363822
Match the following nuclei with the type of characteristic shown. Column I Column II A Isotopes P \(_8{O^{18}}{,_9}{F^{19}}\) B Isobars Q \(_8{O^{17}}{,_9}{F^{17}}\) C Isotones R \(_{92}{U^{235}}{,_{92}}{U^{237}}\)
1 A - P B - R C - Q
2 A - Q B - P C - R
3 A - R B - Q C - P
4 A - R B - P C - Q
Explanation:
For \(_{92}^{235}{\text{U}}\) and \(_{92}^{237}{\text{U}}\), \(Z = 92\); Number of protons equal are isotopes. In \(_8^{17}{\text{O}}\) and \(_9^{17}{\text{F}}\), \(A = 17\), Mass numbers are same \( \Rightarrow \) Isobars. In \(_8^{18}{\text{O}}\) and \(_9^{19}{\text{F}}\), \(N = A - Z = 10\) for both Since, number of neutrons are same, so there are isotones.
PHXII13:NUCLEI
363823
In \({ }_{88} R a^{226}\) nucleus, there are:
1 138 protons and 88 neutrons
2 138 neutrons and 88 protons
3 226 protons and 88 electrons
4 226 neutrons and 88 electrons
Explanation:
\({ }_{Z} X^{A}={ }_{88} R a^{226}\) Number of protons \(Z=88\) Number of neutrons \(=A=Z=226-88=138\).
PHXII13:NUCLEI
363824
Assertion : For the scattering of \(\alpha\)-particles at large angles, only the nucleus of the atom is responsible. Reason : Nucleus is very heavy in comparison to electrons.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that electrons are considerably lighter than \(\alpha\)-particles. Therefore, according to the law of conservation of momentum, electrons cannot scatter \(\alpha\)-particles at large angles. But, the mass of the atomic nucleus is comparable to that of the \(\alpha\)-particle, which is why the nucleus alone is accountable for the scattering of \(\alpha\)-particles. So correct option is (1).
PHXII13:NUCLEI
363825
If the mass number of an atom is \(A=40\) and its electron configuration is \(1\,{s^2},2\,{s^2},2\,{p^6},3\,{s^2},3\,{p^6}\), the number of neutrons and protons in its nucleus will be:
1 22,18
2 18,22
3 20,20
4 18,18
Explanation:
No. of protons \(=2+2+6+2+6=18\) No. of neutrons \(=40-18=22\).
363822
Match the following nuclei with the type of characteristic shown. Column I Column II A Isotopes P \(_8{O^{18}}{,_9}{F^{19}}\) B Isobars Q \(_8{O^{17}}{,_9}{F^{17}}\) C Isotones R \(_{92}{U^{235}}{,_{92}}{U^{237}}\)
1 A - P B - R C - Q
2 A - Q B - P C - R
3 A - R B - Q C - P
4 A - R B - P C - Q
Explanation:
For \(_{92}^{235}{\text{U}}\) and \(_{92}^{237}{\text{U}}\), \(Z = 92\); Number of protons equal are isotopes. In \(_8^{17}{\text{O}}\) and \(_9^{17}{\text{F}}\), \(A = 17\), Mass numbers are same \( \Rightarrow \) Isobars. In \(_8^{18}{\text{O}}\) and \(_9^{19}{\text{F}}\), \(N = A - Z = 10\) for both Since, number of neutrons are same, so there are isotones.
PHXII13:NUCLEI
363823
In \({ }_{88} R a^{226}\) nucleus, there are:
1 138 protons and 88 neutrons
2 138 neutrons and 88 protons
3 226 protons and 88 electrons
4 226 neutrons and 88 electrons
Explanation:
\({ }_{Z} X^{A}={ }_{88} R a^{226}\) Number of protons \(Z=88\) Number of neutrons \(=A=Z=226-88=138\).
