Newton’s Law of Motion
PHXI05:LAWS OF MOTION

363527 The linear momentum \(p\) of a body of mass 5 \(kg\) varies with times \(t\) as, \(p = 5{t^2} + t + 5\). It follows that the body is moving with:-

1 Constant speed
2 Constant acceleration
3 Variable acceleration which is decreasing with time
4 Variable acceleration which is increasing with time
PHXI05:LAWS OF MOTION

363528 A person says that he measured acceleration of a particle to be non-zero while no force is acting on the particle. Then,

1 He is a liar
2 His clock might have run slow
3 Mis meter scale might have been longer than the standard
4 He might have used non-inertial frame of reference
PHXI05:LAWS OF MOTION

363529 A body of mass 2 \(kg\) is acted upon by two forces each of magnitude 1 \(N\) and inclined at \(60^\circ \) with each other. The acceleration of the body in \(m\)/\(s\) is \(\left[ {\cos 60^\circ = 0.5} \right]\)

1 \(\sqrt {0.75} \)
2 \(\sqrt {0.65} \)
3 \(\sqrt {0.20} \)
4 \(\sqrt {0.35} \)
PHXI05:LAWS OF MOTION

363530 A force acts for \(20\;s\) on a body of mass \(20\;kg\), starting from rest, after which the force ceases and then body describes \(50\;m\) in the next \(10\;s\). The value of force will be

1 \(40\;N\)
2 \(20\;N\)
3 \(10\;N\)
4 \(5\;N\)
PHXI05:LAWS OF MOTION

363531 Formula for true force is

1 \(F = \frac{{mdv}}{{dt}}\)
2 \(F = ma\)
3 \(F = \frac{{m{d^2}x}}{{d{t^2}}}\)
4 \(F = \frac{{d(mv)}}{{dt}}\)
PHXI05:LAWS OF MOTION

363527 The linear momentum \(p\) of a body of mass 5 \(kg\) varies with times \(t\) as, \(p = 5{t^2} + t + 5\). It follows that the body is moving with:-

1 Constant speed
2 Constant acceleration
3 Variable acceleration which is decreasing with time
4 Variable acceleration which is increasing with time
PHXI05:LAWS OF MOTION

363528 A person says that he measured acceleration of a particle to be non-zero while no force is acting on the particle. Then,

1 He is a liar
2 His clock might have run slow
3 Mis meter scale might have been longer than the standard
4 He might have used non-inertial frame of reference
PHXI05:LAWS OF MOTION

363529 A body of mass 2 \(kg\) is acted upon by two forces each of magnitude 1 \(N\) and inclined at \(60^\circ \) with each other. The acceleration of the body in \(m\)/\(s\) is \(\left[ {\cos 60^\circ = 0.5} \right]\)

1 \(\sqrt {0.75} \)
2 \(\sqrt {0.65} \)
3 \(\sqrt {0.20} \)
4 \(\sqrt {0.35} \)
PHXI05:LAWS OF MOTION

363530 A force acts for \(20\;s\) on a body of mass \(20\;kg\), starting from rest, after which the force ceases and then body describes \(50\;m\) in the next \(10\;s\). The value of force will be

1 \(40\;N\)
2 \(20\;N\)
3 \(10\;N\)
4 \(5\;N\)
PHXI05:LAWS OF MOTION

363531 Formula for true force is

1 \(F = \frac{{mdv}}{{dt}}\)
2 \(F = ma\)
3 \(F = \frac{{m{d^2}x}}{{d{t^2}}}\)
4 \(F = \frac{{d(mv)}}{{dt}}\)
PHXI05:LAWS OF MOTION

363527 The linear momentum \(p\) of a body of mass 5 \(kg\) varies with times \(t\) as, \(p = 5{t^2} + t + 5\). It follows that the body is moving with:-

1 Constant speed
2 Constant acceleration
3 Variable acceleration which is decreasing with time
4 Variable acceleration which is increasing with time
PHXI05:LAWS OF MOTION

363528 A person says that he measured acceleration of a particle to be non-zero while no force is acting on the particle. Then,

1 He is a liar
2 His clock might have run slow
3 Mis meter scale might have been longer than the standard
4 He might have used non-inertial frame of reference
PHXI05:LAWS OF MOTION

363529 A body of mass 2 \(kg\) is acted upon by two forces each of magnitude 1 \(N\) and inclined at \(60^\circ \) with each other. The acceleration of the body in \(m\)/\(s\) is \(\left[ {\cos 60^\circ = 0.5} \right]\)

