363675
The mass defect for the nucleus of helium is \(0.0303\,amu\). What is the binding energy per nucleon for helium in \(MeV\) ?
1 28
2 7
3 4
4 1
Explanation:
\(BE = 0.0303\,amu \times \frac{{931MeV}}{{1\,amu}} = 28.2\,MeV.\) \(B E\) per nucleon for helium is\( = \frac{{28.2}}{4} = 7MeV\) nucleon as helium has mass number \(=4\). \({\text{So}},\,\,BE = 7\,MeV\,\,i.e.,\) correct option is (2).
PHXII13:NUCLEI
363676
Assume the graph of specific binding energy versus mass number is as shown in the figure. Using this graph, select the correct choice from the following:
1 Fusion of two nuclei of mass number lying in the range of 100 < A < 200 will release energy
2 Fusion of two nuclei of mass number lying in the range of 51 < A < 100 will release energy
3 Fusion of two nuclei of mass number lying in the range of 1< A < 50 will release energy
4 Fission of the nucleus of mass number lying in the range of 100 < A < 200 will release energy when broken into two fragments.
Explanation:
When two nuclei of mass number lying in the range of 51 < A < 100 are combined then a nucleus is formed in the range of 102 < A < 200 which has higher value of specific binding energy and therefore releases energy.
KCET - 2010
PHXII13:NUCLEI
363677
If \(M_{0}\) is the mass of an oxygen isotope \({ }_{8} O^{17}, M_{p}\) and \(M_{n}\) masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is
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PHXII13:NUCLEI
363675
The mass defect for the nucleus of helium is \(0.0303\,amu\). What is the binding energy per nucleon for helium in \(MeV\) ?
1 28
2 7
3 4
4 1
Explanation:
\(BE = 0.0303\,amu \times \frac{{931MeV}}{{1\,amu}} = 28.2\,MeV.\) \(B E\) per nucleon for helium is\( = \frac{{28.2}}{4} = 7MeV\) nucleon as helium has mass number \(=4\). \({\text{So}},\,\,BE = 7\,MeV\,\,i.e.,\) correct option is (2).
PHXII13:NUCLEI
363676
Assume the graph of specific binding energy versus mass number is as shown in the figure. Using this graph, select the correct choice from the following:
1 Fusion of two nuclei of mass number lying in the range of 100 < A < 200 will release energy
2 Fusion of two nuclei of mass number lying in the range of 51 < A < 100 will release energy
3 Fusion of two nuclei of mass number lying in the range of 1< A < 50 will release energy
4 Fission of the nucleus of mass number lying in the range of 100 < A < 200 will release energy when broken into two fragments.
Explanation:
When two nuclei of mass number lying in the range of 51 < A < 100 are combined then a nucleus is formed in the range of 102 < A < 200 which has higher value of specific binding energy and therefore releases energy.
KCET - 2010
PHXII13:NUCLEI
363677
If \(M_{0}\) is the mass of an oxygen isotope \({ }_{8} O^{17}, M_{p}\) and \(M_{n}\) masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is
363675
The mass defect for the nucleus of helium is \(0.0303\,amu\). What is the binding energy per nucleon for helium in \(MeV\) ?
1 28
2 7
3 4
4 1
Explanation:
\(BE = 0.0303\,amu \times \frac{{931MeV}}{{1\,amu}} = 28.2\,MeV.\) \(B E\) per nucleon for helium is\( = \frac{{28.2}}{4} = 7MeV\) nucleon as helium has mass number \(=4\). \({\text{So}},\,\,BE = 7\,MeV\,\,i.e.,\) correct option is (2).
PHXII13:NUCLEI
363676
Assume the graph of specific binding energy versus mass number is as shown in the figure. Using this graph, select the correct choice from the following:
1 Fusion of two nuclei of mass number lying in the range of 100 < A < 200 will release energy
2 Fusion of two nuclei of mass number lying in the range of 51 < A < 100 will release energy
3 Fusion of two nuclei of mass number lying in the range of 1< A < 50 will release energy
4 Fission of the nucleus of mass number lying in the range of 100 < A < 200 will release energy when broken into two fragments.
Explanation:
When two nuclei of mass number lying in the range of 51 < A < 100 are combined then a nucleus is formed in the range of 102 < A < 200 which has higher value of specific binding energy and therefore releases energy.
KCET - 2010
PHXII13:NUCLEI
363677
If \(M_{0}\) is the mass of an oxygen isotope \({ }_{8} O^{17}, M_{p}\) and \(M_{n}\) masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is
363675
The mass defect for the nucleus of helium is \(0.0303\,amu\). What is the binding energy per nucleon for helium in \(MeV\) ?
1 28
2 7
3 4
4 1
Explanation:
\(BE = 0.0303\,amu \times \frac{{931MeV}}{{1\,amu}} = 28.2\,MeV.\) \(B E\) per nucleon for helium is\( = \frac{{28.2}}{4} = 7MeV\) nucleon as helium has mass number \(=4\). \({\text{So}},\,\,BE = 7\,MeV\,\,i.e.,\) correct option is (2).
PHXII13:NUCLEI
363676
Assume the graph of specific binding energy versus mass number is as shown in the figure. Using this graph, select the correct choice from the following:
1 Fusion of two nuclei of mass number lying in the range of 100 < A < 200 will release energy
2 Fusion of two nuclei of mass number lying in the range of 51 < A < 100 will release energy
3 Fusion of two nuclei of mass number lying in the range of 1< A < 50 will release energy
4 Fission of the nucleus of mass number lying in the range of 100 < A < 200 will release energy when broken into two fragments.
Explanation:
When two nuclei of mass number lying in the range of 51 < A < 100 are combined then a nucleus is formed in the range of 102 < A < 200 which has higher value of specific binding energy and therefore releases energy.
KCET - 2010
PHXII13:NUCLEI
363677
If \(M_{0}\) is the mass of an oxygen isotope \({ }_{8} O^{17}, M_{p}\) and \(M_{n}\) masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is