PHXII13:NUCLEI
363824
Assertion : For the scattering of \(\alpha\)-particles at large angles, only the nucleus of the atom is responsible. Reason : Nucleus is very heavy in comparison to electrons.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that electrons are considerably lighter than \(\alpha\)-particles. Therefore, according to the law of conservation of momentum, electrons cannot scatter \(\alpha\)-particles at large angles. But, the mass of the atomic nucleus is comparable to that of the \(\alpha\)-particle, which is why the nucleus alone is accountable for the scattering of \(\alpha\)-particles. So correct option is (1).
PHXII13:NUCLEI
363825
If the mass number of an atom is \(A=40\) and its electron configuration is \(1\,{s^2},2\,{s^2},2\,{p^6},3\,{s^2},3\,{p^6}\), the number of neutrons and protons in its nucleus will be:
1 22,18
2 18,22
3 20,20
4 18,18
Explanation:
No. of protons \(=2+2+6+2+6=18\) No. of neutrons \(=40-18=22\).
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PHXII13:NUCLEI
363822
Match the following nuclei with the type of characteristic shown. Column I Column II A Isotopes P \(_8{O^{18}}{,_9}{F^{19}}\) B Isobars Q \(_8{O^{17}}{,_9}{F^{17}}\) C Isotones R \(_{92}{U^{235}}{,_{92}}{U^{237}}\)
1 A - P B - R C - Q
2 A - Q B - P C - R
3 A - R B - Q C - P
4 A - R B - P C - Q
Explanation:
For \(_{92}^{235}{\text{U}}\) and \(_{92}^{237}{\text{U}}\), \(Z = 92\); Number of protons equal are isotopes. In \(_8^{17}{\text{O}}\) and \(_9^{17}{\text{F}}\), \(A = 17\), Mass numbers are same \( \Rightarrow \) Isobars. In \(_8^{18}{\text{O}}\) and \(_9^{19}{\text{F}}\), \(N = A - Z = 10\) for both Since, number of neutrons are same, so there are isotones.
PHXII13:NUCLEI
363823
In \({ }_{88} R a^{226}\) nucleus, there are:
1 138 protons and 88 neutrons
2 138 neutrons and 88 protons
3 226 protons and 88 electrons
4 226 neutrons and 88 electrons
Explanation:
\({ }_{Z} X^{A}={ }_{88} R a^{226}\) Number of protons \(Z=88\) Number of neutrons \(=A=Z=226-88=138\).
PHXII13:NUCLEI
363824
Assertion : For the scattering of \(\alpha\)-particles at large angles, only the nucleus of the atom is responsible. Reason : Nucleus is very heavy in comparison to electrons.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that electrons are considerably lighter than \(\alpha\)-particles. Therefore, according to the law of conservation of momentum, electrons cannot scatter \(\alpha\)-particles at large angles. But, the mass of the atomic nucleus is comparable to that of the \(\alpha\)-particle, which is why the nucleus alone is accountable for the scattering of \(\alpha\)-particles. So correct option is (1).
PHXII13:NUCLEI
363825
If the mass number of an atom is \(A=40\) and its electron configuration is \(1\,{s^2},2\,{s^2},2\,{p^6},3\,{s^2},3\,{p^6}\), the number of neutrons and protons in its nucleus will be:
1 22,18
2 18,22
3 20,20
4 18,18
Explanation:
No. of protons \(=2+2+6+2+6=18\) No. of neutrons \(=40-18=22\).
363822
Match the following nuclei with the type of characteristic shown. Column I Column II A Isotopes P \(_8{O^{18}}{,_9}{F^{19}}\) B Isobars Q \(_8{O^{17}}{,_9}{F^{17}}\) C Isotones R \(_{92}{U^{235}}{,_{92}}{U^{237}}\)
1 A - P B - R C - Q
2 A - Q B - P C - R
3 A - R B - Q C - P
4 A - R B - P C - Q
Explanation:
For \(_{92}^{235}{\text{U}}\) and \(_{92}^{237}{\text{U}}\), \(Z = 92\); Number of protons equal are isotopes. In \(_8^{17}{\text{O}}\) and \(_9^{17}{\text{F}}\), \(A = 17\), Mass numbers are same \( \Rightarrow \) Isobars. In \(_8^{18}{\text{O}}\) and \(_9^{19}{\text{F}}\), \(N = A - Z = 10\) for both Since, number of neutrons are same, so there are isotones.
