NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXI03:MOTION IN A STRAIGHT LINE
362263
A particle shows distance-time curve as shown in the figure. The maximum instantaneous velocity of the particle is around the point
1 \(P\)
2 \(S\)
3 \(R\)
4 \(Q\)
Explanation:
The slope of the tangent to the distance-time curve at any point gives the instantaneous velocity at that point. Thus, the maximum instantaneous velocity of the particle is aroud the point \(R\) as the slope is steepest at that point.
KCET - 2018
PHXI03:MOTION IN A STRAIGHT LINE
362264
Figure shows the position of a particle moving on \(x\)-axis as a function of time
1 The particle has come to rest 5 times
2 Initial speed of particle was zero
3 The velocity remains positive for \(t = 0\,s\) to \(t = 6s\)
4 The average velocity for the total period shown is negative
Explanation:
The slope of the tangent drawn to the curve is zero at five instants.
PHXI03:MOTION IN A STRAIGHT LINE
362265
Match Column-I with Column-II. Choose the correct answer from the options given below.
A-Q: The \(x-t\) graph may be described by the equation \(x=c t^{2}\) where \(e\) is a constant. \(\therefore v=\dfrac{d x}{d t}=2 c \cdot t\) which represents a straight line passing through the origin. B-S: The \(x-t\) graph may be described by the equation \(x=c / t_{3}\) where \(c\) is a constant. \(\therefore v=\dfrac{d x}{d t}=-\dfrac{c}{t^{2}}\) therefore \(v-t\) graph is correctly shown in option S. C-R: From the \(x-t\) graph, \(v=\) Slope of \(v-t\) graph \(=\dfrac{d x}{d t}=\) positive constant in the first half and negative constant in the second half. D-P: The \(x-t\) graph is a straight line with positive slope. \(\therefore v=\dfrac{d x}{d t}=\) slope of \(x-t\) graph \(=\) positive constant.
JEE - 2023
PHXI03:MOTION IN A STRAIGHT LINE
362266
The displacement of a particle as a function of time is in fig. The graph indicates that
1 The particle starts with a certain velocity, but the motion is retarded and finally the particle stops.
2 The velocity of particle is constant throughout motion.
3 The acceleration of the particle is constant throughout motion.
4 The particle starts with constant velocity, the motion is accelerated and finally the particle moves with another constant velocity.
Explanation:
The slope of the graph changes, decreases continuously \(\left( {\frac{{dx}}{{dt}} = v} \right)\) and finally it becomes zero.
362263
A particle shows distance-time curve as shown in the figure. The maximum instantaneous velocity of the particle is around the point
1 \(P\)
2 \(S\)
3 \(R\)
4 \(Q\)
Explanation:
The slope of the tangent to the distance-time curve at any point gives the instantaneous velocity at that point. Thus, the maximum instantaneous velocity of the particle is aroud the point \(R\) as the slope is steepest at that point.
KCET - 2018
PHXI03:MOTION IN A STRAIGHT LINE
362264
Figure shows the position of a particle moving on \(x\)-axis as a function of time
1 The particle has come to rest 5 times
2 Initial speed of particle was zero
3 The velocity remains positive for \(t = 0\,s\) to \(t = 6s\)
4 The average velocity for the total period shown is negative
Explanation:
The slope of the tangent drawn to the curve is zero at five instants.
PHXI03:MOTION IN A STRAIGHT LINE
362265
Match Column-I with Column-II. Choose the correct answer from the options given below.
A-Q: The \(x-t\) graph may be described by the equation \(x=c t^{2}\) where \(e\) is a constant. \(\therefore v=\dfrac{d x}{d t}=2 c \cdot t\) which represents a straight line passing through the origin. B-S: The \(x-t\) graph may be described by the equation \(x=c / t_{3}\) where \(c\) is a constant. \(\therefore v=\dfrac{d x}{d t}=-\dfrac{c}{t^{2}}\) therefore \(v-t\) graph is correctly shown in option S. C-R: From the \(x-t\) graph, \(v=\) Slope of \(v-t\) graph \(=\dfrac{d x}{d t}=\) positive constant in the first half and negative constant in the second half. D-P: The \(x-t\) graph is a straight line with positive slope. \(\therefore v=\dfrac{d x}{d t}=\) slope of \(x-t\) graph \(=\) positive constant.
JEE - 2023
PHXI03:MOTION IN A STRAIGHT LINE
362266
The displacement of a particle as a function of time is in fig. The graph indicates that
1 The particle starts with a certain velocity, but the motion is retarded and finally the particle stops.
2 The velocity of particle is constant throughout motion.
3 The acceleration of the particle is constant throughout motion.
4 The particle starts with constant velocity, the motion is accelerated and finally the particle moves with another constant velocity.
Explanation:
The slope of the graph changes, decreases continuously \(\left( {\frac{{dx}}{{dt}} = v} \right)\) and finally it becomes zero.
