362933
The shunt resistance required to allow \(4 \%\) of the main current through the galvanometer of resistance \(48 \Omega\) is
1 \(1 \Omega\)
2 \(2 \Omega\)
3 \(3 \Omega\)
4 \(4 \Omega\)
Explanation:
Here, resistance of galvanometer, \(G=48 \Omega\) \(I_{g}=\dfrac{4}{100} I=0.04 I\) Let \(S\) be required shunt. \(S=\dfrac{I_{g} G}{\left(I-I_{g}\right)}=\dfrac{0.04 I \times 48}{(I-0.04 I)}=\dfrac{0.04 \times 48}{0.96}=2 \Omega\)
PHXII04:MOVING CHARGES AND MAGNETISM
362934
To increase the range of an ammeter, we need to connect a suitable
1 Low resistance in parallel
2 Low resistance in series
3 High resistance in parallel
4 High resistance in series
Explanation:
Conceptual Question
PHXII04:MOVING CHARGES AND MAGNETISM
362935
Assertion : A galvanometer can be used in electric circuit to detect the electric current. Reason : A galvanometer can be used as an ammeter only.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
A galvanometer can indeed be used both as an ammeter and as a voltmeter. It can be used as an ammeter by connecting a low resistance in parallel with it, and as a voltmeter by connecting a high resistance in series with it. So correct option is (3).
PHXII04:MOVING CHARGES AND MAGNETISM
362936
In a galvanometer, \(5 \%\) of the total current in the circuit passes through it. If the resistance of the galvanometer is \(G\), the shunt resistance \(S\) connected to the galvanometer is
1 \(19 G\)
2 \(\dfrac{G}{19}\)
3 \(20 G\)
4 \(\dfrac{G}{20}\)
Explanation:
Current in galvanometer, \(i_{g}=\dfrac{5}{100} i\) \(\therefore\) Shunt resistance, \(S=\dfrac{i_{g} G}{i-i_{g}}=\dfrac{5 i / 100 G}{i-\left(\dfrac{5 i}{100}\right)}=\dfrac{G}{19}\)
PHXII04:MOVING CHARGES AND MAGNETISM
362937
A galvanometer has coil of resistane \(200\,\Omega \) with a full scale deflection at \(20\,\mu \;A.\) The value of resistance to be added to use it as an ammeter of range \((0-20) m A\) is
1 \(0.40\,\Omega \)
2 \(0.10\,\Omega \)
3 \(0.50\,\Omega \)
4 \(0.20\,\Omega \)
Explanation:
\(G = 200{\mkern 1mu} \,\Omega ,{\mkern 1mu} {\mkern 1mu} {\kern 1pt} \,\,{i_g} = 20\,\mu A\) Galvanometer can be converted into ammeter by putting a shunt resistance \(S\) in parallel.
362933
The shunt resistance required to allow \(4 \%\) of the main current through the galvanometer of resistance \(48 \Omega\) is
1 \(1 \Omega\)
2 \(2 \Omega\)
3 \(3 \Omega\)
4 \(4 \Omega\)
Explanation:
Here, resistance of galvanometer, \(G=48 \Omega\) \(I_{g}=\dfrac{4}{100} I=0.04 I\) Let \(S\) be required shunt. \(S=\dfrac{I_{g} G}{\left(I-I_{g}\right)}=\dfrac{0.04 I \times 48}{(I-0.04 I)}=\dfrac{0.04 \times 48}{0.96}=2 \Omega\)
PHXII04:MOVING CHARGES AND MAGNETISM
362934
To increase the range of an ammeter, we need to connect a suitable
1 Low resistance in parallel
2 Low resistance in series
3 High resistance in parallel
4 High resistance in series
Explanation:
Conceptual Question
PHXII04:MOVING CHARGES AND MAGNETISM
362935
Assertion : A galvanometer can be used in electric circuit to detect the electric current. Reason : A galvanometer can be used as an ammeter only.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
A galvanometer can indeed be used both as an ammeter and as a voltmeter. It can be used as an ammeter by connecting a low resistance in parallel with it, and as a voltmeter by connecting a high resistance in series with it. So correct option is (3).