PHXII13:NUCLEI
363823
In \({ }_{88} R a^{226}\) nucleus, there are:
1 138 protons and 88 neutrons
2 138 neutrons and 88 protons
3 226 protons and 88 electrons
4 226 neutrons and 88 electrons
Explanation:
\({ }_{Z} X^{A}={ }_{88} R a^{226}\) Number of protons \(Z=88\) Number of neutrons \(=A=Z=226-88=138\).
PHXII13:NUCLEI
363824
Assertion : For the scattering of \(\alpha\)-particles at large angles, only the nucleus of the atom is responsible. Reason : Nucleus is very heavy in comparison to electrons.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that electrons are considerably lighter than \(\alpha\)-particles. Therefore, according to the law of conservation of momentum, electrons cannot scatter \(\alpha\)-particles at large angles. But, the mass of the atomic nucleus is comparable to that of the \(\alpha\)-particle, which is why the nucleus alone is accountable for the scattering of \(\alpha\)-particles. So correct option is (1).
PHXII13:NUCLEI
363825
If the mass number of an atom is \(A=40\) and its electron configuration is \(1\,{s^2},2\,{s^2},2\,{p^6},3\,{s^2},3\,{p^6}\), the number of neutrons and protons in its nucleus will be:
1 22,18
2 18,22
3 20,20
4 18,18
Explanation:
No. of protons \(=2+2+6+2+6=18\) No. of neutrons \(=40-18=22\).
363822
Match the following nuclei with the type of characteristic shown. Column I Column II A Isotopes P \(_8{O^{18}}{,_9}{F^{19}}\) B Isobars Q \(_8{O^{17}}{,_9}{F^{17}}\) C Isotones R \(_{92}{U^{235}}{,_{92}}{U^{237}}\)
1 A - P B - R C - Q
2 A - Q B - P C - R
3 A - R B - Q C - P
4 A - R B - P C - Q
Explanation:
For \(_{92}^{235}{\text{U}}\) and \(_{92}^{237}{\text{U}}\), \(Z = 92\); Number of protons equal are isotopes. In \(_8^{17}{\text{O}}\) and \(_9^{17}{\text{F}}\), \(A = 17\), Mass numbers are same \( \Rightarrow \) Isobars. In \(_8^{18}{\text{O}}\) and \(_9^{19}{\text{F}}\), \(N = A - Z = 10\) for both Since, number of neutrons are same, so there are isotones.
PHXII13:NUCLEI
363823
In \({ }_{88} R a^{226}\) nucleus, there are:
1 138 protons and 88 neutrons
2 138 neutrons and 88 protons
3 226 protons and 88 electrons
4 226 neutrons and 88 electrons
Explanation:
\({ }_{Z} X^{A}={ }_{88} R a^{226}\) Number of protons \(Z=88\) Number of neutrons \(=A=Z=226-88=138\).
PHXII13:NUCLEI
363824
Assertion : For the scattering of \(\alpha\)-particles at large angles, only the nucleus of the atom is responsible. Reason : Nucleus is very heavy in comparison to electrons.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that electrons are considerably lighter than \(\alpha\)-particles. Therefore, according to the law of conservation of momentum, electrons cannot scatter \(\alpha\)-particles at large angles. But, the mass of the atomic nucleus is comparable to that of the \(\alpha\)-particle, which is why the nucleus alone is accountable for the scattering of \(\alpha\)-particles. So correct option is (1).
PHXII13:NUCLEI
363825
If the mass number of an atom is \(A=40\) and its electron configuration is \(1\,{s^2},2\,{s^2},2\,{p^6},3\,{s^2},3\,{p^6}\), the number of neutrons and protons in its nucleus will be:
1 22,18
2 18,22
3 20,20
4 18,18
Explanation:
No. of protons \(=2+2+6+2+6=18\) No. of neutrons \(=40-18=22\).