363634
Assume that a neutron breaks into a proton and an electron. The energy absorbed during this process is: (mass of neutron \( = 1.6725 \times {10^{ - 27}}kg,\) mass of proton \( = 1.6725 \times {10^{ - 27}}kg,\) mass of electron \( = 9 \times {10^{ - 31}}kg\)).
1 \( - 0.51\,MeV\)
2 \( - 7.10\,MeV\)
3 \( - 6.30\,MeV\)
4 \( - 5.4\,MeV\)
Explanation:
\({}_0^1n \to {}_1^1P{ + _{ - 1}}{e^0} + \bar v + Q\) The mass defect during the process \(\Delta m = {m_n} - {m_H} - {m_e} = 1.6725 \times {10^{27}}\) \( - (1.6725 \times {10^{ - 27}} + 9 \times {10^{ - 31}}kg)\) \( = - 9 \times {10^{ - 31}}kg\) Here \(\Delta m\) is \(( - )ve\) so the reaction absorbs energy.The energy absorbed during the process \(E = \Delta m{c^2}\) \(E = 9 \times {10^{ - 31}} \times 9 \times {10^{16}} = 81 \times {10^{ - 15}}{\text{joules}}\) \(E = \frac{{81 \times {{10}^{ - 15}}}}{{1.6 \times {{10}^{ - 19}}}} = 0.511{\mkern 1mu} \) \(Mev\) The correct answer is \( - 0.511\,MeV\)
PHXII13:NUCLEI
363635
The difference between the mass of a nucleus and the combined mass of its nucleons is
1 Zero, positive or negative
2 Zero
3 Positive
4 Negative
Explanation:
Mass of a nucleus is always less than the mass of its constituent nucleons.
PHXII13:NUCLEI
363636
\({6.4 \times 10^{-19}}\) joule is approximately
363634
Assume that a neutron breaks into a proton and an electron. The energy absorbed during this process is: (mass of neutron \( = 1.6725 \times {10^{ - 27}}kg,\) mass of proton \( = 1.6725 \times {10^{ - 27}}kg,\) mass of electron \( = 9 \times {10^{ - 31}}kg\)).
1 \( - 0.51\,MeV\)
2 \( - 7.10\,MeV\)
3 \( - 6.30\,MeV\)
4 \( - 5.4\,MeV\)
Explanation:
\({}_0^1n \to {}_1^1P{ + _{ - 1}}{e^0} + \bar v + Q\) The mass defect during the process \(\Delta m = {m_n} - {m_H} - {m_e} = 1.6725 \times {10^{27}}\) \( - (1.6725 \times {10^{ - 27}} + 9 \times {10^{ - 31}}kg)\) \( = - 9 \times {10^{ - 31}}kg\) Here \(\Delta m\) is \(( - )ve\) so the reaction absorbs energy.The energy absorbed during the process \(E = \Delta m{c^2}\) \(E = 9 \times {10^{ - 31}} \times 9 \times {10^{16}} = 81 \times {10^{ - 15}}{\text{joules}}\) \(E = \frac{{81 \times {{10}^{ - 15}}}}{{1.6 \times {{10}^{ - 19}}}} = 0.511{\mkern 1mu} \) \(Mev\) The correct answer is \( - 0.511\,MeV\)
PHXII13:NUCLEI
363635
The difference between the mass of a nucleus and the combined mass of its nucleons is
1 Zero, positive or negative
2 Zero
3 Positive
4 Negative
Explanation:
Mass of a nucleus is always less than the mass of its constituent nucleons.
PHXII13:NUCLEI
363636
\({6.4 \times 10^{-19}}\) joule is approximately
363634
Assume that a neutron breaks into a proton and an electron. The energy absorbed during this process is: (mass of neutron \( = 1.6725 \times {10^{ - 27}}kg,\) mass of proton \( = 1.6725 \times {10^{ - 27}}kg,\) mass of electron \( = 9 \times {10^{ - 31}}kg\)).
