Explanation:
Given that
\(m = 60\,kg\)
\(a = 1.8\,m{s^{ - 1}}\)
As the lift moving down with acceleration \(a\), the force exerted by the floor on the man is
\(N = mg - ma = m(g - a)\)
\( = (60\,kg)\,(9.8\,m{s^{ - 2}} - 1.8\,m{s^{ - 2}})\)
\( = (60\,kg)\,(8.0\,m{s^{ - 2}}) = 480\,N\)