366341 \(2\;kg\) of ice at \( - 20^\circ C\) is mixed with \(5\;kg\) of water at \(20^\circ C\) in an insulating vessel having negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are 1
\(kcal/kg\,per\,^\circ C\) and \(0.5kcal/kg/\,^\circ C\) while the latent heat of fusion of ice is \(80\,kcal/kg\)

366342 An indian pitcher has \(10\;kg\) of water. Water cools by means of evaporation through the pores. Find the time in which the temperature of water falls by \(5^\circ C.\) The rate of vaporisation is \(5\;g\;{\min ^{ - 1}}\)

366343 In a pressure cooker, the cooking is fast, because

366344 Equal masses of ice and water with temperature equally below and above the melting point of ice respectively are mixed with each other. At equilibrium \(40 \%\) of the ice melted. The initial temperature of water was

366345 A piece of ice falls from a height \(h\) so that it melts completely. Only one-quater of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of \(h\) is (Latent heat of ice is \(3.4 \times {10^5}\;J/kg\) and \(g = 10\;N/kg)\)

366341 \(2\;kg\) of ice at \( - 20^\circ C\) is mixed with \(5\;kg\) of water at \(20^\circ C\) in an insulating vessel having negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are 1
\(kcal/kg\,per\,^\circ C\) and \(0.5kcal/kg/\,^\circ C\) while the latent heat of fusion of ice is \(80\,kcal/kg\)

366342 An indian pitcher has \(10\;kg\) of water. Water cools by means of evaporation through the pores. Find the time in which the temperature of water falls by \(5^\circ C.\) The rate of vaporisation is \(5\;g\;{\min ^{ - 1}}\)

366343 In a pressure cooker, the cooking is fast, because

366344 Equal masses of ice and water with temperature equally below and above the melting point of ice respectively are mixed with each other. At equilibrium \(40 \%\) of the ice melted. The initial temperature of water was

366345 A piece of ice falls from a height \(h\) so that it melts completely. Only one-quater of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of \(h\) is (Latent heat of ice is \(3.4 \times {10^5}\;J/kg\) and \(g = 10\;N/kg)\)

366341 \(2\;kg\) of ice at \( - 20^\circ C\) is mixed with \(5\;kg\) of water at \(20^\circ C\) in an insulating vessel having negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are 1
\(kcal/kg\,per\,^\circ C\) and \(0.5kcal/kg/\,^\circ C\) while the latent heat of fusion of ice is \(80\,kcal/kg\)

366342 An indian pitcher has \(10\;kg\) of water. Water cools by means of evaporation through the pores. Find the time in which the temperature of water falls by \(5^\circ C.\) The rate of vaporisation is \(5\;g\;{\min ^{ - 1}}\)

366343 In a pressure cooker, the cooking is fast, because

366344 Equal masses of ice and water with temperature equally below and above the melting point of ice respectively are mixed with each other. At equilibrium \(40 \%\) of the ice melted. The initial temperature of water was

366345 A piece of ice falls from a height \(h\) so that it melts completely. Only one-quater of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of \(h\) is (Latent heat of ice is \(3.4 \times {10^5}\;J/kg\) and \(g = 10\;N/kg)\)

366341 \(2\;kg\) of ice at \( - 20^\circ C\) is mixed with \(5\;kg\) of water at \(20^\circ C\) in an insulating vessel having negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are 1
\(kcal/kg\,per\,^\circ C\) and \(0.5kcal/kg/\,^\circ C\) while the latent heat of fusion of ice is \(80\,kcal/kg\)

366342 An indian pitcher has \(10\;kg\) of water. Water cools by means of evaporation through the pores. Find the time in which the temperature of water falls by \(5^\circ C.\) The rate of vaporisation is \(5\;g\;{\min ^{ - 1}}\)

366343 In a pressure cooker, the cooking is fast, because

366344 Equal masses of ice and water with temperature equally below and above the melting point of ice respectively are mixed with each other. At equilibrium \(40 \%\) of the ice melted. The initial temperature of water was

366345 A piece of ice falls from a height \(h\) so that it melts completely. Only one-quater of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of \(h\) is (Latent heat of ice is \(3.4 \times {10^5}\;J/kg\) and \(g = 10\;N/kg)\)

366341 \(2\;kg\) of ice at \( - 20^\circ C\) is mixed with \(5\;kg\) of water at \(20^\circ C\) in an insulating vessel having negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are 1
\(kcal/kg\,per\,^\circ C\) and \(0.5kcal/kg/\,^\circ C\) while the latent heat of fusion of ice is \(80\,kcal/kg\)

366342 An indian pitcher has \(10\;kg\) of water. Water cools by means of evaporation through the pores. Find the time in which the temperature of water falls by \(5^\circ C.\) The rate of vaporisation is \(5\;g\;{\min ^{ - 1}}\)

366343 In a pressure cooker, the cooking is fast, because

366344 Equal masses of ice and water with temperature equally below and above the melting point of ice respectively are mixed with each other. At equilibrium \(40 \%\) of the ice melted. The initial temperature of water was

366345 A piece of ice falls from a height \(h\) so that it melts completely. Only one-quater of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of \(h\) is (Latent heat of ice is \(3.4 \times {10^5}\;J/kg\) and \(g = 10\;N/kg)\)