1 \( - 0.51\,MeV\)
2 \( - 7.10\,MeV\)
3 \( - 6.30\,MeV\)
4 \( - 5.4\,MeV\)
Explanation:
\({}_0^1n \to {}_1^1P{ + _{ - 1}}{e^0} + \bar v + Q\) The mass defect during the process \(\Delta m = {m_n} - {m_H} - {m_e} = 1.6725 \times {10^{27}}\) \( - (1.6725 \times {10^{ - 27}} + 9 \times {10^{ - 31}}kg)\) \( = - 9 \times {10^{ - 31}}kg\) Here \(\Delta m\) is \(( - )ve\) so the reaction absorbs energy.The energy absorbed during the process \(E = \Delta m{c^2}\) \(E = 9 \times {10^{ - 31}} \times 9 \times {10^{16}} = 81 \times {10^{ - 15}}{\text{joules}}\) \(E = \frac{{81 \times {{10}^{ - 15}}}}{{1.6 \times {{10}^{ - 19}}}} = 0.511{\mkern 1mu} \) \(Mev\) The correct answer is \( - 0.511\,MeV\)
PHXII13:NUCLEI
363635
The difference between the mass of a nucleus and the combined mass of its nucleons is
1 Zero, positive or negative
2 Zero
3 Positive
4 Negative
Explanation:
Mass of a nucleus is always less than the mass of its constituent nucleons.
PHXII13:NUCLEI
363636
\({6.4 \times 10^{-19}}\) joule is approximately
363634
Assume that a neutron breaks into a proton and an electron. The energy absorbed during this process is: (mass of neutron \( = 1.6725 \times {10^{ - 27}}kg,\) mass of proton \( = 1.6725 \times {10^{ - 27}}kg,\) mass of electron \( = 9 \times {10^{ - 31}}kg\)).
1 \( - 0.51\,MeV\)
2 \( - 7.10\,MeV\)
3 \( - 6.30\,MeV\)
4 \( - 5.4\,MeV\)
Explanation:
\({}_0^1n \to {}_1^1P{ + _{ - 1}}{e^0} + \bar v + Q\) The mass defect during the process \(\Delta m = {m_n} - {m_H} - {m_e} = 1.6725 \times {10^{27}}\) \( - (1.6725 \times {10^{ - 27}} + 9 \times {10^{ - 31}}kg)\) \( = - 9 \times {10^{ - 31}}kg\) Here \(\Delta m\) is \(( - )ve\) so the reaction absorbs energy.The energy absorbed during the process \(E = \Delta m{c^2}\) \(E = 9 \times {10^{ - 31}} \times 9 \times {10^{16}} = 81 \times {10^{ - 15}}{\text{joules}}\) \(E = \frac{{81 \times {{10}^{ - 15}}}}{{1.6 \times {{10}^{ - 19}}}} = 0.511{\mkern 1mu} \) \(Mev\) The correct answer is \( - 0.511\,MeV\)
PHXII13:NUCLEI
363635
The difference between the mass of a nucleus and the combined mass of its nucleons is
1 Zero, positive or negative
2 Zero
3 Positive
4 Negative
Explanation:
Mass of a nucleus is always less than the mass of its constituent nucleons.
PHXII13:NUCLEI
363636
\({6.4 \times 10^{-19}}\) joule is approximately
363634
Assume that a neutron breaks into a proton and an electron. The energy absorbed during this process is: (mass of neutron \( = 1.6725 \times {10^{ - 27}}kg,\) mass of proton \( = 1.6725 \times {10^{ - 27}}kg,\) mass of electron \( = 9 \times {10^{ - 31}}kg\)).
1 \( - 0.51\,MeV\)
2 \( - 7.10\,MeV\)
3 \( - 6.30\,MeV\)
4 \( - 5.4\,MeV\)
Explanation:
\({}_0^1n \to {}_1^1P{ + _{ - 1}}{e^0} + \bar v + Q\) The mass defect during the process \(\Delta m = {m_n} - {m_H} - {m_e} = 1.6725 \times {10^{27}}\) \( - (1.6725 \times {10^{ - 27}} + 9 \times {10^{ - 31}}kg)\) \( = - 9 \times {10^{ - 31}}kg\) Here \(\Delta m\) is \(( - )ve\) so the reaction absorbs energy.The energy absorbed during the process \(E = \Delta m{c^2}\) \(E = 9 \times {10^{ - 31}} \times 9 \times {10^{16}} = 81 \times {10^{ - 15}}{\text{joules}}\) \(E = \frac{{81 \times {{10}^{ - 15}}}}{{1.6 \times {{10}^{ - 19}}}} = 0.511{\mkern 1mu} \) \(Mev\) The correct answer is \( - 0.511\,MeV\)
PHXII13:NUCLEI
363635
The difference between the mass of a nucleus and the combined mass of its nucleons is
1 Zero, positive or negative
2 Zero
3 Positive
4 Negative
Explanation:
Mass of a nucleus is always less than the mass of its constituent nucleons.
PHXII13:NUCLEI
363636
\({6.4 \times 10^{-19}}\) joule is approximately
