360363
The molar specific heat at constant pressure for a monoatomic gas is
1 \(\dfrac{3}{2} R\)
2 \(\dfrac{5}{2} R\)
3 \(\dfrac{7}{2} R\)
4 \(4 R\)
Explanation:
\({C_P} - {C_V} = R \Rightarrow {C_P} = R + {C_V} = R + \frac{f}{2}R\,\,\) \( = R + \frac{3}{2}R = \frac{5}{2}R\)
PHXI13:KINETIC THEORY
360364
If \(C_{P}\) and \(C_{V}\) denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then
1 \(C_{P}-C_{V}=28 R\)
2 \(C_{P}-C_{V}=R / 28\)
3 \(C_{P}-C_{V}=R / 14\)
4 \(C_{P}-C_{V}=R\)
Explanation:
Molar specific heat \(C^{\prime}=\dfrac{\Delta Q}{n \Delta T}\) Specific heat \(C=\dfrac{\Delta Q}{m \Delta T}\) \(\begin{aligned}& \dfrac{C^{\prime}}{C}=\dfrac{m}{n}=M(\text { Molecular weight }) \\& C=\dfrac{C^{\prime}}{M} \\& C_{P}^{\prime}-C_{V}^{1}=R \\& M C_{P}-M C_{V}=R \Rightarrow C_{P}-C_{V}=\dfrac{R}{M}\end{aligned}\) For nitrogen \(M=28\) \(C_{P}-C_{V}=\dfrac{R}{28}\)
PHXI13:KINETIC THEORY
360365
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure \(\left(C_{p}\right)\) and at constant volume \(\left(C_{V}\right)\) is:
1 6
2 \(\dfrac{7}{2}\)
3 \(\dfrac{5}{2}\)
4 \(\dfrac{7}{5}\)
Explanation:
The ratio of specific heats at constant pressure \(\left(C_{P}\right)\) and constant volume \(\left(C_{V}\right)\) \(\dfrac{C_{P}}{C_{V}}=\gamma=\left(1+\dfrac{2}{F}\right)\) where \(F\) is degree of freedom \(\dfrac{C_{P}}{C_{V}}=\left(1+\dfrac{2}{5}\right)=\dfrac{7}{5}\)
JEE - 2017
PHXI13:KINETIC THEORY
360366
The temperature of 5 moles of a gas which was held at constant volume was changed from \(100^\circ \,C\) to \(120^\circ \,C\). The change in internal energy was found to be \(80\,\,Joules\). The total heat capacity of the gas at constant volume will be equal to
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PHXI13:KINETIC THEORY
360363
The molar specific heat at constant pressure for a monoatomic gas is
1 \(\dfrac{3}{2} R\)
2 \(\dfrac{5}{2} R\)
3 \(\dfrac{7}{2} R\)
4 \(4 R\)
Explanation:
\({C_P} - {C_V} = R \Rightarrow {C_P} = R + {C_V} = R + \frac{f}{2}R\,\,\) \( = R + \frac{3}{2}R = \frac{5}{2}R\)
PHXI13:KINETIC THEORY
360364
If \(C_{P}\) and \(C_{V}\) denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then
1 \(C_{P}-C_{V}=28 R\)
2 \(C_{P}-C_{V}=R / 28\)
3 \(C_{P}-C_{V}=R / 14\)
4 \(C_{P}-C_{V}=R\)
Explanation:
Molar specific heat \(C^{\prime}=\dfrac{\Delta Q}{n \Delta T}\) Specific heat \(C=\dfrac{\Delta Q}{m \Delta T}\) \(\begin{aligned}& \dfrac{C^{\prime}}{C}=\dfrac{m}{n}=M(\text { Molecular weight }) \\& C=\dfrac{C^{\prime}}{M} \\& C_{P}^{\prime}-C_{V}^{1}=R \\& M C_{P}-M C_{V}=R \Rightarrow C_{P}-C_{V}=\dfrac{R}{M}\end{aligned}\) For nitrogen \(M=28\) \(C_{P}-C_{V}=\dfrac{R}{28}\)
PHXI13:KINETIC THEORY
360365
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure \(\left(C_{p}\right)\) and at constant volume \(\left(C_{V}\right)\) is:
1 6
2 \(\dfrac{7}{2}\)
3 \(\dfrac{5}{2}\)
4 \(\dfrac{7}{5}\)
Explanation:
The ratio of specific heats at constant pressure \(\left(C_{P}\right)\) and constant volume \(\left(C_{V}\right)\) \(\dfrac{C_{P}}{C_{V}}=\gamma=\left(1+\dfrac{2}{F}\right)\) where \(F\) is degree of freedom \(\dfrac{C_{P}}{C_{V}}=\left(1+\dfrac{2}{5}\right)=\dfrac{7}{5}\)
JEE - 2017
PHXI13:KINETIC THEORY
360366
The temperature of 5 moles of a gas which was held at constant volume was changed from \(100^\circ \,C\) to \(120^\circ \,C\). The change in internal energy was found to be \(80\,\,Joules\). The total heat capacity of the gas at constant volume will be equal to
