NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI04:MOTION IN A PLANE
361942
A body is projected horizontally from the top of a tower with a velocity of 10 \(m\)/\(s\). If it hits the ground at an angle of \(45^\circ \) then the vertical component of velocity when it hits ground (in \(m\)/\(s\)) is :
1 \(5\sqrt 2 \)
2 \(10\sqrt 2 \)
3 \(10\)
4 \(5\)
Explanation:
The horizontal component of velocity \({v_x} = u = 10\,m/s\) Now, \(\tan \theta = \tan 45^\circ = \frac{{{v_y}}}{{{v_x}}} = \frac{{{v_y}}}{{10}} \Rightarrow {v_y} = 10\,m/s\)
