363884
In nuclear reaction, \(_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}}{ + _a}{M^b}\) Where \(M\) denotes
1 electron
2 poistron
3 proton
4 neutron
Explanation:
Applying charge and mass conservation \(4 + A = A + 3 + b \Rightarrow b = 1\) \(2 + Z = Z + 2 + a \Rightarrow a = 0\) Hence, \(M\) is neutron.
PHXII13:NUCLEI
363885
The electron emitted in beta radiation originates from
1 inner orbits of atoms
2 free electron existing in nuclei
3 decay of neutron in the nucleus
4 photon escaping from the nucleus
Explanation:
The electron emitted by beta radiation originates from decay of neutron in the nucleus.
PHXII13:NUCLEI
363886
Assertion : In \(\alpha\) -decay, atomic number of daughter nucleus reduces by a unit from the parents nucleus. Reason : An \(\alpha\) -particle carries four units of mass.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In \(\alpha\)-decay, the atomic number (the number of protons) of the daughter nucleus decreases by 2 units, not by 1 unit. So, the assertion is not correct. An \(\alpha\)-particle consists of two protons and two neutrons, which gives it a mass of four atomic mass units (amu). This is a valid and accurate statement. So option (4) is correct.
AIIMS - 2017
PHXII13:NUCLEI
363887
A radioactive nucleus undergoes a series of decay according to the scheme If the mass number and atomic number of ' \(A\) ' are 180 and 72 respectively, then what are these numbers for \({A_4}\)
363884
In nuclear reaction, \(_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}}{ + _a}{M^b}\) Where \(M\) denotes
1 electron
2 poistron
3 proton
4 neutron
Explanation:
Applying charge and mass conservation \(4 + A = A + 3 + b \Rightarrow b = 1\) \(2 + Z = Z + 2 + a \Rightarrow a = 0\) Hence, \(M\) is neutron.
PHXII13:NUCLEI
363885
The electron emitted in beta radiation originates from
1 inner orbits of atoms
2 free electron existing in nuclei
3 decay of neutron in the nucleus
4 photon escaping from the nucleus
Explanation:
The electron emitted by beta radiation originates from decay of neutron in the nucleus.
PHXII13:NUCLEI
363886
Assertion : In \(\alpha\) -decay, atomic number of daughter nucleus reduces by a unit from the parents nucleus. Reason : An \(\alpha\) -particle carries four units of mass.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In \(\alpha\)-decay, the atomic number (the number of protons) of the daughter nucleus decreases by 2 units, not by 1 unit. So, the assertion is not correct. An \(\alpha\)-particle consists of two protons and two neutrons, which gives it a mass of four atomic mass units (amu). This is a valid and accurate statement. So option (4) is correct.
AIIMS - 2017
PHXII13:NUCLEI
363887
A radioactive nucleus undergoes a series of decay according to the scheme If the mass number and atomic number of ' \(A\) ' are 180 and 72 respectively, then what are these numbers for \({A_4}\)
363884
In nuclear reaction, \(_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}}{ + _a}{M^b}\) Where \(M\) denotes
1 electron
2 poistron
3 proton
4 neutron
Explanation:
Applying charge and mass conservation \(4 + A = A + 3 + b \Rightarrow b = 1\) \(2 + Z = Z + 2 + a \Rightarrow a = 0\) Hence, \(M\) is neutron.
PHXII13:NUCLEI
363885
The electron emitted in beta radiation originates from
1 inner orbits of atoms
2 free electron existing in nuclei
3 decay of neutron in the nucleus
4 photon escaping from the nucleus
Explanation:
The electron emitted by beta radiation originates from decay of neutron in the nucleus.
PHXII13:NUCLEI
363886
Assertion : In \(\alpha\) -decay, atomic number of daughter nucleus reduces by a unit from the parents nucleus. Reason : An \(\alpha\) -particle carries four units of mass.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In \(\alpha\)-decay, the atomic number (the number of protons) of the daughter nucleus decreases by 2 units, not by 1 unit. So, the assertion is not correct. An \(\alpha\)-particle consists of two protons and two neutrons, which gives it a mass of four atomic mass units (amu). This is a valid and accurate statement. So option (4) is correct.
AIIMS - 2017
PHXII13:NUCLEI
363887
A radioactive nucleus undergoes a series of decay according to the scheme If the mass number and atomic number of ' \(A\) ' are 180 and 72 respectively, then what are these numbers for \({A_4}\)
363884
In nuclear reaction, \(_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}}{ + _a}{M^b}\) Where \(M\) denotes
1 electron
2 poistron
3 proton
4 neutron
Explanation:
Applying charge and mass conservation \(4 + A = A + 3 + b \Rightarrow b = 1\) \(2 + Z = Z + 2 + a \Rightarrow a = 0\) Hence, \(M\) is neutron.
PHXII13:NUCLEI
363885
The electron emitted in beta radiation originates from
1 inner orbits of atoms
2 free electron existing in nuclei
3 decay of neutron in the nucleus
4 photon escaping from the nucleus
Explanation:
The electron emitted by beta radiation originates from decay of neutron in the nucleus.
PHXII13:NUCLEI
363886
Assertion : In \(\alpha\) -decay, atomic number of daughter nucleus reduces by a unit from the parents nucleus. Reason : An \(\alpha\) -particle carries four units of mass.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In \(\alpha\)-decay, the atomic number (the number of protons) of the daughter nucleus decreases by 2 units, not by 1 unit. So, the assertion is not correct. An \(\alpha\)-particle consists of two protons and two neutrons, which gives it a mass of four atomic mass units (amu). This is a valid and accurate statement. So option (4) is correct.
AIIMS - 2017
PHXII13:NUCLEI
363887
A radioactive nucleus undergoes a series of decay according to the scheme If the mass number and atomic number of ' \(A\) ' are 180 and 72 respectively, then what are these numbers for \({A_4}\)