PHXII04:MOVING CHARGES AND MAGNETISM
362936
In a galvanometer, \(5 \%\) of the total current in the circuit passes through it. If the resistance of the galvanometer is \(G\), the shunt resistance \(S\) connected to the galvanometer is
1 \(19 G\)
2 \(\dfrac{G}{19}\)
3 \(20 G\)
4 \(\dfrac{G}{20}\)
Explanation:
Current in galvanometer, \(i_{g}=\dfrac{5}{100} i\) \(\therefore\) Shunt resistance, \(S=\dfrac{i_{g} G}{i-i_{g}}=\dfrac{5 i / 100 G}{i-\left(\dfrac{5 i}{100}\right)}=\dfrac{G}{19}\)
PHXII04:MOVING CHARGES AND MAGNETISM
362937
A galvanometer has coil of resistane \(200\,\Omega \) with a full scale deflection at \(20\,\mu \;A.\) The value of resistance to be added to use it as an ammeter of range \((0-20) m A\) is
1 \(0.40\,\Omega \)
2 \(0.10\,\Omega \)
3 \(0.50\,\Omega \)
4 \(0.20\,\Omega \)
Explanation:
\(G = 200{\mkern 1mu} \,\Omega ,{\mkern 1mu} {\mkern 1mu} {\kern 1pt} \,\,{i_g} = 20\,\mu A\) Galvanometer can be converted into ammeter by putting a shunt resistance \(S\) in parallel.
362933
The shunt resistance required to allow \(4 \%\) of the main current through the galvanometer of resistance \(48 \Omega\) is
1 \(1 \Omega\)
2 \(2 \Omega\)
3 \(3 \Omega\)
4 \(4 \Omega\)
Explanation:
Here, resistance of galvanometer, \(G=48 \Omega\) \(I_{g}=\dfrac{4}{100} I=0.04 I\) Let \(S\) be required shunt. \(S=\dfrac{I_{g} G}{\left(I-I_{g}\right)}=\dfrac{0.04 I \times 48}{(I-0.04 I)}=\dfrac{0.04 \times 48}{0.96}=2 \Omega\)
PHXII04:MOVING CHARGES AND MAGNETISM
362934
To increase the range of an ammeter, we need to connect a suitable
1 Low resistance in parallel
2 Low resistance in series
3 High resistance in parallel
4 High resistance in series
Explanation:
Conceptual Question
PHXII04:MOVING CHARGES AND MAGNETISM
362935
Assertion : A galvanometer can be used in electric circuit to detect the electric current. Reason : A galvanometer can be used as an ammeter only.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
A galvanometer can indeed be used both as an ammeter and as a voltmeter. It can be used as an ammeter by connecting a low resistance in parallel with it, and as a voltmeter by connecting a high resistance in series with it. So correct option is (3).
PHXII04:MOVING CHARGES AND MAGNETISM
362936
In a galvanometer, \(5 \%\) of the total current in the circuit passes through it. If the resistance of the galvanometer is \(G\), the shunt resistance \(S\) connected to the galvanometer is
1 \(19 G\)
2 \(\dfrac{G}{19}\)
3 \(20 G\)
4 \(\dfrac{G}{20}\)
Explanation:
Current in galvanometer, \(i_{g}=\dfrac{5}{100} i\) \(\therefore\) Shunt resistance, \(S=\dfrac{i_{g} G}{i-i_{g}}=\dfrac{5 i / 100 G}{i-\left(\dfrac{5 i}{100}\right)}=\dfrac{G}{19}\)
PHXII04:MOVING CHARGES AND MAGNETISM
362937
A galvanometer has coil of resistane \(200\,\Omega \) with a full scale deflection at \(20\,\mu \;A.\) The value of resistance to be added to use it as an ammeter of range \((0-20) m A\) is
1 \(0.40\,\Omega \)
2 \(0.10\,\Omega \)
3 \(0.50\,\Omega \)
4 \(0.20\,\Omega \)
Explanation:
\(G = 200{\mkern 1mu} \,\Omega ,{\mkern 1mu} {\mkern 1mu} {\kern 1pt} \,\,{i_g} = 20\,\mu A\) Galvanometer can be converted into ammeter by putting a shunt resistance \(S\) in parallel.
362933
The shunt resistance required to allow \(4 \%\) of the main current through the galvanometer of resistance \(48 \Omega\) is
1 \(1 \Omega\)
2 \(2 \Omega\)
3 \(3 \Omega\)
4 \(4 \Omega\)
Explanation:
Here, resistance of galvanometer, \(G=48 \Omega\) \(I_{g}=\dfrac{4}{100} I=0.04 I\) Let \(S\) be required shunt. \(S=\dfrac{I_{g} G}{\left(I-I_{g}\right)}=\dfrac{0.04 I \times 48}{(I-0.04 I)}=\dfrac{0.04 \times 48}{0.96}=2 \Omega\)
PHXII04:MOVING CHARGES AND MAGNETISM
362934
To increase the range of an ammeter, we need to connect a suitable
1 Low resistance in parallel
2 Low resistance in series
3 High resistance in parallel
4 High resistance in series
Explanation:
Conceptual Question
PHXII04:MOVING CHARGES AND MAGNETISM
362935
Assertion : A galvanometer can be used in electric circuit to detect the electric current. Reason : A galvanometer can be used as an ammeter only.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
A galvanometer can indeed be used both as an ammeter and as a voltmeter. It can be used as an ammeter by connecting a low resistance in parallel with it, and as a voltmeter by connecting a high resistance in series with it. So correct option is (3).
