367517 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is \(20.0\;cm\) known to \(1\;mm\) accuracy and time for 100 oscillations of the pendulum is found to be \(80\;s\) using a wrist watch of \(1\;s\) accuracy. What will be the accuracy in the determination of \(g\) ?
367517 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is \(20.0\;cm\) known to \(1\;mm\) accuracy and time for 100 oscillations of the pendulum is found to be \(80\;s\) using a wrist watch of \(1\;s\) accuracy. What will be the accuracy in the determination of \(g\) ?
367517 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is \(20.0\;cm\) known to \(1\;mm\) accuracy and time for 100 oscillations of the pendulum is found to be \(80\;s\) using a wrist watch of \(1\;s\) accuracy. What will be the accuracy in the determination of \(g\) ?
367517 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is \(20.0\;cm\) known to \(1\;mm\) accuracy and time for 100 oscillations of the pendulum is found to be \(80\;s\) using a wrist watch of \(1\;s\) accuracy. What will be the accuracy in the determination of \(g\) ?