Errors
PHXI02:UNITS AND MEASUREMENTS

367541 The length of a strip measured with a metre rod is 10.0 \(cm\). Its width measured with a vernier callipers is 1.00 \(cm\). The least count of the metre rod is 0.1 \(cm\) and that of vernier calliper is 0.01 \(cm\). What will be the error in its area?

1 \( \pm 0.01\,c{m^2}\)
2 \( \pm 0.1\,c{m^2}\)
3 \( \pm 0.1\,1c{m^2}\)
4 \( \pm 0.2c{m^2}\)
PHXI02:UNITS AND MEASUREMENTS

367542 In a vernier callipers, \({(N+1)}\) divisions of vernier scale coincide with \({N}\) divisions of main scale. If 1 MSD represents \(0.1\,mm\), the vernier constant (in \(cm\)) is:

1 \({\dfrac{1}{10 {~N}}}\)
2 \({\dfrac{1}{100(N+1)}}\)
3 \(100\,N\)
4 \({10(N+1)}\)
PHXI02:UNITS AND MEASUREMENTS

367543 There is a vernier callipers which has 1 \(cm\) divided into 10 equal divisions on the main scale. The vernier scale (\(C\)) has 10 equal divisions that correspond to 9 main scale divisions. The measured value (in \(cm\)) by callipers \(C\) is
supporting img

1 \(2.87\)
2 \(2.78\)
3 \(2.85\)
4 \(2.68\)
PHXI02:UNITS AND MEASUREMENTS

367544 Assertion :
In Vernier Calliper if positive zero error exists, then while taking measurements, the reading taken will be more than the actual reading.
Reason :
The zero error in Vernier Calliper might have happened due to manufacturing defect or due to rough handling.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI02:UNITS AND MEASUREMENTS

367545 The Vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 \(mm\), then the least count of the microscope is

1 \(0.01\,mm\)
2 \(0.5\,cm\)
3 \(0.01\,cm\)
4 \(0.5\,mm\)
PHXI02:UNITS AND MEASUREMENTS

367541 The length of a strip measured with a metre rod is 10.0 \(cm\). Its width measured with a vernier callipers is 1.00 \(cm\). The least count of the metre rod is 0.1 \(cm\) and that of vernier calliper is 0.01 \(cm\). What will be the error in its area?

1 \( \pm 0.01\,c{m^2}\)
2 \( \pm 0.1\,c{m^2}\)
3 \( \pm 0.1\,1c{m^2}\)
4 \( \pm 0.2c{m^2}\)
PHXI02:UNITS AND MEASUREMENTS

367542 In a vernier callipers, \({(N+1)}\) divisions of vernier scale coincide with \({N}\) divisions of main scale. If 1 MSD represents \(0.1\,mm\), the vernier constant (in \(cm\)) is:

1 \({\dfrac{1}{10 {~N}}}\)
2 \({\dfrac{1}{100(N+1)}}\)
3 \(100\,N\)
4 \({10(N+1)}\)
PHXI02:UNITS AND MEASUREMENTS

367543 There is a vernier callipers which has 1 \(cm\) divided into 10 equal divisions on the main scale. The vernier scale (\(C\)) has 10 equal divisions that correspond to 9 main scale divisions. The measured value (in \(cm\)) by callipers \(C\) is
supporting img

1 \(2.87\)
2 \(2.78\)
3 \(2.85\)
4 \(2.68\)
PHXI02:UNITS AND MEASUREMENTS

367544 Assertion :
In Vernier Calliper if positive zero error exists, then while taking measurements, the reading taken will be more than the actual reading.
Reason :
The zero error in Vernier Calliper might have happened due to manufacturing defect or due to rough handling.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI02:UNITS AND MEASUREMENTS

367545 The Vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 \(mm\), then the least count of the microscope is

1 \(0.01\,mm\)
2 \(0.5\,cm\)
3 \(0.01\,cm\)
4 \(0.5\,mm\)
PHXI02:UNITS AND MEASUREMENTS

367541 The length of a strip measured with a metre rod is 10.0 \(cm\). Its width measured with a vernier callipers is 1.00 \(cm\). The least count of the metre rod is 0.1 \(cm\) and that of vernier calliper is 0.01 \(cm\). What will be the error in its area?