PHXII04:MOVING CHARGES AND MAGNETISM
362936
In a galvanometer, \(5 \%\) of the total current in the circuit passes through it. If the resistance of the galvanometer is \(G\), the shunt resistance \(S\) connected to the galvanometer is
1 \(19 G\)
2 \(\dfrac{G}{19}\)
3 \(20 G\)
4 \(\dfrac{G}{20}\)
Explanation:
Current in galvanometer, \(i_{g}=\dfrac{5}{100} i\) \(\therefore\) Shunt resistance, \(S=\dfrac{i_{g} G}{i-i_{g}}=\dfrac{5 i / 100 G}{i-\left(\dfrac{5 i}{100}\right)}=\dfrac{G}{19}\)
PHXII04:MOVING CHARGES AND MAGNETISM
362937
A galvanometer has coil of resistane \(200\,\Omega \) with a full scale deflection at \(20\,\mu \;A.\) The value of resistance to be added to use it as an ammeter of range \((0-20) m A\) is
1 \(0.40\,\Omega \)
2 \(0.10\,\Omega \)
3 \(0.50\,\Omega \)
4 \(0.20\,\Omega \)
Explanation:
\(G = 200{\mkern 1mu} \,\Omega ,{\mkern 1mu} {\mkern 1mu} {\kern 1pt} \,\,{i_g} = 20\,\mu A\) Galvanometer can be converted into ammeter by putting a shunt resistance \(S\) in parallel.
362933
The shunt resistance required to allow \(4 \%\) of the main current through the galvanometer of resistance \(48 \Omega\) is
1 \(1 \Omega\)
2 \(2 \Omega\)
3 \(3 \Omega\)
4 \(4 \Omega\)
Explanation:
Here, resistance of galvanometer, \(G=48 \Omega\) \(I_{g}=\dfrac{4}{100} I=0.04 I\) Let \(S\) be required shunt. \(S=\dfrac{I_{g} G}{\left(I-I_{g}\right)}=\dfrac{0.04 I \times 48}{(I-0.04 I)}=\dfrac{0.04 \times 48}{0.96}=2 \Omega\)
PHXII04:MOVING CHARGES AND MAGNETISM
362934
To increase the range of an ammeter, we need to connect a suitable
1 Low resistance in parallel
2 Low resistance in series
3 High resistance in parallel
4 High resistance in series
Explanation:
Conceptual Question
PHXII04:MOVING CHARGES AND MAGNETISM
362935
Assertion : A galvanometer can be used in electric circuit to detect the electric current. Reason : A galvanometer can be used as an ammeter only.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
A galvanometer can indeed be used both as an ammeter and as a voltmeter. It can be used as an ammeter by connecting a low resistance in parallel with it, and as a voltmeter by connecting a high resistance in series with it. So correct option is (3).
PHXII04:MOVING CHARGES AND MAGNETISM
362936
In a galvanometer, \(5 \%\) of the total current in the circuit passes through it. If the resistance of the galvanometer is \(G\), the shunt resistance \(S\) connected to the galvanometer is
1 \(19 G\)
2 \(\dfrac{G}{19}\)
3 \(20 G\)
4 \(\dfrac{G}{20}\)
Explanation:
Current in galvanometer, \(i_{g}=\dfrac{5}{100} i\) \(\therefore\) Shunt resistance, \(S=\dfrac{i_{g} G}{i-i_{g}}=\dfrac{5 i / 100 G}{i-\left(\dfrac{5 i}{100}\right)}=\dfrac{G}{19}\)
PHXII04:MOVING CHARGES AND MAGNETISM
362937
A galvanometer has coil of resistane \(200\,\Omega \) with a full scale deflection at \(20\,\mu \;A.\) The value of resistance to be added to use it as an ammeter of range \((0-20) m A\) is
1 \(0.40\,\Omega \)
2 \(0.10\,\Omega \)
3 \(0.50\,\Omega \)
4 \(0.20\,\Omega \)
Explanation:
\(G = 200{\mkern 1mu} \,\Omega ,{\mkern 1mu} {\mkern 1mu} {\kern 1pt} \,\,{i_g} = 20\,\mu A\) Galvanometer can be converted into ammeter by putting a shunt resistance \(S\) in parallel.
