Projectile – Oblique Projectile
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NEET DIGITAL LIBRARY
PHXI04:MOTION IN A PLANE

361965 A particle moving in a circle of radius \(R\) with a uniform speed takes a time \(T\) to complete one revolution. If this particle were projected with the same speed at an angle ‘ \(\theta \)’ to the horizontal, the maximum height attained by it equals 4\(R\) . The angle of projection \(\theta \), is then given by :

1 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
2 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
3 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{2g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
4 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
NEET - 2021
PHXI04:MOTION IN A PLANE

361966 A bullet is fired from a gun at the speed of \(280\,m{s^{ - 1}}\) in the direction \(30^{\circ}\) above the horizontal. The maximum height attained by the bullet is\((g = 9.8\,m{s^{ - 2}},\sin 30^\circ = 0.5)\) :

1 \(2000\;m\)
2 \(1000\;m\)
3 \(3000\;m\)
4 \(2800\;m\)
NEET - 2023
PHXI04:MOTION IN A PLANE

361967 The relation between the time of flight of a projectile \({T_f}\) and the time to reach the maximum height \({t_m}\) is

1 \({T_f} = 2{t_m}\)
2 \({T_f} = {t_m}\)
3 \({T_f} = \frac{{{t_m}}}{2}\)
4 \({T_f} = \sqrt 2 ({t_m})\)
PHXI04:MOTION IN A PLANE

361968 For a projectile, the ratio of maximum height reached to the square of flight time is \(g = 10\,m/{s^2}\)

1 \(5:4\)
2 \(5:2\)
3 \(5:1\)
4 \(10:1\)
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PHXI04:MOTION IN A PLANE

361965 A particle moving in a circle of radius \(R\) with a uniform speed takes a time \(T\) to complete one revolution. If this particle were projected with the same speed at an angle ‘ \(\theta \)’ to the horizontal, the maximum height attained by it equals 4\(R\) . The angle of projection \(\theta \), is then given by :

1 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
2 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
3 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{2g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
4 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
NEET - 2021
PHXI04:MOTION IN A PLANE

361966 A bullet is fired from a gun at the speed of \(280\,m{s^{ - 1}}\) in the direction \(30^{\circ}\) above the horizontal. The maximum height attained by the bullet is\((g = 9.8\,m{s^{ - 2}},\sin 30^\circ = 0.5)\) :

1 \(2000\;m\)
2 \(1000\;m\)
3 \(3000\;m\)
4 \(2800\;m\)
NEET - 2023
PHXI04:MOTION IN A PLANE

361967 The relation between the time of flight of a projectile \({T_f}\) and the time to reach the maximum height \({t_m}\) is

1 \({T_f} = 2{t_m}\)
2 \({T_f} = {t_m}\)
3 \({T_f} = \frac{{{t_m}}}{2}\)
4 \({T_f} = \sqrt 2 ({t_m})\)
PHXI04:MOTION IN A PLANE

361968 For a projectile, the ratio of maximum height reached to the square of flight time is \(g = 10\,m/{s^2}\)

1 \(5:4\)
2 \(5:2\)
3 \(5:1\)
4 \(10:1\)
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PHXI04:MOTION IN A PLANE

361965 A particle moving in a circle of radius \(R\) with a uniform speed takes a time \(T\) to complete one revolution. If this particle were projected with the same speed at an angle ‘ \(\theta \)’ to the horizontal, the maximum height attained by it equals 4\(R\) . The angle of projection \(\theta \), is then given by :

1 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
2 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
3 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{2g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
4 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
NEET - 2021
PHXI04:MOTION IN A PLANE

361966 A bullet is fired from a gun at the speed of \(280\,m{s^{ - 1}}\) in the direction \(30^{\circ}\) above the horizontal. The maximum height attained by the bullet is\((g = 9.8\,m{s^{ - 2}},\sin 30^\circ = 0.5)\) :

1 \(2000\;m\)
2 \(1000\;m\)
3 \(3000\;m\)
4 \(2800\;m\)
NEET - 2023
PHXI04:MOTION IN A PLANE

361967 The relation between the time of flight of a projectile \({T_f}\) and the time to reach the maximum height \({t_m}\) is

1 \({T_f} = 2{t_m}\)
2 \({T_f} = {t_m}\)
3 \({T_f} = \frac{{{t_m}}}{2}\)
4 \({T_f} = \sqrt 2 ({t_m})\)
PHXI04:MOTION IN A PLANE

361968 For a projectile, the ratio of maximum height reached to the square of flight time is \(g = 10\,m/{s^2}\)

1 \(5:4\)
2 \(5:2\)
3 \(5:1\)
4 \(10:1\)
NEET DIGITAL LIBRARY
PHXI04:MOTION IN A PLANE

361965 A particle moving in a circle of radius \(R\) with a uniform speed takes a time \(T\) to complete one revolution. If this particle were projected with the same speed at an angle ‘ \(\theta \)’ to the horizontal, the maximum height attained by it equals 4\(R\) . The angle of projection \(\theta \), is then given by :

1 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
2 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{{\pi ^2}R}}{{g{T^2}}}} \right)^{1/2}}\)
3 \(\theta = {\sin ^{ - 1}}{\left( {\frac{{2g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
4 \(\theta = {\cos ^{ - 1}}{\left( {\frac{{g{T^2}}}{{{\pi ^2}R}}} \right)^{1/2}}\)
NEET - 2021
PHXI04:MOTION IN A PLANE

361966 A bullet is fired from a gun at the speed of \(280\,m{s^{ - 1}}\) in the direction \(30^{\circ}\) above the horizontal. The maximum height attained by the bullet is\((g = 9.8\,m{s^{ - 2}},\sin 30^\circ = 0.5)\) :

1 \(2000\;m\)
2 \(1000\;m\)
3 \(3000\;m\)
4 \(2800\;m\)
NEET - 2023
PHXI04:MOTION IN A PLANE

361967 The relation between the time of flight of a projectile \({T_f}\) and the time to reach the maximum height \({t_m}\) is

1 \({T_f} = 2{t_m}\)
2 \({T_f} = {t_m}\)
3 \({T_f} = \frac{{{t_m}}}{2}\)
4 \({T_f} = \sqrt 2 ({t_m})\)
PHXI04:MOTION IN A PLANE

361968 For a projectile, the ratio of maximum height reached to the square of flight time is \(g = 10\,m/{s^2}\)

1 \(5:4\)
2 \(5:2\)
3 \(5:1\)
4 \(10:1\)
Join With Us for More Updates