361956 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Generally, the path of a projectile from the earth is parabolic but it is elliptical for projectile going to a very large height.
Reason :
The path of a projectile is independent of the gravitational force of the earth.

361957 The equation of trajectory of a projectile is \(y=10 x-\left(\dfrac{5}{9}\right) x^{2}\). If we assume \(g=10 m s^{-2}\), then the range of projectile (in metre) is

361958 A projectile is projected from ground with initial velocity \(\vec u = {u_o}\hat i + {v_o}\hat j.\) If acceleration due to gravity (\(g\)) is along the negative \(y\) - direction then find maximum displacement in \(x\) - direction.

361959 For a projectile motion, the angle between the velocity and acceleration is minimum and acute at

361960 The equation of motion of a projectile is \(y=2 x-\dfrac{3}{4} x^{2}\). The horizontal component of velocity is \(6\;m{s^{ - 1}}.\) What is the range (in metres) of the projectile? (Take \(g = 10\;m{s^{ - 2}}\))

361956 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Generally, the path of a projectile from the earth is parabolic but it is elliptical for projectile going to a very large height.
Reason :
The path of a projectile is independent of the gravitational force of the earth.

361957 The equation of trajectory of a projectile is \(y=10 x-\left(\dfrac{5}{9}\right) x^{2}\). If we assume \(g=10 m s^{-2}\), then the range of projectile (in metre) is

361958 A projectile is projected from ground with initial velocity \(\vec u = {u_o}\hat i + {v_o}\hat j.\) If acceleration due to gravity (\(g\)) is along the negative \(y\) - direction then find maximum displacement in \(x\) - direction.

361959 For a projectile motion, the angle between the velocity and acceleration is minimum and acute at

361960 The equation of motion of a projectile is \(y=2 x-\dfrac{3}{4} x^{2}\). The horizontal component of velocity is \(6\;m{s^{ - 1}}.\) What is the range (in metres) of the projectile? (Take \(g = 10\;m{s^{ - 2}}\))

361956 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Generally, the path of a projectile from the earth is parabolic but it is elliptical for projectile going to a very large height.
Reason :
The path of a projectile is independent of the gravitational force of the earth.

361957 The equation of trajectory of a projectile is \(y=10 x-\left(\dfrac{5}{9}\right) x^{2}\). If we assume \(g=10 m s^{-2}\), then the range of projectile (in metre) is

361958 A projectile is projected from ground with initial velocity \(\vec u = {u_o}\hat i + {v_o}\hat j.\) If acceleration due to gravity (\(g\)) is along the negative \(y\) - direction then find maximum displacement in \(x\) - direction.

361959 For a projectile motion, the angle between the velocity and acceleration is minimum and acute at

361960 The equation of motion of a projectile is \(y=2 x-\dfrac{3}{4} x^{2}\). The horizontal component of velocity is \(6\;m{s^{ - 1}}.\) What is the range (in metres) of the projectile? (Take \(g = 10\;m{s^{ - 2}}\))

361956 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Generally, the path of a projectile from the earth is parabolic but it is elliptical for projectile going to a very large height.
Reason :
The path of a projectile is independent of the gravitational force of the earth.

361957 The equation of trajectory of a projectile is \(y=10 x-\left(\dfrac{5}{9}\right) x^{2}\). If we assume \(g=10 m s^{-2}\), then the range of projectile (in metre) is

361958 A projectile is projected from ground with initial velocity \(\vec u = {u_o}\hat i + {v_o}\hat j.\) If acceleration due to gravity (\(g\)) is along the negative \(y\) - direction then find maximum displacement in \(x\) - direction.

361959 For a projectile motion, the angle between the velocity and acceleration is minimum and acute at

361960 The equation of motion of a projectile is \(y=2 x-\dfrac{3}{4} x^{2}\). The horizontal component of velocity is \(6\;m{s^{ - 1}}.\) What is the range (in metres) of the projectile? (Take \(g = 10\;m{s^{ - 2}}\))

361956 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Generally, the path of a projectile from the earth is parabolic but it is elliptical for projectile going to a very large height.
Reason :
The path of a projectile is independent of the gravitational force of the earth.

361957 The equation of trajectory of a projectile is \(y=10 x-\left(\dfrac{5}{9}\right) x^{2}\). If we assume \(g=10 m s^{-2}\), then the range of projectile (in metre) is

361958 A projectile is projected from ground with initial velocity \(\vec u = {u_o}\hat i + {v_o}\hat j.\) If acceleration due to gravity (\(g\)) is along the negative \(y\) - direction then find maximum displacement in \(x\) - direction.

361959 For a projectile motion, the angle between the velocity and acceleration is minimum and acute at

361960 The equation of motion of a projectile is \(y=2 x-\dfrac{3}{4} x^{2}\). The horizontal component of velocity is \(6\;m{s^{ - 1}}.\) What is the range (in metres) of the projectile? (Take \(g = 10\;m{s^{ - 2}}\))