is incident on a small aperture. After passing through the aperture, the beam is no longer parallel but diverges at \(1^\circ \) to the incident direction. What is the diameter of the aperture?
1 \(0.18\;m\)
2 \(180\;m\)
3 \(18\;m\)
4 \(18\;\mu m\)
Explanation:
From diffraction at a single slit, size of aperture, \(a = \frac{\lambda }{{\sin \theta }}\) or, \(a = \frac{{3141.59 \times {{10}^{ - 10}}}}{{\sin {1^0}}} = 18 \times {10^{ - 6}}m = 18\mu m\)
PHXII10:WAVE OPTICS
367718
The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length \(1\,m\).The width of slit is \(0.3\,mm\). If third minimum is formed at a distance of \(5\,mm\) from central maximum, then wavelength of light will be
367719
A single slit of width \(0.1\,mm\) is illuminated by a parallel beam of light of wavelength \(6000\,\mathop A\limits^o \) and diffraction bands are observed on a screen \(0.5\,m\) from the slit. The distance of the third dark band from the central bright band is
367720
How wil the diffraction pattern change when yellow lights is replaced by green light? The fringe will be
1 Wider
2 Narrower
3 Brighter
4 Fainter
Explanation:
\({\lambda _y} > {\lambda _G}\) Fringe width in diffraction \( \propto \,\lambda {\rm{ }}\) If yellow light is replaced with green light then central fringe becomes narrow
367717
A parallel beam of light of wavelength \(3141.59\mathop A\limits^ \circ \) is incident on a small aperture. After passing through the aperture, the beam is no longer parallel but diverges at \(1^\circ \) to the incident direction. What is the diameter of the aperture?
1 \(0.18\;m\)
2 \(180\;m\)
3 \(18\;m\)
4 \(18\;\mu m\)
Explanation:
From diffraction at a single slit, size of aperture, \(a = \frac{\lambda }{{\sin \theta }}\) or, \(a = \frac{{3141.59 \times {{10}^{ - 10}}}}{{\sin {1^0}}} = 18 \times {10^{ - 6}}m = 18\mu m\)
PHXII10:WAVE OPTICS
367718
The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length \(1\,m\).The width of slit is \(0.3\,mm\). If third minimum is formed at a distance of \(5\,mm\) from central maximum, then wavelength of light will be
367719
A single slit of width \(0.1\,mm\) is illuminated by a parallel beam of light of wavelength \(6000\,\mathop A\limits^o \) and diffraction bands are observed on a screen \(0.5\,m\) from the slit. The distance of the third dark band from the central bright band is
367720
How wil the diffraction pattern change when yellow lights is replaced by green light? The fringe will be
1 Wider
2 Narrower
3 Brighter
4 Fainter
Explanation:
\({\lambda _y} > {\lambda _G}\) Fringe width in diffraction \( \propto \,\lambda {\rm{ }}\) If yellow light is replaced with green light then central fringe becomes narrow