Law of Conservation of Linear Momentum
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PHXI05:LAWS OF MOTION

363459 Conservation of momentum in a collision between particles can be understood from

1 Conservation of energy
2 Newton’s first law of energy
3 Newton’s second law only
4 Both Newton’s second and third law
NCERT Exemplar
PHXI05:LAWS OF MOTION

363460 A \(100\,kg\) gun fires a ball of \(1\,kg\) horizontally from a cliff of height \(500\,m.\) It falls on the ground at a distance of \(400\,m\) from the bottom of the cliff. The recoil velocity of the gun is (take, \(g = 10\;m{s^{ - 2}}\) )

1 \(0.2\;m{s^{ - 1}}\)
2 \(0.4\;m{s^{ - 1}}\)
3 \(0.6\;m{s^{ - 1}}\)
4 \(0.8\;m{s^{ - 1}}\)
PHXI05:LAWS OF MOTION

363461 A bullet of mass \(10 g\) is fired from a gun of mass \(1\,kg\) with recoil velocity of gun \(5\,m/s.\) The muzzle velocity will be

1 \(30\;km/\min \)
2 \(60\;km/\min \)
3 \(30\;m/s\)
4 \(500\;m/s\)
PHXI05:LAWS OF MOTION

363462 When a \({U^{238}}\) nucleus originally at rest, decays by emitting an alpha particle having speed ' \({u}\) ', then the recoil velocity of residual nucleus is :

1 \({-\dfrac{4 u}{238}}\)
2 \({\dfrac{4 u}{238}}\)
3 \({-\dfrac{4 u}{234}}\)
4 \({\dfrac{4 u}{234}}\)
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PHXI05:LAWS OF MOTION

363459 Conservation of momentum in a collision between particles can be understood from

1 Conservation of energy
2 Newton’s first law of energy
3 Newton’s second law only
4 Both Newton’s second and third law
NCERT Exemplar
PHXI05:LAWS OF MOTION

363460 A \(100\,kg\) gun fires a ball of \(1\,kg\) horizontally from a cliff of height \(500\,m.\) It falls on the ground at a distance of \(400\,m\) from the bottom of the cliff. The recoil velocity of the gun is (take, \(g = 10\;m{s^{ - 2}}\) )

1 \(0.2\;m{s^{ - 1}}\)
2 \(0.4\;m{s^{ - 1}}\)
3 \(0.6\;m{s^{ - 1}}\)
4 \(0.8\;m{s^{ - 1}}\)
PHXI05:LAWS OF MOTION

363461 A bullet of mass \(10 g\) is fired from a gun of mass \(1\,kg\) with recoil velocity of gun \(5\,m/s.\) The muzzle velocity will be

1 \(30\;km/\min \)
2 \(60\;km/\min \)
3 \(30\;m/s\)
4 \(500\;m/s\)
PHXI05:LAWS OF MOTION

363462 When a \({U^{238}}\) nucleus originally at rest, decays by emitting an alpha particle having speed ' \({u}\) ', then the recoil velocity of residual nucleus is :

1 \({-\dfrac{4 u}{238}}\)
2 \({\dfrac{4 u}{238}}\)
3 \({-\dfrac{4 u}{234}}\)
4 \({\dfrac{4 u}{234}}\)
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PHXI05:LAWS OF MOTION

363459 Conservation of momentum in a collision between particles can be understood from

1 Conservation of energy
2 Newton’s first law of energy
3 Newton’s second law only
4 Both Newton’s second and third law
NCERT Exemplar
PHXI05:LAWS OF MOTION

363460 A \(100\,kg\) gun fires a ball of \(1\,kg\) horizontally from a cliff of height \(500\,m.\) It falls on the ground at a distance of \(400\,m\) from the bottom of the cliff. The recoil velocity of the gun is (take, \(g = 10\;m{s^{ - 2}}\) )

1 \(0.2\;m{s^{ - 1}}\)
2 \(0.4\;m{s^{ - 1}}\)
3 \(0.6\;m{s^{ - 1}}\)
4 \(0.8\;m{s^{ - 1}}\)
PHXI05:LAWS OF MOTION

363461 A bullet of mass \(10 g\) is fired from a gun of mass \(1\,kg\) with recoil velocity of gun \(5\,m/s.\) The muzzle velocity will be

1 \(30\;km/\min \)
2 \(60\;km/\min \)
3 \(30\;m/s\)
4 \(500\;m/s\)
PHXI05:LAWS OF MOTION

363462 When a \({U^{238}}\) nucleus originally at rest, decays by emitting an alpha particle having speed ' \({u}\) ', then the recoil velocity of residual nucleus is :

1 \({-\dfrac{4 u}{238}}\)
2 \({\dfrac{4 u}{238}}\)
3 \({-\dfrac{4 u}{234}}\)
4 \({\dfrac{4 u}{234}}\)
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PHXI05:LAWS OF MOTION

363459 Conservation of momentum in a collision between particles can be understood from

1 Conservation of energy
2 Newton’s first law of energy
3 Newton’s second law only
4 Both Newton’s second and third law
NCERT Exemplar
PHXI05:LAWS OF MOTION

363460 A \(100\,kg\) gun fires a ball of \(1\,kg\) horizontally from a cliff of height \(500\,m.\) It falls on the ground at a distance of \(400\,m\) from the bottom of the cliff. The recoil velocity of the gun is (take, \(g = 10\;m{s^{ - 2}}\) )

1 \(0.2\;m{s^{ - 1}}\)
2 \(0.4\;m{s^{ - 1}}\)
3 \(0.6\;m{s^{ - 1}}\)
4 \(0.8\;m{s^{ - 1}}\)
PHXI05:LAWS OF MOTION

363461 A bullet of mass \(10 g\) is fired from a gun of mass \(1\,kg\) with recoil velocity of gun \(5\,m/s.\) The muzzle velocity will be

1 \(30\;km/\min \)
2 \(60\;km/\min \)
3 \(30\;m/s\)
4 \(500\;m/s\)
PHXI05:LAWS OF MOTION

363462 When a \({U^{238}}\) nucleus originally at rest, decays by emitting an alpha particle having speed ' \({u}\) ', then the recoil velocity of residual nucleus is :

1 \({-\dfrac{4 u}{238}}\)
2 \({\dfrac{4 u}{238}}\)
3 \({-\dfrac{4 u}{234}}\)
4 \({\dfrac{4 u}{234}}\)
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