1 \( \pm 0.01\,c{m^2}\)
2 \( \pm 0.1\,c{m^2}\)
3 \( \pm 0.1\,1c{m^2}\)
4 \( \pm 0.2c{m^2}\)
PHXI02:UNITS AND MEASUREMENTS

367542 In a vernier callipers, \({(N+1)}\) divisions of vernier scale coincide with \({N}\) divisions of main scale. If 1 MSD represents \(0.1\,mm\), the vernier constant (in \(cm\)) is:

1 \({\dfrac{1}{10 {~N}}}\)
2 \({\dfrac{1}{100(N+1)}}\)
3 \(100\,N\)
4 \({10(N+1)}\)
PHXI02:UNITS AND MEASUREMENTS

367543 There is a vernier callipers which has 1 \(cm\) divided into 10 equal divisions on the main scale. The vernier scale (\(C\)) has 10 equal divisions that correspond to 9 main scale divisions. The measured value (in \(cm\)) by callipers \(C\) is
supporting img

1 \(2.87\)
2 \(2.78\)
3 \(2.85\)
4 \(2.68\)
PHXI02:UNITS AND MEASUREMENTS

367544 Assertion :
In Vernier Calliper if positive zero error exists, then while taking measurements, the reading taken will be more than the actual reading.
Reason :
The zero error in Vernier Calliper might have happened due to manufacturing defect or due to rough handling.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI02:UNITS AND MEASUREMENTS

367545 The Vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 \(mm\), then the least count of the microscope is

1 \(0.01\,mm\)
2 \(0.5\,cm\)
3 \(0.01\,cm\)
4 \(0.5\,mm\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI02:UNITS AND MEASUREMENTS

367541 The length of a strip measured with a metre rod is 10.0 \(cm\). Its width measured with a vernier callipers is 1.00 \(cm\). The least count of the metre rod is 0.1 \(cm\) and that of vernier calliper is 0.01 \(cm\). What will be the error in its area?

1 \( \pm 0.01\,c{m^2}\)
2 \( \pm 0.1\,c{m^2}\)
3 \( \pm 0.1\,1c{m^2}\)
4 \( \pm 0.2c{m^2}\)
PHXI02:UNITS AND MEASUREMENTS

367542 In a vernier callipers, \({(N+1)}\) divisions of vernier scale coincide with \({N}\) divisions of main scale. If 1 MSD represents \(0.1\,mm\), the vernier constant (in \(cm\)) is:

1 \({\dfrac{1}{10 {~N}}}\)
2 \({\dfrac{1}{100(N+1)}}\)
3 \(100\,N\)
4 \({10(N+1)}\)
PHXI02:UNITS AND MEASUREMENTS

367543 There is a vernier callipers which has 1 \(cm\) divided into 10 equal divisions on the main scale. The vernier scale (\(C\)) has 10 equal divisions that correspond to 9 main scale divisions. The measured value (in \(cm\)) by callipers \(C\) is
supporting img

1 \(2.87\)
2 \(2.78\)
3 \(2.85\)
4 \(2.68\)
PHXI02:UNITS AND MEASUREMENTS

367544 Assertion :
In Vernier Calliper if positive zero error exists, then while taking measurements, the reading taken will be more than the actual reading.
Reason :
The zero error in Vernier Calliper might have happened due to manufacturing defect or due to rough handling.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI02:UNITS AND MEASUREMENTS

367545 The Vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 \(mm\), then the least count of the microscope is

1 \(0.01\,mm\)
2 \(0.5\,cm\)
3 \(0.01\,cm\)
4 \(0.5\,mm\)
PHXI02:UNITS AND MEASUREMENTS

367541 The length of a strip measured with a metre rod is 10.0 \(cm\). Its width measured with a vernier callipers is 1.00 \(cm\). The least count of the metre rod is 0.1 \(cm\) and that of vernier calliper is 0.01 \(cm\). What will be the error in its area?

1 \( \pm 0.01\,c{m^2}\)
2 \( \pm 0.1\,c{m^2}\)
3 \( \pm 0.1\,1c{m^2}\)
4 \( \pm 0.2c{m^2}\)
PHXI02:UNITS AND MEASUREMENTS

367542 In a vernier callipers, \({(N+1)}\) divisions of vernier scale coincide with \({N}\) divisions of main scale. If 1 MSD represents \(0.1\,mm\), the vernier constant (in \(cm\)) is:

1 \({\dfrac{1}{10 {~N}}}\)
2 \({\dfrac{1}{100(N+1)}}\)
3 \(100\,N\)
4 \({10(N+1)}\)
PHXI02:UNITS AND MEASUREMENTS

367543 There is a vernier callipers which has 1 \(cm\) divided into 10 equal divisions on the main scale. The vernier scale (\(C\)) has 10 equal divisions that correspond to 9 main scale divisions. The measured value (in \(cm\)) by callipers \(C\) is
supporting img

1 \(2.87\)
2 \(2.78\)
3 \(2.85\)
4 \(2.68\)
PHXI02:UNITS AND MEASUREMENTS

367544 Assertion :
In Vernier Calliper if positive zero error exists, then while taking measurements, the reading taken will be more than the actual reading.
Reason :
The zero error in Vernier Calliper might have happened due to manufacturing defect or due to rough handling.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI02:UNITS AND MEASUREMENTS

367545 The Vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 \(mm\), then the least count of the microscope is

1 \(0.01\,mm\)
2 \(0.5\,cm\)
3 \(0.01\,cm\)
4 \(0.5\,mm\)