360363
The molar specific heat at constant pressure for a monoatomic gas is
1 \(\dfrac{3}{2} R\)
2 \(\dfrac{5}{2} R\)
3 \(\dfrac{7}{2} R\)
4 \(4 R\)
Explanation:
\({C_P} - {C_V} = R \Rightarrow {C_P} = R + {C_V} = R + \frac{f}{2}R\,\,\) \( = R + \frac{3}{2}R = \frac{5}{2}R\)
PHXI13:KINETIC THEORY
360364
If \(C_{P}\) and \(C_{V}\) denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then
1 \(C_{P}-C_{V}=28 R\)
2 \(C_{P}-C_{V}=R / 28\)
3 \(C_{P}-C_{V}=R / 14\)
4 \(C_{P}-C_{V}=R\)
Explanation:
Molar specific heat \(C^{\prime}=\dfrac{\Delta Q}{n \Delta T}\) Specific heat \(C=\dfrac{\Delta Q}{m \Delta T}\) \(\begin{aligned}& \dfrac{C^{\prime}}{C}=\dfrac{m}{n}=M(\text { Molecular weight }) \\& C=\dfrac{C^{\prime}}{M} \\& C_{P}^{\prime}-C_{V}^{1}=R \\& M C_{P}-M C_{V}=R \Rightarrow C_{P}-C_{V}=\dfrac{R}{M}\end{aligned}\) For nitrogen \(M=28\) \(C_{P}-C_{V}=\dfrac{R}{28}\)
PHXI13:KINETIC THEORY
360365
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure \(\left(C_{p}\right)\) and at constant volume \(\left(C_{V}\right)\) is:
1 6
2 \(\dfrac{7}{2}\)
3 \(\dfrac{5}{2}\)
4 \(\dfrac{7}{5}\)
Explanation:
The ratio of specific heats at constant pressure \(\left(C_{P}\right)\) and constant volume \(\left(C_{V}\right)\) \(\dfrac{C_{P}}{C_{V}}=\gamma=\left(1+\dfrac{2}{F}\right)\) where \(F\) is degree of freedom \(\dfrac{C_{P}}{C_{V}}=\left(1+\dfrac{2}{5}\right)=\dfrac{7}{5}\)
JEE - 2017
PHXI13:KINETIC THEORY
360366
The temperature of 5 moles of a gas which was held at constant volume was changed from \(100^\circ \,C\) to \(120^\circ \,C\). The change in internal energy was found to be \(80\,\,Joules\). The total heat capacity of the gas at constant volume will be equal to
360363
The molar specific heat at constant pressure for a monoatomic gas is
1 \(\dfrac{3}{2} R\)
2 \(\dfrac{5}{2} R\)
3 \(\dfrac{7}{2} R\)
4 \(4 R\)
Explanation:
\({C_P} - {C_V} = R \Rightarrow {C_P} = R + {C_V} = R + \frac{f}{2}R\,\,\) \( = R + \frac{3}{2}R = \frac{5}{2}R\)
PHXI13:KINETIC THEORY
360364
If \(C_{P}\) and \(C_{V}\) denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then
1 \(C_{P}-C_{V}=28 R\)
2 \(C_{P}-C_{V}=R / 28\)
3 \(C_{P}-C_{V}=R / 14\)
4 \(C_{P}-C_{V}=R\)
Explanation:
Molar specific heat \(C^{\prime}=\dfrac{\Delta Q}{n \Delta T}\) Specific heat \(C=\dfrac{\Delta Q}{m \Delta T}\) \(\begin{aligned}& \dfrac{C^{\prime}}{C}=\dfrac{m}{n}=M(\text { Molecular weight }) \\& C=\dfrac{C^{\prime}}{M} \\& C_{P}^{\prime}-C_{V}^{1}=R \\& M C_{P}-M C_{V}=R \Rightarrow C_{P}-C_{V}=\dfrac{R}{M}\end{aligned}\) For nitrogen \(M=28\) \(C_{P}-C_{V}=\dfrac{R}{28}\)
PHXI13:KINETIC THEORY
360365
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure \(\left(C_{p}\right)\) and at constant volume \(\left(C_{V}\right)\) is:
1 6
2 \(\dfrac{7}{2}\)
3 \(\dfrac{5}{2}\)
4 \(\dfrac{7}{5}\)
Explanation:
The ratio of specific heats at constant pressure \(\left(C_{P}\right)\) and constant volume \(\left(C_{V}\right)\) \(\dfrac{C_{P}}{C_{V}}=\gamma=\left(1+\dfrac{2}{F}\right)\) where \(F\) is degree of freedom \(\dfrac{C_{P}}{C_{V}}=\left(1+\dfrac{2}{5}\right)=\dfrac{7}{5}\)
JEE - 2017
PHXI13:KINETIC THEORY
360366
The temperature of 5 moles of a gas which was held at constant volume was changed from \(100^\circ \,C\) to \(120^\circ \,C\). The change in internal energy was found to be \(80\,\,Joules\). The total heat capacity of the gas at constant volume will be equal to