362263
A particle shows distance-time curve as shown in the figure. The maximum instantaneous velocity of the particle is around the point
1 \(P\)
2 \(S\)
3 \(R\)
4 \(Q\)
Explanation:
The slope of the tangent to the distance-time curve at any point gives the instantaneous velocity at that point. Thus, the maximum instantaneous velocity of the particle is aroud the point \(R\) as the slope is steepest at that point.
KCET - 2018
PHXI03:MOTION IN A STRAIGHT LINE
362264
Figure shows the position of a particle moving on \(x\)-axis as a function of time
1 The particle has come to rest 5 times
2 Initial speed of particle was zero
3 The velocity remains positive for \(t = 0\,s\) to \(t = 6s\)
4 The average velocity for the total period shown is negative
Explanation:
The slope of the tangent drawn to the curve is zero at five instants.
PHXI03:MOTION IN A STRAIGHT LINE
362265
Match Column-I with Column-II. Choose the correct answer from the options given below.
A-Q: The \(x-t\) graph may be described by the equation \(x=c t^{2}\) where \(e\) is a constant. \(\therefore v=\dfrac{d x}{d t}=2 c \cdot t\) which represents a straight line passing through the origin. B-S: The \(x-t\) graph may be described by the equation \(x=c / t_{3}\) where \(c\) is a constant. \(\therefore v=\dfrac{d x}{d t}=-\dfrac{c}{t^{2}}\) therefore \(v-t\) graph is correctly shown in option S. C-R: From the \(x-t\) graph, \(v=\) Slope of \(v-t\) graph \(=\dfrac{d x}{d t}=\) positive constant in the first half and negative constant in the second half. D-P: The \(x-t\) graph is a straight line with positive slope. \(\therefore v=\dfrac{d x}{d t}=\) slope of \(x-t\) graph \(=\) positive constant.
JEE - 2023
PHXI03:MOTION IN A STRAIGHT LINE
362266
The displacement of a particle as a function of time is in fig. The graph indicates that
1 The particle starts with a certain velocity, but the motion is retarded and finally the particle stops.
2 The velocity of particle is constant throughout motion.
3 The acceleration of the particle is constant throughout motion.
4 The particle starts with constant velocity, the motion is accelerated and finally the particle moves with another constant velocity.
Explanation:
The slope of the graph changes, decreases continuously \(\left( {\frac{{dx}}{{dt}} = v} \right)\) and finally it becomes zero.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXI03:MOTION IN A STRAIGHT LINE
362263
A particle shows distance-time curve as shown in the figure. The maximum instantaneous velocity of the particle is around the point
1 \(P\)
2 \(S\)
3 \(R\)
4 \(Q\)
Explanation:
The slope of the tangent to the distance-time curve at any point gives the instantaneous velocity at that point. Thus, the maximum instantaneous velocity of the particle is aroud the point \(R\) as the slope is steepest at that point.
KCET - 2018
PHXI03:MOTION IN A STRAIGHT LINE
362264
Figure shows the position of a particle moving on \(x\)-axis as a function of time
1 The particle has come to rest 5 times
2 Initial speed of particle was zero
3 The velocity remains positive for \(t = 0\,s\) to \(t = 6s\)
4 The average velocity for the total period shown is negative
Explanation:
The slope of the tangent drawn to the curve is zero at five instants.
PHXI03:MOTION IN A STRAIGHT LINE
362265
Match Column-I with Column-II. Choose the correct answer from the options given below.
A-Q: The \(x-t\) graph may be described by the equation \(x=c t^{2}\) where \(e\) is a constant. \(\therefore v=\dfrac{d x}{d t}=2 c \cdot t\) which represents a straight line passing through the origin. B-S: The \(x-t\) graph may be described by the equation \(x=c / t_{3}\) where \(c\) is a constant. \(\therefore v=\dfrac{d x}{d t}=-\dfrac{c}{t^{2}}\) therefore \(v-t\) graph is correctly shown in option S. C-R: From the \(x-t\) graph, \(v=\) Slope of \(v-t\) graph \(=\dfrac{d x}{d t}=\) positive constant in the first half and negative constant in the second half. D-P: The \(x-t\) graph is a straight line with positive slope. \(\therefore v=\dfrac{d x}{d t}=\) slope of \(x-t\) graph \(=\) positive constant.
JEE - 2023
PHXI03:MOTION IN A STRAIGHT LINE
362266
The displacement of a particle as a function of time is in fig. The graph indicates that
1 The particle starts with a certain velocity, but the motion is retarded and finally the particle stops.
2 The velocity of particle is constant throughout motion.
3 The acceleration of the particle is constant throughout motion.
4 The particle starts with constant velocity, the motion is accelerated and finally the particle moves with another constant velocity.
Explanation:
The slope of the graph changes, decreases continuously \(\left( {\frac{{dx}}{{dt}} = v} \right)\) and finally it becomes zero.
