Surface Tension
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361220 In an isothermal process, 2 water drops of radius \(1 \mathrm{~mm}\) are combined to form a bigger drop. Find the energy change in this process, if \(T = 0.1\;N{\rm{/}}m\)

1 \(1\,\mu J\)
2 \(0.5\,\mu J\)
3 \(0.25\,\mu J\)
4 \(0.75\,\mu J\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361221 When liquid medicine of density \(\rho\) is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension \(T\) when the radius of the drop is \(R\). When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper. If the radius of the opening of the dropper is \(r\), the vertical force due to the surface tension on the drop of radius \(R\) (assuming \(r < < R\)) is

1 \(2 \pi r T\)
2 \(2 \pi R T\)
3 \(\dfrac{2 \pi r^{2} T}{R}\)
4 \(\dfrac{2 \pi R^{2} T}{r}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361222 There is a soap bubble in which there exists yet another soap bubble. It is given that the outside pressure is zero. If due to some reason the inner bubble bursts then the radius of bigger bubble will
supporting img

1 Remain \(2R\)
2 Become \(3R\)
3 Become \(\sqrt{5} R\)
4 Become \(4R\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361223 Find the difference of air pressure between the inside and outside of a soap bubble \(5\;mm\) in diameter, if the surface tension is \(1.6\,\,N{m^{ - 1}}\).

1 \(2560\,\,N{m^{ - 2}}\)
2 \(3720\,\,N{m^{ - 2}}\)
3 \(1208\,\,N{m^{ - 2}}\)
4 \(10132\,\,N{m^{ - 2}}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361220 In an isothermal process, 2 water drops of radius \(1 \mathrm{~mm}\) are combined to form a bigger drop. Find the energy change in this process, if \(T = 0.1\;N{\rm{/}}m\)

1 \(1\,\mu J\)
2 \(0.5\,\mu J\)
3 \(0.25\,\mu J\)
4 \(0.75\,\mu J\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361221 When liquid medicine of density \(\rho\) is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension \(T\) when the radius of the drop is \(R\). When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper. If the radius of the opening of the dropper is \(r\), the vertical force due to the surface tension on the drop of radius \(R\) (assuming \(r < < R\)) is

1 \(2 \pi r T\)
2 \(2 \pi R T\)
3 \(\dfrac{2 \pi r^{2} T}{R}\)
4 \(\dfrac{2 \pi R^{2} T}{r}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361222 There is a soap bubble in which there exists yet another soap bubble. It is given that the outside pressure is zero. If due to some reason the inner bubble bursts then the radius of bigger bubble will
supporting img

1 Remain \(2R\)
2 Become \(3R\)
3 Become \(\sqrt{5} R\)
4 Become \(4R\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361223 Find the difference of air pressure between the inside and outside of a soap bubble \(5\;mm\) in diameter, if the surface tension is \(1.6\,\,N{m^{ - 1}}\).

1 \(2560\,\,N{m^{ - 2}}\)
2 \(3720\,\,N{m^{ - 2}}\)
3 \(1208\,\,N{m^{ - 2}}\)
4 \(10132\,\,N{m^{ - 2}}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361220 In an isothermal process, 2 water drops of radius \(1 \mathrm{~mm}\) are combined to form a bigger drop. Find the energy change in this process, if \(T = 0.1\;N{\rm{/}}m\)

1 \(1\,\mu J\)
2 \(0.5\,\mu J\)
3 \(0.25\,\mu J\)
4 \(0.75\,\mu J\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361221 When liquid medicine of density \(\rho\) is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension \(T\) when the radius of the drop is \(R\). When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper. If the radius of the opening of the dropper is \(r\), the vertical force due to the surface tension on the drop of radius \(R\) (assuming \(r < < R\)) is

1 \(2 \pi r T\)
2 \(2 \pi R T\)
3 \(\dfrac{2 \pi r^{2} T}{R}\)
4 \(\dfrac{2 \pi R^{2} T}{r}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361222 There is a soap bubble in which there exists yet another soap bubble. It is given that the outside pressure is zero. If due to some reason the inner bubble bursts then the radius of bigger bubble will
supporting img

1 Remain \(2R\)
2 Become \(3R\)
3 Become \(\sqrt{5} R\)
4 Become \(4R\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361223 Find the difference of air pressure between the inside and outside of a soap bubble \(5\;mm\) in diameter, if the surface tension is \(1.6\,\,N{m^{ - 1}}\).

1 \(2560\,\,N{m^{ - 2}}\)
2 \(3720\,\,N{m^{ - 2}}\)
3 \(1208\,\,N{m^{ - 2}}\)
4 \(10132\,\,N{m^{ - 2}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361220 In an isothermal process, 2 water drops of radius \(1 \mathrm{~mm}\) are combined to form a bigger drop. Find the energy change in this process, if \(T = 0.1\;N{\rm{/}}m\)

1 \(1\,\mu J\)
2 \(0.5\,\mu J\)
3 \(0.25\,\mu J\)
4 \(0.75\,\mu J\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361221 When liquid medicine of density \(\rho\) is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension \(T\) when the radius of the drop is \(R\). When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper. If the radius of the opening of the dropper is \(r\), the vertical force due to the surface tension on the drop of radius \(R\) (assuming \(r < < R\)) is

1 \(2 \pi r T\)
2 \(2 \pi R T\)
3 \(\dfrac{2 \pi r^{2} T}{R}\)
4 \(\dfrac{2 \pi R^{2} T}{r}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361222 There is a soap bubble in which there exists yet another soap bubble. It is given that the outside pressure is zero. If due to some reason the inner bubble bursts then the radius of bigger bubble will
supporting img

1 Remain \(2R\)
2 Become \(3R\)
3 Become \(\sqrt{5} R\)
4 Become \(4R\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

361223 Find the difference of air pressure between the inside and outside of a soap bubble \(5\;mm\) in diameter, if the surface tension is \(1.6\,\,N{m^{ - 1}}\).

1 \(2560\,\,N{m^{ - 2}}\)
2 \(3720\,\,N{m^{ - 2}}\)
3 \(1208\,\,N{m^{ - 2}}\)
4 \(10132\,\,N{m^{ - 2}}\)