1 \(\sqrt {0.75} \)
2 \(\sqrt {0.65} \)
3 \(\sqrt {0.20} \)
4 \(\sqrt {0.35} \)
PHXI05:LAWS OF MOTION

363530 A force acts for \(20\;s\) on a body of mass \(20\;kg\), starting from rest, after which the force ceases and then body describes \(50\;m\) in the next \(10\;s\). The value of force will be

1 \(40\;N\)
2 \(20\;N\)
3 \(10\;N\)
4 \(5\;N\)
PHXI05:LAWS OF MOTION

363531 Formula for true force is

1 \(F = \frac{{mdv}}{{dt}}\)
2 \(F = ma\)
3 \(F = \frac{{m{d^2}x}}{{d{t^2}}}\)
4 \(F = \frac{{d(mv)}}{{dt}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI05:LAWS OF MOTION

363527 The linear momentum \(p\) of a body of mass 5 \(kg\) varies with times \(t\) as, \(p = 5{t^2} + t + 5\). It follows that the body is moving with:-

1 Constant speed
2 Constant acceleration
3 Variable acceleration which is decreasing with time
4 Variable acceleration which is increasing with time
PHXI05:LAWS OF MOTION

363528 A person says that he measured acceleration of a particle to be non-zero while no force is acting on the particle. Then,

1 He is a liar
2 His clock might have run slow
3 Mis meter scale might have been longer than the standard
4 He might have used non-inertial frame of reference
PHXI05:LAWS OF MOTION

363529 A body of mass 2 \(kg\) is acted upon by two forces each of magnitude 1 \(N\) and inclined at \(60^\circ \) with each other. The acceleration of the body in \(m\)/\(s\) is \(\left[ {\cos 60^\circ = 0.5} \right]\)

1 \(\sqrt {0.75} \)
2 \(\sqrt {0.65} \)
3 \(\sqrt {0.20} \)
4 \(\sqrt {0.35} \)
PHXI05:LAWS OF MOTION

363530 A force acts for \(20\;s\) on a body of mass \(20\;kg\), starting from rest, after which the force ceases and then body describes \(50\;m\) in the next \(10\;s\). The value of force will be

1 \(40\;N\)
2 \(20\;N\)
3 \(10\;N\)
4 \(5\;N\)
PHXI05:LAWS OF MOTION

363531 Formula for true force is

1 \(F = \frac{{mdv}}{{dt}}\)
2 \(F = ma\)
3 \(F = \frac{{m{d^2}x}}{{d{t^2}}}\)
4 \(F = \frac{{d(mv)}}{{dt}}\)
PHXI05:LAWS OF MOTION

363527 The linear momentum \(p\) of a body of mass 5 \(kg\) varies with times \(t\) as, \(p = 5{t^2} + t + 5\). It follows that the body is moving with:-

1 Constant speed
2 Constant acceleration
3 Variable acceleration which is decreasing with time
4 Variable acceleration which is increasing with time
PHXI05:LAWS OF MOTION

363528 A person says that he measured acceleration of a particle to be non-zero while no force is acting on the particle. Then,

1 He is a liar
2 His clock might have run slow
3 Mis meter scale might have been longer than the standard
4 He might have used non-inertial frame of reference
PHXI05:LAWS OF MOTION

363529 A body of mass 2 \(kg\) is acted upon by two forces each of magnitude 1 \(N\) and inclined at \(60^\circ \) with each other. The acceleration of the body in \(m\)/\(s\) is \(\left[ {\cos 60^\circ = 0.5} \right]\)

1 \(\sqrt {0.75} \)
2 \(\sqrt {0.65} \)
3 \(\sqrt {0.20} \)
4 \(\sqrt {0.35} \)
PHXI05:LAWS OF MOTION

363530 A force acts for \(20\;s\) on a body of mass \(20\;kg\), starting from rest, after which the force ceases and then body describes \(50\;m\) in the next \(10\;s\). The value of force will be

1 \(40\;N\)
2 \(20\;N\)
3 \(10\;N\)
4 \(5\;N\)
PHXI05:LAWS OF MOTION

363531 Formula for true force is

1 \(F = \frac{{mdv}}{{dt}}\)
2 \(F = ma\)
3 \(F = \frac{{m{d^2}x}}{{d{t^2}}}\)
4 \(F = \frac{{d(mv)}}{{dt}}\)