Explanation:
Given, \({F_1} = {F_2} = 1N\), \(m = 2\,kg\) and \(\theta = 60^\circ \)
Resultant force , \(F = \sqrt {F_1^2 + F_2^2 + 2{F_1}{F_2}\cos \theta } \)
\( = \sqrt {{1^2} + {1^2} + 2\cos 60^\circ } \)
\( = \sqrt {2 + 2\left( {0.5} \right)} = \sqrt 3 N\)
If the acceleration of the body is \(a\), then
\(ma = \sqrt 3 \)
or \(a = \frac{{\sqrt 3 }}{m} = \frac{{\sqrt 3 }}{2} = \sqrt {\frac{3}{4}} = \sqrt {0.75} m{s^{ - 2}}\)